Work sheet –chapter 2 CLASS - XI CHEMISTRY (Structure of Atom
... 11. Why Rutherford’s model could not explain the stability of an atom? ...
... 11. Why Rutherford’s model could not explain the stability of an atom? ...
Ch.3 lecture
... Energy levels and transitions of the many-electron atom: Sodium Quantum states of the valence electron ...
... Energy levels and transitions of the many-electron atom: Sodium Quantum states of the valence electron ...
Chapter 4: Struct of Atom
... S Classical and quantum domains are different S Planck’s constant helps with deciding where we are: e.g., energy of a baseball is classical while the energy of a moving electron is quantum S h = 6.626 x 10^-34 J-s -> E of baseball =(1/2)mv^2 is ~Joules and m ~ 0.1 kg while v ~ 90 mph ~ 40 m/s so ...
... S Classical and quantum domains are different S Planck’s constant helps with deciding where we are: e.g., energy of a baseball is classical while the energy of a moving electron is quantum S h = 6.626 x 10^-34 J-s -> E of baseball =(1/2)mv^2 is ~Joules and m ~ 0.1 kg while v ~ 90 mph ~ 40 m/s so ...
Chapter 38
... A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in "head-on" to a particular lead nucleus and stops 6.50×10−14 m away from the center of the nucleus. (This point is well outside the nucleus). Assume that the lead nucleus, which has 82 protons, remains at ...
... A beam of alpha particles is incident on a target of lead. A particular alpha particle comes in "head-on" to a particular lead nucleus and stops 6.50×10−14 m away from the center of the nucleus. (This point is well outside the nucleus). Assume that the lead nucleus, which has 82 protons, remains at ...
APCh7MB
... Calculate E corresponding to n=3 in H atom. E = -2.178 X 10-18 J [12/32] = -2.42 X 10-19 J When you move there is a change in energy. Δ E = Efinal – Einitial Δ E = -2.178 X 10-18 J [z2/nf2 – z2/ni2] If going from 13, ni=1 and nf=3 ΔE=(-2.178 X 10-18J [12/32]) – (-2.178 X 10-18J [12/12]) ΔE = -2.178 ...
... Calculate E corresponding to n=3 in H atom. E = -2.178 X 10-18 J [12/32] = -2.42 X 10-19 J When you move there is a change in energy. Δ E = Efinal – Einitial Δ E = -2.178 X 10-18 J [z2/nf2 – z2/ni2] If going from 13, ni=1 and nf=3 ΔE=(-2.178 X 10-18J [12/32]) – (-2.178 X 10-18J [12/12]) ΔE = -2.178 ...
Nuclear Chemistry
... Electron Capture (K-Capture) Addition of an electron to a proton in the nucleus is known as electron capture or Kcapture. – The result of this process is that a proton is transformed into a neutron. ...
... Electron Capture (K-Capture) Addition of an electron to a proton in the nucleus is known as electron capture or Kcapture. – The result of this process is that a proton is transformed into a neutron. ...
Hydrocarbon Notes
... Naming branched alkanes: 1. Find the ____________ _______________ carbon chain. 2. Number the _____________ in the __________ chain beginning at the end ____________ the 1st branch. 3. ______________ and number each _____________ according to which ______________ it is attached to. 4. Write the name ...
... Naming branched alkanes: 1. Find the ____________ _______________ carbon chain. 2. Number the _____________ in the __________ chain beginning at the end ____________ the 1st branch. 3. ______________ and number each _____________ according to which ______________ it is attached to. 4. Write the name ...
The Electron - webhosting.au.edu
... through space in the form of waves.. Radioactivity (Antoine Henri Becquerel(1852-1908) spontaneous emission of particles and / or radiation / ...
... through space in the form of waves.. Radioactivity (Antoine Henri Becquerel(1852-1908) spontaneous emission of particles and / or radiation / ...
Chapter 6 lecture 1
... Bohr proposed that: the electron moves around the proton only in circular 'orbits' of certain allowed radii, which correspond to certain definite energies ...
... Bohr proposed that: the electron moves around the proton only in circular 'orbits' of certain allowed radii, which correspond to certain definite energies ...
1 - shawnschmitt
... g. Mole- the amount of particles in 12g of Carbon-12, also, the amount of substance having 6.022x1023 of any kind of particle h. half-life- the amount of time required for ½ of the mass of an isotope to decay i. metalloid- those elements that have properties of both metals and nonmetals j. Ionizatio ...
... g. Mole- the amount of particles in 12g of Carbon-12, also, the amount of substance having 6.022x1023 of any kind of particle h. half-life- the amount of time required for ½ of the mass of an isotope to decay i. metalloid- those elements that have properties of both metals and nonmetals j. Ionizatio ...
Introduction to Spectroscopy
... • What is the connection of this with spectroscopy? – Fapplied is due to EM radiation (monochromatic at ω) – When ω is far from ωo then e- is forced to oscillate at ω and not the natural frequency of the bond – energy is absorbed and there is a transition to an excited state – explains absorption in ...
... • What is the connection of this with spectroscopy? – Fapplied is due to EM radiation (monochromatic at ω) – When ω is far from ωo then e- is forced to oscillate at ω and not the natural frequency of the bond – energy is absorbed and there is a transition to an excited state – explains absorption in ...
Mathematical Methods of Physics – Fall 2010 – Dr
... The delayed choice experiment detailed on page 91 of Krane shows that it is not the case that light is sometimes a particle and sometimes a wave. The experiment shows that light has properties of a particle and of a wave all the time. On page 93, Krane writes that particle and wave behavior “must so ...
... The delayed choice experiment detailed on page 91 of Krane shows that it is not the case that light is sometimes a particle and sometimes a wave. The experiment shows that light has properties of a particle and of a wave all the time. On page 93, Krane writes that particle and wave behavior “must so ...
Chemistry—Chapter 13: Electrons in Atoms
... 4. Write a complete electron configuration of each atom, including orbital notations. Give the quantum numbers for the highest energy electron in each atom a. hydrogen b. barium c. bromine d. sulfur e. krypton f. arsenic g. vanadium ...
... 4. Write a complete electron configuration of each atom, including orbital notations. Give the quantum numbers for the highest energy electron in each atom a. hydrogen b. barium c. bromine d. sulfur e. krypton f. arsenic g. vanadium ...
Bremsstrahlung
Bremsstrahlung (German pronunciation: [ˈbʁɛmsˌʃtʁaːlʊŋ], from bremsen ""to brake"" and Strahlung ""radiation"", i.e. ""braking radiation"" or ""deceleration radiation"") is electromagnetic radiation produced by the deceleration of a charged particle when deflected by another charged particle, typically an electron by an atomic nucleus. The moving particle loses kinetic energy, which is converted into a photon, thus satisfying the law of conservation of energy. The term is also used to refer to the process of producing the radiation. Bremsstrahlung has a continuous spectrum, which becomes more intense and whose peak intensity shifts toward higher frequencies as the change of the energy of the accelerated particles increases.Strictly speaking, braking radiation is any radiation due to the acceleration of a charged particle, which includes synchrotron radiation, cyclotron radiation, and the emission of electrons and positrons during beta decay. However, the term is frequently used in the more narrow sense of radiation from electrons (from whatever source) slowing in matter.Bremsstrahlung emitted from plasma is sometimes referred to as free/free radiation. This refers to the fact that the radiation in this case is created by charged particles that are free both before and after the deflection (acceleration) that caused the emission.