
Chapter 4: Forces and Newton`s Laws of Motion
... The free body diagram (FBD) is a simplified representation of an object, and the forces acting on it. It is called free because the diagram will show the object without its surroundings; i.e. the body is “free” of its environment. We will consider only the forces acting on our object of interest. Th ...
... The free body diagram (FBD) is a simplified representation of an object, and the forces acting on it. It is called free because the diagram will show the object without its surroundings; i.e. the body is “free” of its environment. We will consider only the forces acting on our object of interest. Th ...
Part 2
... NOTE 1: The coefficients of friction are independent of the area of contact and the speed of the object. They only depend on the types of surfaces in contact. NOTE 2: When an object is on the verge of slipping, its acceleration is still zero and the static friction force is at its maximum value so c ...
... NOTE 1: The coefficients of friction are independent of the area of contact and the speed of the object. They only depend on the types of surfaces in contact. NOTE 2: When an object is on the verge of slipping, its acceleration is still zero and the static friction force is at its maximum value so c ...
Chapter 11 Science Notes
... • Speed- how fast an object’s position changes over time. To calculate speed: Speed=distance ÷ time ...
... • Speed- how fast an object’s position changes over time. To calculate speed: Speed=distance ÷ time ...
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... we simulate a trip through space, we see the images of objects in the universe as they appeared when the light first left them to travel across space to reach our detectors. Note that the images in this animation are simulated from telescopic observations, but are not represent actual photographs. W ...
... we simulate a trip through space, we see the images of objects in the universe as they appeared when the light first left them to travel across space to reach our detectors. Note that the images in this animation are simulated from telescopic observations, but are not represent actual photographs. W ...
Concept Summary
... 5. Write down the values given to you and identify what they represent (e.g., the 2 m/s given is the final velocity). 6. Identify and write down what variables/quantities you are being asked to determine. 7. Identify the physics of the problem. This will point you to the equation or set of equations ...
... 5. Write down the values given to you and identify what they represent (e.g., the 2 m/s given is the final velocity). 6. Identify and write down what variables/quantities you are being asked to determine. 7. Identify the physics of the problem. This will point you to the equation or set of equations ...
force
... Why is a heavy truck harder to stop than a small moving car at the same speed? - truck has a greater mass, therefore greater momentum Can you change an objects momentum? - Yes, using forces, but most importantly “how long” that force is applied ex. force applied briefly to a stalled car, small c ...
... Why is a heavy truck harder to stop than a small moving car at the same speed? - truck has a greater mass, therefore greater momentum Can you change an objects momentum? - Yes, using forces, but most importantly “how long” that force is applied ex. force applied briefly to a stalled car, small c ...
Physics - Allen ISD
... a. kg b. m/s2 c. N d. kg m/s 5. You would have a larger mass of gold if your chunk of gold weighed 1 N on _____. (THINK!!) a. the moon b. Earth c. it doesn’t matter which planet you are on. 6. Which has more mass, a kilogram of feathers or a kilogram of iron? a. the feathers b. the iron c. same mass ...
... a. kg b. m/s2 c. N d. kg m/s 5. You would have a larger mass of gold if your chunk of gold weighed 1 N on _____. (THINK!!) a. the moon b. Earth c. it doesn’t matter which planet you are on. 6. Which has more mass, a kilogram of feathers or a kilogram of iron? a. the feathers b. the iron c. same mass ...
Gravitation - India Study Channel
... product of their masses and inversely proportional to the square of the distance between them. Force is direct along the line joining the particles and towards other particle. ...
... product of their masses and inversely proportional to the square of the distance between them. Force is direct along the line joining the particles and towards other particle. ...
File
... What is the acceleration of the object in m/s2? The second law says a = F/m. Therefore a = 25 N /10 kg = 2.5 m/s2 If the object starts at rest, then how long will it be before its velocity is 25 m/s? You know that v = v0 + at and v0= 0. Rearranging gives t = v/a = (25 m/s) / (2.5 m/s2) = 10 seconds. ...
... What is the acceleration of the object in m/s2? The second law says a = F/m. Therefore a = 25 N /10 kg = 2.5 m/s2 If the object starts at rest, then how long will it be before its velocity is 25 m/s? You know that v = v0 + at and v0= 0. Rearranging gives t = v/a = (25 m/s) / (2.5 m/s2) = 10 seconds. ...
CHAPTER 10 QUESTION SETS
... water, a calculator. In class, we’ll see how close you were. (A lemon or an apple = approx. 1 N) 12. What would be the velocity of an object in a state of free fall after 4 seconds? 13. How does air resistance affect falling objects? ...
... water, a calculator. In class, we’ll see how close you were. (A lemon or an apple = approx. 1 N) 12. What would be the velocity of an object in a state of free fall after 4 seconds? 13. How does air resistance affect falling objects? ...
Inertia and Newtons laws of motion
... Galileo argued that only when friction is present is a force needed to keep an object moving. Galileo stated that if friction were entirely absent, a ball moving horizontally would move forever at the same speed and in the same direction (at a constant velocity). ...
... Galileo argued that only when friction is present is a force needed to keep an object moving. Galileo stated that if friction were entirely absent, a ball moving horizontally would move forever at the same speed and in the same direction (at a constant velocity). ...
ch10
... Sample problem, cont. (b) What is the magnitude a of the passenger’s net acceleration at point P and after point P? Reasoning: At P, a has the design value of 4g. Just after P is reached, the passenger moves in a straight line and no longer has centripetal acceleration. Thus, the passenger has only ...
... Sample problem, cont. (b) What is the magnitude a of the passenger’s net acceleration at point P and after point P? Reasoning: At P, a has the design value of 4g. Just after P is reached, the passenger moves in a straight line and no longer has centripetal acceleration. Thus, the passenger has only ...
Modified Newtonian dynamics

In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.