CfE Advanced Higher Physics – Unit 1 – Rotational Motion
... The moment of inertia of each mass is m r2 = 0.8 x 0.52= 0.2 kg m2 giving a total moment of inertia I = 0.4 kg m2. Notice that we assume that all the mass is at the 50 cm distance. The small moment of inertia of the light rod has been ignored. Another example is a hoop, with very light spokes connec ...
... The moment of inertia of each mass is m r2 = 0.8 x 0.52= 0.2 kg m2 giving a total moment of inertia I = 0.4 kg m2. Notice that we assume that all the mass is at the 50 cm distance. The small moment of inertia of the light rod has been ignored. Another example is a hoop, with very light spokes connec ...
PHYSICS UNIT 3 Motion
... force on an object can be calculated by multiplying its mass by (the acceleration due to gravity), that is :W = mg, where g =9.8 Newton/kg or m/s2. It also acceptable to approximate this to 10 N/kg. This force acts vertically downwards and can be considered to act through the centre of the object, t ...
... force on an object can be calculated by multiplying its mass by (the acceleration due to gravity), that is :W = mg, where g =9.8 Newton/kg or m/s2. It also acceptable to approximate this to 10 N/kg. This force acts vertically downwards and can be considered to act through the centre of the object, t ...
Random Problems
... When the mass is set in motion and air resistance is negligible. Will the total energy of the system be conserved? Yes, mechanical energy is always conserved in the presence of conservative (non-dissipative) forces such as gravity and the restoring force within a spring. ...
... When the mass is set in motion and air resistance is negligible. Will the total energy of the system be conserved? Yes, mechanical energy is always conserved in the presence of conservative (non-dissipative) forces such as gravity and the restoring force within a spring. ...
Lesson 10 notes - Angular Measurement - science
... For there to be circular motion the forces must be unbalanced. There is a centripetal force that is proportional to a centripetal acceleration. If there is no more centripetal force the object does not fly out of the circle away from the centre of the circle it just carries along in a straight line ...
... For there to be circular motion the forces must be unbalanced. There is a centripetal force that is proportional to a centripetal acceleration. If there is no more centripetal force the object does not fly out of the circle away from the centre of the circle it just carries along in a straight line ...
NewtonsLaws
... between all objects that have mass. • Objects fall to the ground because Earth exerts gravity on them. • Earth’s gravitational force pulls objects towards Earth’s surface. • Mass is the amount of matter in an object. • Mass is often measured in kilograms (kg). ...
... between all objects that have mass. • Objects fall to the ground because Earth exerts gravity on them. • Earth’s gravitational force pulls objects towards Earth’s surface. • Mass is the amount of matter in an object. • Mass is often measured in kilograms (kg). ...
Answers
... 2.1.3B – Calculate the force of kinetic friction. Determine net force in a system that is sliding. Determine the coefficient of kinetic friction in a sliding system. Determine: net force; applied force; friction force; and/or acceleration. A 3.0 kilogram wooden object is sliding along a wooden surfa ...
... 2.1.3B – Calculate the force of kinetic friction. Determine net force in a system that is sliding. Determine the coefficient of kinetic friction in a sliding system. Determine: net force; applied force; friction force; and/or acceleration. A 3.0 kilogram wooden object is sliding along a wooden surfa ...
Physics Review #1
... a seat reading this question. The magnitude of the force with which the seat is pushing up on the student to support him is closest to ...
... a seat reading this question. The magnitude of the force with which the seat is pushing up on the student to support him is closest to ...
Astronomy Essay Questions
... process of stellar evolution? Describe and discuss neutron stars. What are they? Describe their physical characteristics. What was the phenomenon that led to their discovery? How are they observed? Where do they fit into the scheme of stellar evolution? Describe and discuss white dwarf stars. What a ...
... process of stellar evolution? Describe and discuss neutron stars. What are they? Describe their physical characteristics. What was the phenomenon that led to their discovery? How are they observed? Where do they fit into the scheme of stellar evolution? Describe and discuss white dwarf stars. What a ...
PPT
... What have we learned? • How do we measure the distances to galaxies? – The distance-measurement chain begins with parallax measurements that build on radar ranging in our solar system – Using parallax and the relationship between luminosity, distance, and brightness, we can calibrate a series of st ...
... What have we learned? • How do we measure the distances to galaxies? – The distance-measurement chain begins with parallax measurements that build on radar ranging in our solar system – Using parallax and the relationship between luminosity, distance, and brightness, we can calibrate a series of st ...
Circular Motion - Manchester HEP
... The experiment analysed in the tutorial question is now setup and performed. A light gate is used to determine the angular velocity of the disk. The light gate is triggered on and off by a plastic wedge of 10o size that is attached to the disk. Please be careful with this experiment as the plastic p ...
... The experiment analysed in the tutorial question is now setup and performed. A light gate is used to determine the angular velocity of the disk. The light gate is triggered on and off by a plastic wedge of 10o size that is attached to the disk. Please be careful with this experiment as the plastic p ...
Interview Format - PhysicsEducation.net
... DEM: So, if we had the same force, and we had the bigger mass, are we going to get the bigger acceleration? STUDENT: If we have the same force, and we have more mass . . . Now you're going to have less acceleration. So that [her statement about bigger acceleration] is so wrong. So a is F over m. ...
... DEM: So, if we had the same force, and we had the bigger mass, are we going to get the bigger acceleration? STUDENT: If we have the same force, and we have more mass . . . Now you're going to have less acceleration. So that [her statement about bigger acceleration] is so wrong. So a is F over m. ...
FYC5_CON 4_ Rocket propulsion _SYNOPSIS Rocket propulsion
... Out of the given bodies (of same mass) for which the moment of inertia will be maximum about the axis passing through its centre of gravity and perpendicular to its plane (1) Disc of radius a (2) Ring of radius a (3) Square lamina of side 2a (4) Four rods each of length 2a making a square be the ...
... Out of the given bodies (of same mass) for which the moment of inertia will be maximum about the axis passing through its centre of gravity and perpendicular to its plane (1) Disc of radius a (2) Ring of radius a (3) Square lamina of side 2a (4) Four rods each of length 2a making a square be the ...
11-Apr-16 15 - Fulton Schools of Engineering Tutoring Centers
... according to x(t) = t + 2t3, where x is measured in meters and t is in seconds. ...
... according to x(t) = t + 2t3, where x is measured in meters and t is in seconds. ...
Rotation
... In fact, (8) holds for non-circular motion, but the proof requires more effort; see Section 2.4. Equation (8) is the rotational analogue of the momentum principle for translational motion: force = rate of change of momentum For single particles the angular-momentum equation offers no advantage over ...
... In fact, (8) holds for non-circular motion, but the proof requires more effort; see Section 2.4. Equation (8) is the rotational analogue of the momentum principle for translational motion: force = rate of change of momentum For single particles the angular-momentum equation offers no advantage over ...
Concept Questions
... The time derivative that appears in the second term in the above expression, the time derivative of the momentum of a mass element in the center-of mass-frame, is equal to the force acting on that element which include both inertial and fictitious forces, ...
... The time derivative that appears in the second term in the above expression, the time derivative of the momentum of a mass element in the center-of mass-frame, is equal to the force acting on that element which include both inertial and fictitious forces, ...
Review for Final Exam Exams 1, 2, 3, and 4 How to Understand
... Quick Quiz Solution: The friction force appears as it keeps from sliding back on the truck’s bed. Thus, the direction of the (static) friction is pointing to the right. If you isolate the box, and draw the free-body diagram for the box, you ...
... Quick Quiz Solution: The friction force appears as it keeps from sliding back on the truck’s bed. Thus, the direction of the (static) friction is pointing to the right. If you isolate the box, and draw the free-body diagram for the box, you ...
A1 Physics Unit 5: Newton`s Laws Conceptual Physics Newton`s
... 24. If you start with an acceleration of 10 m/s2, what would your new acceleration be if you multiply the mass by three and multiply the force by four? [13.33 m/s2] 25. A 1500 kg car can accelerate uniformly at 4 m/s2. What will its acceleration be if it accelerates while pulling another car of the ...
... 24. If you start with an acceleration of 10 m/s2, what would your new acceleration be if you multiply the mass by three and multiply the force by four? [13.33 m/s2] 25. A 1500 kg car can accelerate uniformly at 4 m/s2. What will its acceleration be if it accelerates while pulling another car of the ...
Momentum - barransclass
... second law a = F/m. Then we can find Dv using the definition of acceleration a = Dv/Dt. ...
... second law a = F/m. Then we can find Dv using the definition of acceleration a = Dv/Dt. ...
Modified Newtonian dynamics
In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.