Q1. A small mass is situated at a point on a line joining two large
... An unfortunate printing error, for which AQA apologises, meant that an erratum notice had to be issued for this question. This corrected the charge on Q from +6μC to –6μC. In the main, the candidates showed a good understanding of electric potential, causing the question to have a facility of 75%. W ...
... An unfortunate printing error, for which AQA apologises, meant that an erratum notice had to be issued for this question. This corrected the charge on Q from +6μC to –6μC. In the main, the candidates showed a good understanding of electric potential, causing the question to have a facility of 75%. W ...
19. Centripetal Force
... with a string, the tension in the string equals the ____________ force experienced by the object. An object's ____________, mass, and ____________ of rotation all contribute to the magnitude of the centripetal force. Newton’s ____________ law holds true for rotational motion in that the centripetal ...
... with a string, the tension in the string equals the ____________ force experienced by the object. An object's ____________, mass, and ____________ of rotation all contribute to the magnitude of the centripetal force. Newton’s ____________ law holds true for rotational motion in that the centripetal ...
Solution - NUS Physics Department
... However, for the case of (µ1 >µ2 ), the light rod provides a tension acting on the the two blocks. This is in contrast to the string, in which there are no forces acting on the two blocks by the string. Hence, we would expects the answers to change for both part (a) and (b). For part (a), without th ...
... However, for the case of (µ1 >µ2 ), the light rod provides a tension acting on the the two blocks. This is in contrast to the string, in which there are no forces acting on the two blocks by the string. Hence, we would expects the answers to change for both part (a) and (b). For part (a), without th ...
Forces
... Suppose a large rock is dropped straight down from a high cliff while the other is pushed out from the top of the cliff. Which one will land first and WHY? A. The rock that is pushed out from the cliff will hit first because it had an extra force to make it fall faster. B. The rock that’s dropped st ...
... Suppose a large rock is dropped straight down from a high cliff while the other is pushed out from the top of the cliff. Which one will land first and WHY? A. The rock that is pushed out from the cliff will hit first because it had an extra force to make it fall faster. B. The rock that’s dropped st ...
Note 13 Newton`s Third Law
... We measured that, during the collision, the speed of the right cart went from 0 m/s to +31.8 cm/s. The time of the collision itself is about 3/30 second. The average acceleration of the right cart is ...
... We measured that, during the collision, the speed of the right cart went from 0 m/s to +31.8 cm/s. The time of the collision itself is about 3/30 second. The average acceleration of the right cart is ...
People`s Physics Book Ch 5-1 The Big Idea Acceleration is caused
... right now? Measuring acceleration is comparatively easy — you can feel accelerations. Here’s a clever way to determine your acceleration. As you accelerate your car on a flat stretch, you notice that the fuzzy dice hanging from your rearview mirror are no longer hanging straight up and down. In fact ...
... right now? Measuring acceleration is comparatively easy — you can feel accelerations. Here’s a clever way to determine your acceleration. As you accelerate your car on a flat stretch, you notice that the fuzzy dice hanging from your rearview mirror are no longer hanging straight up and down. In fact ...
Dynamics Multiple Choice Problems
... A. less than zero B. between zero and Mg C. equal to Mg D. greater than Mg E. zero 33. An elevator of mass M is pulled upwards by a cable; the elevator has a positive, but decreasing, velocity. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and ...
... A. less than zero B. between zero and Mg C. equal to Mg D. greater than Mg E. zero 33. An elevator of mass M is pulled upwards by a cable; the elevator has a positive, but decreasing, velocity. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and ...
ch5
... work: W = 3000 J = 3000 Nm distance: d = 500 m force: F = ? N Begin with the work equation, W = Fd, then divide work by distance to find force. Then, substitute the known values for work and distance into the work equation and calculate force. ...
... work: W = 3000 J = 3000 Nm distance: d = 500 m force: F = ? N Begin with the work equation, W = Fd, then divide work by distance to find force. Then, substitute the known values for work and distance into the work equation and calculate force. ...
Dynamics Multiple Choice Homework
... A. less than zero B. between zero and Mg C. equal to Mg D. greater than Mg E. zero 33. An elevator of mass M is pulled upwards by a cable; the elevator has a positive, but decreasing, velocity. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and ...
... A. less than zero B. between zero and Mg C. equal to Mg D. greater than Mg E. zero 33. An elevator of mass M is pulled upwards by a cable; the elevator has a positive, but decreasing, velocity. What is the tension in the cable (neglecting the mass of the cable)? A. less than zero B. between zero and ...
Tension
... • The magnitude of the force exerted by a spring is proportional to the amount it is stretched. • F = kx – F: force exerted by the spring (N) – k: force constant of the spring (N/m or N/cm) – x: displacement from equilibrium (unstretched and uncompressed) position (m or cm) ...
... • The magnitude of the force exerted by a spring is proportional to the amount it is stretched. • F = kx – F: force exerted by the spring (N) – k: force constant of the spring (N/m or N/cm) – x: displacement from equilibrium (unstretched and uncompressed) position (m or cm) ...
PHY–309 K. Solutions for Problem set # 10. Non
... with the right support. Thus, there is no normal force on the right and of the bridge. Instead, the right end is pulled up by the two chains of net tension T ; we do not know the magnitude of this tension force but we do know its direction: along the chains themselves, θ = 40◦ above the horizontal. ...
... with the right support. Thus, there is no normal force on the right and of the bridge. Instead, the right end is pulled up by the two chains of net tension T ; we do not know the magnitude of this tension force but we do know its direction: along the chains themselves, θ = 40◦ above the horizontal. ...
Force and Motion
... If you apply the same force to several different objects, the one with the most mass will have the smallest acceleration and the one with the least mass will have the greatest acceleration. If you apply the same force to several different objects, the one with the most mass will have the smallest ac ...
... If you apply the same force to several different objects, the one with the most mass will have the smallest acceleration and the one with the least mass will have the greatest acceleration. If you apply the same force to several different objects, the one with the most mass will have the smallest ac ...
Class Notes - St. Bonaventure University
... line/arrow on top. A vector may also be represented by an ordered list of numbers, which are called the components: [t,x,y,z]. Written this way, mathematically the vector would t x be called a row matrix. A column matrix is a vertical list of components: . ...
... line/arrow on top. A vector may also be represented by an ordered list of numbers, which are called the components: [t,x,y,z]. Written this way, mathematically the vector would t x be called a row matrix. A column matrix is a vertical list of components: . ...
Gravity Pre-Lab 1. Why do you need an inclined plane to measure
... Newton’s laws are all a natural consequence of the conservation of momentum. His first law states that an object’s velocity will not change unless a force acts upon it. This can be approximately verified by simply pushing a cart on the track. If the tracks were infinitely long and carts were truly f ...
... Newton’s laws are all a natural consequence of the conservation of momentum. His first law states that an object’s velocity will not change unless a force acts upon it. This can be approximately verified by simply pushing a cart on the track. If the tracks were infinitely long and carts were truly f ...
kinematics of rotation of rigid bodies
... In the study of linear motion, we found that the simplest form of accelerated motion to analyze is motion under constant linear acceleration. Like wise for rotational motion about fixed axis, the simplest accelerated motion to analyze is motion under constant angular acceleration. Therefore we next ...
... In the study of linear motion, we found that the simplest form of accelerated motion to analyze is motion under constant linear acceleration. Like wise for rotational motion about fixed axis, the simplest accelerated motion to analyze is motion under constant angular acceleration. Therefore we next ...
Modified Newtonian dynamics
In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.