DNA - hdueck
... Total number of genes is unknown, it estimated to be 30 000 to 120 000 Genes comprise only 3% of the chromosome—the rest is called junk DNA—its code is meaningless “junk” ...
... Total number of genes is unknown, it estimated to be 30 000 to 120 000 Genes comprise only 3% of the chromosome—the rest is called junk DNA—its code is meaningless “junk” ...
Bio 93 Quiz 4: Master Copy
... B) The 5' to 3' direction of one strand runs counter to the 5' to 3' direction of the other strand. C) Base pairings create unequal spacing between the two DNA strands. D) One strand is positively charged and the other is negatively charged. E) One strand contains only purines and the other contains ...
... B) The 5' to 3' direction of one strand runs counter to the 5' to 3' direction of the other strand. C) Base pairings create unequal spacing between the two DNA strands. D) One strand is positively charged and the other is negatively charged. E) One strand contains only purines and the other contains ...
DNA Structure and Replication
... Melting and re-association of DNA ! H-bonds are weak bonds, broken by high temperature ! DNA “melts”--strands separate--at 85-95oC ! When cool, the strands can re-associate, if they have complementary base sequences ! Use this technique to recognize specific sequences ! make radioactive DNA of part ...
... Melting and re-association of DNA ! H-bonds are weak bonds, broken by high temperature ! DNA “melts”--strands separate--at 85-95oC ! When cool, the strands can re-associate, if they have complementary base sequences ! Use this technique to recognize specific sequences ! make radioactive DNA of part ...
DNA Replication, Transcription and Translation assessment
... Topic 2.7: DNA Replication and Protein Synthesis Assessment Statements Topic 2.7 2.7.1 Explain the process of DNA replication in eukaryotes, including the role of enzymes (helicase, DNA polymerase, RNA primase and DNA ligase), Okazaki fragments and deoxynucleoside triphosphates. 2.7.2 Explain the si ...
... Topic 2.7: DNA Replication and Protein Synthesis Assessment Statements Topic 2.7 2.7.1 Explain the process of DNA replication in eukaryotes, including the role of enzymes (helicase, DNA polymerase, RNA primase and DNA ligase), Okazaki fragments and deoxynucleoside triphosphates. 2.7.2 Explain the si ...
Biology Test Topics Chapters 11-12 Slideshows
... Polymer (macromolecule) and monomer (name and three parts and also list the four types of bases that can be present in this monomer) Be able to label a diagram of DNA Bonding type between sugar and phosphate molecules Bonding type between bases Shape of DNA Major contributions of the fol ...
... Polymer (macromolecule) and monomer (name and three parts and also list the four types of bases that can be present in this monomer) Be able to label a diagram of DNA Bonding type between sugar and phosphate molecules Bonding type between bases Shape of DNA Major contributions of the fol ...
Unit 2 Review: Molecular Genetics
... -structure deduced by Watson and Crick, using X-ray diffraction, base proportions -anti-parallel strands, base pairing (purine to pyrimidine), double helix with sugarphosphate backbone, 5' (phosphate) to 3' (sugar) direction DNA Replication -needed for cell division, growth, tissue repair -strands s ...
... -structure deduced by Watson and Crick, using X-ray diffraction, base proportions -anti-parallel strands, base pairing (purine to pyrimidine), double helix with sugarphosphate backbone, 5' (phosphate) to 3' (sugar) direction DNA Replication -needed for cell division, growth, tissue repair -strands s ...
dna structure - Siegel Science
... concern with cell division is the maintenance of the cell’s GENETIC information. Before a CELL can divide, genetic information in chromosomes must be replicated (i.e. DNA replication) ...
... concern with cell division is the maintenance of the cell’s GENETIC information. Before a CELL can divide, genetic information in chromosomes must be replicated (i.e. DNA replication) ...
Chapter 9
... • Two nucleotide strands held together by hydrogen bonds • Hydrogen bonds between two strands are easily broken ...
... • Two nucleotide strands held together by hydrogen bonds • Hydrogen bonds between two strands are easily broken ...
Discovering DNA: Structure and Replication
... Hershey and Chase • bacteriophages to see if information is carried on proteins or DNA ...
... Hershey and Chase • bacteriophages to see if information is carried on proteins or DNA ...
A1988L264200002
... methylase that would postreplicationally form 5’-methylcytosine at symmetrical DNA sites. It was further proposed that thisenzyme would prefer hemimethylated sites. With such an enzyme, methylation patterns would be somatically heritable and could be important for X-chromosome inactivation and cellu ...
... methylase that would postreplicationally form 5’-methylcytosine at symmetrical DNA sites. It was further proposed that thisenzyme would prefer hemimethylated sites. With such an enzyme, methylation patterns would be somatically heritable and could be important for X-chromosome inactivation and cellu ...
Key concepts_chromatin
... repeating structure. The repeating elements of eukaryotic chromatin are celled nucleosomes. Nucleosomes consist of core particle and linker DNA. In each core particle, about 147 bp of DNA is wrapped in 1.67 left-handed turns about an octamer of histones, two each of four types: H2A, H2B, H3 and H4. ...
... repeating structure. The repeating elements of eukaryotic chromatin are celled nucleosomes. Nucleosomes consist of core particle and linker DNA. In each core particle, about 147 bp of DNA is wrapped in 1.67 left-handed turns about an octamer of histones, two each of four types: H2A, H2B, H3 and H4. ...
Slide 1 DNA and RNA are two forms of nucleic acids
... order for a cell to actually create a protein or polypeptide using these genes, the other nucleic acid, RNA is used. Slide 4 As mentioned previously, DNA stores all of the hereditary material for an organism, and this hereditary material is the code of information needed to build proteins. However, ...
... order for a cell to actually create a protein or polypeptide using these genes, the other nucleic acid, RNA is used. Slide 4 As mentioned previously, DNA stores all of the hereditary material for an organism, and this hereditary material is the code of information needed to build proteins. However, ...
Meiosis = nuclear division that reduces chromosome
... Meiosis = nuclear division that reduces chromosome number by half sex cell division gametes = sperm & egg (ovum) (plural = ova) results in 4 haploid cells sperm (23) + egg (23) zygote (46) = fertilized egg you have exactly ½ of your Dad’s chromosomes and ½ of your Mom’s puberty = stage ...
... Meiosis = nuclear division that reduces chromosome number by half sex cell division gametes = sperm & egg (ovum) (plural = ova) results in 4 haploid cells sperm (23) + egg (23) zygote (46) = fertilized egg you have exactly ½ of your Dad’s chromosomes and ½ of your Mom’s puberty = stage ...
name period ______ date
... 4. What is the name given to the point where replication starts on a DNA molecule? 5. How does the replicated daughter molecule of DNA compare to the parent molecule of DNA? 6. What would the complementary bases be if one side of a DNA molecule had the bases adenine, cytosine, cytosine, thymine, thy ...
... 4. What is the name given to the point where replication starts on a DNA molecule? 5. How does the replicated daughter molecule of DNA compare to the parent molecule of DNA? 6. What would the complementary bases be if one side of a DNA molecule had the bases adenine, cytosine, cytosine, thymine, thy ...
Biology 12 Daily Notes - Mrs. Kennedy`s Biology 12 Site!
... 1. Semiconservative = replication results in two DNA molecules each with two strands, one original and one new. 2. Sequence of events a) Helix unwinds b) Both strands replicate simultaneously, during ...
... 1. Semiconservative = replication results in two DNA molecules each with two strands, one original and one new. 2. Sequence of events a) Helix unwinds b) Both strands replicate simultaneously, during ...
Francis Crick - WordPress.com
... Using X-ray diffraction studies of DNA, in 1953, James Watson and Crick constructed a molecular model representing the known physical and chemical properties of DNA. It consisted of two intertwined spiral strands, resembling a twisted ladder (referred to as the "double helix"). They hypothesized tha ...
... Using X-ray diffraction studies of DNA, in 1953, James Watson and Crick constructed a molecular model representing the known physical and chemical properties of DNA. It consisted of two intertwined spiral strands, resembling a twisted ladder (referred to as the "double helix"). They hypothesized tha ...
Homologous recombination
... Retrotransposition mechanisms using DNA targets. The COXI gene of strain 1+t20 (top) contains both the donor aI1 intron (hatched) and the 5 848 ectopic site in intron 5 (open rectangle) The mechanism on the left begins with reverse splicing into the ectopic site in double-stranded DNA. Inefficient n ...
... Retrotransposition mechanisms using DNA targets. The COXI gene of strain 1+t20 (top) contains both the donor aI1 intron (hatched) and the 5 848 ectopic site in intron 5 (open rectangle) The mechanism on the left begins with reverse splicing into the ectopic site in double-stranded DNA. Inefficient n ...
Supplemental Instruction BY123 Dr. Fischer (session 19
... The removal of the RNA primer and addition of DNA nucleotides to the 3' end of Okazaki fragments in its place is carried out by _____. ...
... The removal of the RNA primer and addition of DNA nucleotides to the 3' end of Okazaki fragments in its place is carried out by _____. ...
Comparing Mitosis and Meiosis
... (purely radioactive molecule was not preserved) Replication in eukaryotes was later proved to occur by the same means. ...
... (purely radioactive molecule was not preserved) Replication in eukaryotes was later proved to occur by the same means. ...
From DNA to Protein Name: What does DNA stand for? What is DNA
... what would the nucleotide sequence on the complementary strand of DNA? ...
... what would the nucleotide sequence on the complementary strand of DNA? ...
Only One Strand of DNA Is Translated
... and light strands, and challenged each separately with “early” mRNA and “late” mRNA. They added a DNA endonculease that degraded single-stranded DNA, so that any DNA not bound by the mRNA was degraded. They could then ask which DNA strand bound which mRNA by looking to see which gene survive the deg ...
... and light strands, and challenged each separately with “early” mRNA and “late” mRNA. They added a DNA endonculease that degraded single-stranded DNA, so that any DNA not bound by the mRNA was degraded. They could then ask which DNA strand bound which mRNA by looking to see which gene survive the deg ...
Nucleic Acids - Informational Polymers
... • Organisms inherit DNA from their parents. – Each DNA molecule is very long and usually consists of hundreds to thousands of genes. – When a cell reproduces itself by dividing, its DNA is copied and passed to the next generation of cells. ...
... • Organisms inherit DNA from their parents. – Each DNA molecule is very long and usually consists of hundreds to thousands of genes. – When a cell reproduces itself by dividing, its DNA is copied and passed to the next generation of cells. ...
Biol 3301: Genetics Exam #3 Practice questions
... Black boxes are direct repeats in genomic flanking sequences. IS elements are inverted or tandem. 26. (2) Retrotransposons move via an intermediate that is answer - d a) A double strand DNA circle b) A retrovirus c) Double-strand RNA d) Single-strand RNA e) Single-strand DNA 27. (3) What protein doe ...
... Black boxes are direct repeats in genomic flanking sequences. IS elements are inverted or tandem. 26. (2) Retrotransposons move via an intermediate that is answer - d a) A double strand DNA circle b) A retrovirus c) Double-strand RNA d) Single-strand RNA e) Single-strand DNA 27. (3) What protein doe ...
Holliday junction
A Holliday junction is a branched nucleic acid structure that contains four double-stranded arms joined together. These arms may adopt one of several conformations depending on buffer salt concentrations and the sequence of nucleobases closest to the junction. The structure is named after the molecular biologist Robin Holliday, who proposed its existence in 1964.In biology, Holliday junctions are a key intermediate in many types of genetic recombination, as well as in double-strand break repair. These junctions usually have a symmetrical sequence and are thus mobile, meaning that the four individual arms may slide though the junction in a specific pattern that largely preserves base pairing. Additionally, four-arm junctions similar to Holliday junctions appear in some functional RNA molecules.Immobile Holliday junctions, with asymmetrical sequences that lock the strands in a specific position, were artificially created by scientists to study their structure as a model for natural Holliday junctions. These junctions also later found use as basic structural building blocks in DNA nanotechnology, where multiple Holliday junctions can be combined into specific designed geometries that provide molecules with a high degree of structural rigidity.