December 2013 Activity Solutions
... consecutive numbers in this list is 10. Using what we learned from the video, we can conclude that the arithmetic mean of this list of numbers will be the middle value, which we can determine by adding the first and last numbers in the list and dividing by two. So the arithmetic mean of these number ...
... consecutive numbers in this list is 10. Using what we learned from the video, we can conclude that the arithmetic mean of this list of numbers will be the middle value, which we can determine by adding the first and last numbers in the list and dividing by two. So the arithmetic mean of these number ...
UNIT 1: REAL NUMBERS Equivalent fractions Two fractions are
... To round down, just cut off the number at the place you want. See the table below. b) Rounding is the most usual kind of estimating. To round a decimal number, find the place value you want and look at the digit just to the right. If it is 5 or more, then round up. If it is 4 or less, round down. Th ...
... To round down, just cut off the number at the place you want. See the table below. b) Rounding is the most usual kind of estimating. To round a decimal number, find the place value you want and look at the digit just to the right. If it is 5 or more, then round up. If it is 4 or less, round down. Th ...
Complex Numbers
... If b2 – 4ac < 0, then the equation has no real solution. But in the complex number system, this equation will always have solutions, because negative numbers have square roots in this expanded setting. ...
... If b2 – 4ac < 0, then the equation has no real solution. But in the complex number system, this equation will always have solutions, because negative numbers have square roots in this expanded setting. ...
Numbers Strand Lecture 5 (Week 8)
... [If k were equal to 1, then n = 2 . However, we know that n > 2 .] Therefore, we have positive numbers 2 and k where n = 2k and k ≠ 1, 2 ≠ 1 . Thus, by definition, n is composite. This is a contradiction, as we said n is prime. Therefore, there does not exist an even prime n such that n > 2 , and so ...
... [If k were equal to 1, then n = 2 . However, we know that n > 2 .] Therefore, we have positive numbers 2 and k where n = 2k and k ≠ 1, 2 ≠ 1 . Thus, by definition, n is composite. This is a contradiction, as we said n is prime. Therefore, there does not exist an even prime n such that n > 2 , and so ...
Slides Set 2
... The Big Oh notation was introduced by the number theorist Paul Bachman in 1894. It perfectly matches ...
... The Big Oh notation was introduced by the number theorist Paul Bachman in 1894. It perfectly matches ...
Math Glossary - Waioneke School
... The list below explains the meaning of some of the key terms used in the math: Meaning ...
... The list below explains the meaning of some of the key terms used in the math: Meaning ...