Name
... If the saturated solution is cooled from 80oC to 50oC, how many grams of precipitate are formed? ...
... If the saturated solution is cooled from 80oC to 50oC, how many grams of precipitate are formed? ...
Chapter 2 power point File
... Scales are used by scientists to measure samples and to find out specific information A meter scale measures things that are large (length of a car), a centimeter measures things that are small (the length of a book), and a millimeter measures things that are microscopic or really small (like the th ...
... Scales are used by scientists to measure samples and to find out specific information A meter scale measures things that are large (length of a car), a centimeter measures things that are small (the length of a book), and a millimeter measures things that are microscopic or really small (like the th ...
Section 4.6: Double Displacement Reactions
... 7. Silver ions are the only metal ions that can be precipitated from a solution containing the C2H3O2− ions. Therefore, a solution such as NaC2H3O2(aq) can be used to precipitate silver ions from a mixture of dissolved metal ions. 8. Answers may vary. Sample answer: Most of the limescale that forms ...
... 7. Silver ions are the only metal ions that can be precipitated from a solution containing the C2H3O2− ions. Therefore, a solution such as NaC2H3O2(aq) can be used to precipitate silver ions from a mixture of dissolved metal ions. 8. Answers may vary. Sample answer: Most of the limescale that forms ...
Chapter 4: Solution Chemistry and the Hydrosphere
... a. In a 0.125M Na2SO4(aq) solution [Na+]=____________ and [SO42-]=____________. b. In a 0.500M Fe(NO3)3(aq) solution [Fe3+]=____________ and [NO3–]=___________. c. In a 1.250M Al2(SO4)3(aq) solution [Al+3]=____________ and [SO42-]=___________. ...
... a. In a 0.125M Na2SO4(aq) solution [Na+]=____________ and [SO42-]=____________. b. In a 0.500M Fe(NO3)3(aq) solution [Fe3+]=____________ and [NO3–]=___________. c. In a 1.250M Al2(SO4)3(aq) solution [Al+3]=____________ and [SO42-]=___________. ...
final review cp2 1213 by chapter
... 1.Which of the following explains why methane (CH4) has a boiling point of – 161 °C and octane (C8H18) has a boiling point of 125.6 °C. A.the London dispersion forces are stronger in methane B.the hydrogen bonds are stronger in octane C.octane can hydrogen bond and methane cannot D.the hydrogen bond ...
... 1.Which of the following explains why methane (CH4) has a boiling point of – 161 °C and octane (C8H18) has a boiling point of 125.6 °C. A.the London dispersion forces are stronger in methane B.the hydrogen bonds are stronger in octane C.octane can hydrogen bond and methane cannot D.the hydrogen bond ...
equilibrium questions - Southington Public Schools
... (i) Which of the two acids is stronger, HOCl or HOBr? Justify your answer in terms of Ka. (ii) Draw a complete Lewis electron-dot diagram for the acid that you identified in part (a)(i). (iii) Hypoiodous acid has the formula HOI. Predict whether HOI is a stronger acid or a weaker acid than the acid ...
... (i) Which of the two acids is stronger, HOCl or HOBr? Justify your answer in terms of Ka. (ii) Draw a complete Lewis electron-dot diagram for the acid that you identified in part (a)(i). (iii) Hypoiodous acid has the formula HOI. Predict whether HOI is a stronger acid or a weaker acid than the acid ...
CHEM 101 Final (Term 141)
... 17. Nickel forms a gaseous compound of the formula Ni(CO)x. What is the value of x given the fact that under the same conditions of temperature and pressure, methan (CH4) effuses 3.3 faster than the compound? A) B) C) D) E) ...
... 17. Nickel forms a gaseous compound of the formula Ni(CO)x. What is the value of x given the fact that under the same conditions of temperature and pressure, methan (CH4) effuses 3.3 faster than the compound? A) B) C) D) E) ...
14.1 Dynamic Equilibrium, Keq , and the Mass Action Expression
... In general, simplifying assumptions works when the initial concentration of the reactant is high but not when it is low. To summarize, we assume that x (Δ [React]) can be neglected if Keq is small relative to [React]initial. The benchmark in justifying the assumption isYour job is to determine what ...
... In general, simplifying assumptions works when the initial concentration of the reactant is high but not when it is low. To summarize, we assume that x (Δ [React]) can be neglected if Keq is small relative to [React]initial. The benchmark in justifying the assumption isYour job is to determine what ...
Chemistry Log Books - Social Circle City Schools
... 3. If one liquid is soluble in another liquid, such as food coloring in water, the two liquids are considered ________________. 4. If one liquid is insoluble in another, such as oil in water, the two liquids are _____________. 5. Discuss the two processes that occur during solution formation. ...
... 3. If one liquid is soluble in another liquid, such as food coloring in water, the two liquids are considered ________________. 4. If one liquid is insoluble in another, such as oil in water, the two liquids are _____________. 5. Discuss the two processes that occur during solution formation. ...
Acids ,Bases and Salts
... This dissociation/ionization makes aqueous ammonia to: (i)turn litmus paper/solution blue. (ii)have pH 8/9/10/11 (iii)be a good electrical conductor (iv)react with acids to form ammonium salt and water only. NH4OH(aq) + HCl(aq) -> NH4Cl(aq) + H2O(l) (d)Ammonia gas dissolves in methylbenzene/benzene ...
... This dissociation/ionization makes aqueous ammonia to: (i)turn litmus paper/solution blue. (ii)have pH 8/9/10/11 (iii)be a good electrical conductor (iv)react with acids to form ammonium salt and water only. NH4OH(aq) + HCl(aq) -> NH4Cl(aq) + H2O(l) (d)Ammonia gas dissolves in methylbenzene/benzene ...
Document
... nonelectrolytes are written in molecule form. • Solids, liquids, and gases are not dissolved, hence molecule form 2 K+(aq) + 2 OH−(aq) + Mg2+(aq) + 2 NO3−(aq) K+(aq) + 2 NO3−(aq) + Mg(OH)2(s) ...
... nonelectrolytes are written in molecule form. • Solids, liquids, and gases are not dissolved, hence molecule form 2 K+(aq) + 2 OH−(aq) + Mg2+(aq) + 2 NO3−(aq) K+(aq) + 2 NO3−(aq) + Mg(OH)2(s) ...
Separation and Purification Methods
... The basis of extractive techniques is the “like dissolves like” rule. Water typically dissolves inorganic salts (such as lithium chloride) and other ionized species, while solvents (ethyl acetate, methylene chloride, diethyl ether, etc.) dissolve neutral organic molecules. However, some compounds (e ...
... The basis of extractive techniques is the “like dissolves like” rule. Water typically dissolves inorganic salts (such as lithium chloride) and other ionized species, while solvents (ethyl acetate, methylene chloride, diethyl ether, etc.) dissolve neutral organic molecules. However, some compounds (e ...
The Copper Cycle
... and excess hydronium ions (H3O+) remain from the nitric acid used. 2nd Beaker: Adding NaOH(aq) to the blue solution results in the OH– ions neutralizing the H3O+ ions to form water: H3O+(aq) + OH–(aq) → 2 H2O(l). The Na+ ions and resulting water molecules are not shown. 3rd and 4th Beakers: Once all ...
... and excess hydronium ions (H3O+) remain from the nitric acid used. 2nd Beaker: Adding NaOH(aq) to the blue solution results in the OH– ions neutralizing the H3O+ ions to form water: H3O+(aq) + OH–(aq) → 2 H2O(l). The Na+ ions and resulting water molecules are not shown. 3rd and 4th Beakers: Once all ...
Document
... In order for a substance to move between the states of matter; for example, to turn from a solid into a liquid, which is called fusion, or from a liquid to a gas (vaporization), energy must be gained or lost. (As we move from solid to gas it is gained and from gas to a solid it is lost. Why? Molar H ...
... In order for a substance to move between the states of matter; for example, to turn from a solid into a liquid, which is called fusion, or from a liquid to a gas (vaporization), energy must be gained or lost. (As we move from solid to gas it is gained and from gas to a solid it is lost. Why? Molar H ...
CHAPTER 4: AQUEOUS REACTIONS AND SOLUTION
... When ionic compounds dissolve in water the ions separate and are surrounded by water molecules. Once the ions have separated, they can move and conduct electricity. In the crystalline form they cannot move or conduct electricity. The solvation process helps stabilize the ions in solution and prevent ...
... When ionic compounds dissolve in water the ions separate and are surrounded by water molecules. Once the ions have separated, they can move and conduct electricity. In the crystalline form they cannot move or conduct electricity. The solvation process helps stabilize the ions in solution and prevent ...
Ch 11 Review - mvhs
... (A) Neon has a lower boiling point than krypton. (B) Solid silver chloride is not a good conductor of electricity though solid silver metal is an excellent conductor of electricity. (C) At room temperature silicon dioxide, SiO2 , is a solid. If you move up in group IV to carbon and look at the analo ...
... (A) Neon has a lower boiling point than krypton. (B) Solid silver chloride is not a good conductor of electricity though solid silver metal is an excellent conductor of electricity. (C) At room temperature silicon dioxide, SiO2 , is a solid. If you move up in group IV to carbon and look at the analo ...
Synthesis of novel dendrimers having aspartate grafts and their
... Naproxen is one of the acidic non-steroidal anti-inflammatory drugs (NSAIDs) with a functional group –COOH (pKa ¼ 4.2), so its solubility in water is pH-dependent [11]. Because the acidity of naproxen, the inherent solubility was 1.18 mg/ml, pH ¼ 6; 2.24 mg/ ml, pH ¼ 7; 24.45 mg/ml, pH ¼ 8. We measur ...
... Naproxen is one of the acidic non-steroidal anti-inflammatory drugs (NSAIDs) with a functional group –COOH (pKa ¼ 4.2), so its solubility in water is pH-dependent [11]. Because the acidity of naproxen, the inherent solubility was 1.18 mg/ml, pH ¼ 6; 2.24 mg/ ml, pH ¼ 7; 24.45 mg/ml, pH ¼ 8. We measur ...
Types of Reactions
... The final product of the reaction contains solid PbI2, aqueous K+2, and aqueous NO3–1 ions. Sometimes we want to highlight the reaction between ions. The molecular equation lists all species in their molecular forms: Pb(NO3)2 (aq) + 2 KI (aq) PbI2 (s) + 2 KNO3 (aq) The complete ionic equation list ...
... The final product of the reaction contains solid PbI2, aqueous K+2, and aqueous NO3–1 ions. Sometimes we want to highlight the reaction between ions. The molecular equation lists all species in their molecular forms: Pb(NO3)2 (aq) + 2 KI (aq) PbI2 (s) + 2 KNO3 (aq) The complete ionic equation list ...
Solutes
... Significant Figure Rule – The number of places to the right of the decimal for a log must be equal to the number of significant figures in the original number. ...
... Significant Figure Rule – The number of places to the right of the decimal for a log must be equal to the number of significant figures in the original number. ...
CH 4 Notes
... Take a known volume of the HCl solution (e.g., 20.0 mL) and measure the number of milliliters of NaOH solution required to react completely with the HCl solution. The point at which stoichiometrically equivalent quantities of NaOH and HCl are brought together is known as the equivalence point of ...
... Take a known volume of the HCl solution (e.g., 20.0 mL) and measure the number of milliliters of NaOH solution required to react completely with the HCl solution. The point at which stoichiometrically equivalent quantities of NaOH and HCl are brought together is known as the equivalence point of ...
Solutes
... Significant Figure Rule – The number of places to the right of the decimal for a log must be equal to the number of significant figures in the original number. ...
... Significant Figure Rule – The number of places to the right of the decimal for a log must be equal to the number of significant figures in the original number. ...
Aqueous chemistry is a very important component to laboratory
... In an acid-base titration, an indicator is used to show the change from an acidic situation (all acid), and as the base is slowly added and neutralization occurs, the color shift will be towards the basic side. When the moles of acid = moles of base neutralization is said to occur. We note this by t ...
... In an acid-base titration, an indicator is used to show the change from an acidic situation (all acid), and as the base is slowly added and neutralization occurs, the color shift will be towards the basic side. When the moles of acid = moles of base neutralization is said to occur. We note this by t ...
AP Chemistry: Aqueous Reactions and Solution Stoichiometry
... Take a known volume of the HCl solution (e.g., 20.0 mL) and measure the number of milliliters of NaOH solution required to react completely with the HCl solution. The point at which stoichiometrically equivalent quantities of NaOH and HCl are brought together is known as the equivalence point of the ...
... Take a known volume of the HCl solution (e.g., 20.0 mL) and measure the number of milliliters of NaOH solution required to react completely with the HCl solution. The point at which stoichiometrically equivalent quantities of NaOH and HCl are brought together is known as the equivalence point of the ...
Writing Net Ionic Equations
... molecular species is formed), then the reaction is reversible (no ions have been removed). Reversible reactions are at equilibrium and have both forward and reverse reactions taking place. In a reversible reaction, evaporation of the water solvent will result in solid residues of both reactants and ...
... molecular species is formed), then the reaction is reversible (no ions have been removed). Reversible reactions are at equilibrium and have both forward and reverse reactions taking place. In a reversible reaction, evaporation of the water solvent will result in solid residues of both reactants and ...
Complete Set
... • The ocean contains a variety of forms of CO32– and CO2 with a variety of acid-base and solubility equilibria determining their concentrations. There is concern that increasing levels of CO2 will lead to increased dissolution of CaCO3 and critically affect the survival of life forms that rely on a ...
... • The ocean contains a variety of forms of CO32– and CO2 with a variety of acid-base and solubility equilibria determining their concentrations. There is concern that increasing levels of CO2 will lead to increased dissolution of CaCO3 and critically affect the survival of life forms that rely on a ...