
Announcements
... Motion in one dimension l …or, to be more precise, one space dimension (x) and one time dimension (t) l We want to characterize the position along the x axis as a function of time l Note that we plot x on the vertical axis as it is the dependent variable and t on the horizontal axis as it is ...
... Motion in one dimension l …or, to be more precise, one space dimension (x) and one time dimension (t) l We want to characterize the position along the x axis as a function of time l Note that we plot x on the vertical axis as it is the dependent variable and t on the horizontal axis as it is ...
Document
... 4 N = 10 kg * a a = 0.4 m/s² Downhill ramp (w/Friction) while weight hangs over a Pulley Coefficient of kinetic friction = 0.6 It's actually better to show the normal force originating at the table top (ramp) and rising perpendicular to the surface of the ramp. (instead of below as shown) I just wan ...
... 4 N = 10 kg * a a = 0.4 m/s² Downhill ramp (w/Friction) while weight hangs over a Pulley Coefficient of kinetic friction = 0.6 It's actually better to show the normal force originating at the table top (ramp) and rising perpendicular to the surface of the ramp. (instead of below as shown) I just wan ...
Problem-Solving Strategies
... (a) Find the magnitudes of the forces F and F that add to give the total force F shown in Figure 2. This may be done either graphically or by using trigonometry. (b) Show graphically that the same total force is obtained independent of the order of addition of F and F . (c) Find the direction and ma ...
... (a) Find the magnitudes of the forces F and F that add to give the total force F shown in Figure 2. This may be done either graphically or by using trigonometry. (b) Show graphically that the same total force is obtained independent of the order of addition of F and F . (c) Find the direction and ma ...
Serway_PSE_quick_ch05
... component of the gravitational force parallel to the board is approximately equal to the maximum static friction force. Because the kinetic coefficient of friction is smaller than the static coefficient, at this angle, the component of the gravitational force parallel to the board is larger than the ...
... component of the gravitational force parallel to the board is approximately equal to the maximum static friction force. Because the kinetic coefficient of friction is smaller than the static coefficient, at this angle, the component of the gravitational force parallel to the board is larger than the ...
Slide 1
... circular path with a radius of 25 meters to point P. At point P, the car hits an area of ice and loses all frictional force on its tires. Which path does the car follow on the ice? A) A ...
... circular path with a radius of 25 meters to point P. At point P, the car hits an area of ice and loses all frictional force on its tires. Which path does the car follow on the ice? A) A ...
1 Chapter 12 Static Equilibrium Equilibrium Summary Static vs
... This is a statement of translational equilibrium The acceleration of the center of mass of the object must be zero when viewed from an inertial frame of reference ...
... This is a statement of translational equilibrium The acceleration of the center of mass of the object must be zero when viewed from an inertial frame of reference ...
Slide 1
... circular path with a radius of 25 meters to point P. At point P, the car hits an area of ice and loses all frictional force on its tires. Which path does the car follow on the ice? A) A ...
... circular path with a radius of 25 meters to point P. At point P, the car hits an area of ice and loses all frictional force on its tires. Which path does the car follow on the ice? A) A ...
A force
... Weight (in newtons) = mass x acceleration due to gravity. 1 kg x 9.8 m/s/s = 9.8 Newtons ...
... Weight (in newtons) = mass x acceleration due to gravity. 1 kg x 9.8 m/s/s = 9.8 Newtons ...
Acceleration due to gravity
... When we use the word “acceleration” we mean the rate at which the velocity of a moving object changes with time. Acceleration is always caused by force – gravitational force as one of the fundamental forces of nature. This is the essence of Newton’s first law. In today’s lab we will measure the acce ...
... When we use the word “acceleration” we mean the rate at which the velocity of a moving object changes with time. Acceleration is always caused by force – gravitational force as one of the fundamental forces of nature. This is the essence of Newton’s first law. In today’s lab we will measure the acce ...
Version 072 – Midterm 2
... The normal force of the wall on the rider provides the centripetal acceleration necessary to keep her going around in a circle. The downward force of gravity is equal and opposite to the upward frictional force on her. Note: Since this problem states that it is viewed by a bystander, we assume that ...
... The normal force of the wall on the rider provides the centripetal acceleration necessary to keep her going around in a circle. The downward force of gravity is equal and opposite to the upward frictional force on her. Note: Since this problem states that it is viewed by a bystander, we assume that ...
hw2 - forces - Uplift North Hills Prep
... 16. In her physics lab, Molly puts a 1.0-kg mass on a 2.0-kg block of wood. She pulls the combination across another wooden board with a constant speed to determine the coefficient of sliding friction between the two surfaces. If Molly must pull with a force of 6.0 N, what coefficient of sliding fri ...
... 16. In her physics lab, Molly puts a 1.0-kg mass on a 2.0-kg block of wood. She pulls the combination across another wooden board with a constant speed to determine the coefficient of sliding friction between the two surfaces. If Molly must pull with a force of 6.0 N, what coefficient of sliding fri ...
Document
... Newton’s Law of Gravitation Gravitational force: an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the ...
... Newton’s Law of Gravitation Gravitational force: an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the ...
Chapter 1 Matter in Motion
... Helps reduce the amount of friction. Lets take the same box of bricks I talked about earlier and put them on a cart with wheels. Pushing them across the floor would become a lot easier. This would be an example of rolling friction. ...
... Helps reduce the amount of friction. Lets take the same box of bricks I talked about earlier and put them on a cart with wheels. Pushing them across the floor would become a lot easier. This would be an example of rolling friction. ...
Modified Newtonian dynamics

In physics, modified Newtonian dynamics (MOND) is a theory that proposes a modification of Newton's laws to account for observed properties of galaxies. Created in 1983 by Israeli physicist Mordehai Milgrom, the theory's original motivation was to explain the fact that the velocities of stars in galaxies were observed to be larger than expected based on Newtonian mechanics. Milgrom noted that this discrepancy could be resolved if the gravitational force experienced by a star in the outer regions of a galaxy was proportional to the square of its centripetal acceleration (as opposed to the centripetal acceleration itself, as in Newton's Second Law), or alternatively if gravitational force came to vary inversely with radius (as opposed to the inverse square of the radius, as in Newton's Law of Gravity). In MOND, violation of Newton's Laws occurs at extremely small accelerations, characteristic of galaxies yet far below anything typically encountered in the Solar System or on Earth.MOND is an example of a class of theories known as modified gravity, and is an alternative to the hypothesis that the dynamics of galaxies are determined by massive, invisible dark matter halos. Since Milgrom's original proposal, MOND has successfully predicted a variety of galactic phenomena that are difficult to understand from a dark matter perspective. However, MOND and its generalisations do not adequately account for observed properties of galaxy clusters, and no satisfactory cosmological model has been constructed from the theory.