
Ch.6 Momentum
... 2 Object Momentum Conservation • momentum before = momentum after • (m1v1)initial + (m2v2)initial = (m1v1)final + (m2v2)final • When can we use this equation? • When net force due to all other objects acting on 1 and 2 is zero. • Or, very soon after collision ends ...
... 2 Object Momentum Conservation • momentum before = momentum after • (m1v1)initial + (m2v2)initial = (m1v1)final + (m2v2)final • When can we use this equation? • When net force due to all other objects acting on 1 and 2 is zero. • Or, very soon after collision ends ...
Concept Questions
... The total torque on a rigid body due to the gravitational force can be determined by placing all the gravitational force at the center-of-mass of the object. ...
... The total torque on a rigid body due to the gravitational force can be determined by placing all the gravitational force at the center-of-mass of the object. ...
Force & Motion
... A car driving up a hill and down the other side. A car turning a corner. A car turning a corner at a constant speed. A car driving at a constant speed along a straight ...
... A car driving up a hill and down the other side. A car turning a corner. A car turning a corner at a constant speed. A car driving at a constant speed along a straight ...
UNIT 4 - Uplift North Hills
... A 0.014kg red bouncy ball is traveling at a velocity of 1.2 m/s to the right. It collides elastically with a initially stationary blue bouncy ball (mass of 0.011 kg). If the red ball has a final velocity of 0.5 m/s to the left, what is the final velocity of the blue ball? G: m1 = 0.014kg v1i = 1.2 m ...
... A 0.014kg red bouncy ball is traveling at a velocity of 1.2 m/s to the right. It collides elastically with a initially stationary blue bouncy ball (mass of 0.011 kg). If the red ball has a final velocity of 0.5 m/s to the left, what is the final velocity of the blue ball? G: m1 = 0.014kg v1i = 1.2 m ...
IMPULSE: F = ∆(mv)/∆t ⇒ F ∆t = ∆ (mv)
... object is equal to the change of its kinetic energy. W = F d = ∆(½ m v2) By Newton’s third law the force acting on the object is equal and opposite to the force exerted by the object on the external agent! Therefore, the work done by that force – by the object is equal to the work done on it with a ...
... object is equal to the change of its kinetic energy. W = F d = ∆(½ m v2) By Newton’s third law the force acting on the object is equal and opposite to the force exerted by the object on the external agent! Therefore, the work done by that force – by the object is equal to the work done on it with a ...
Powerpoint for today
... An object that is at rest will remain at rest and an object that is moving will continue to move in a straight line with constant speed, if and only if the sum of the forces acting on that object is zero. Newton's 2nd Law acceleration of an object = sum of forces acting on that object / the mass of ...
... An object that is at rest will remain at rest and an object that is moving will continue to move in a straight line with constant speed, if and only if the sum of the forces acting on that object is zero. Newton's 2nd Law acceleration of an object = sum of forces acting on that object / the mass of ...
An intro to forces
... 2. GRAVITATIONAL force is the force of attraction between two different masses. The larger the mass, the more gravitational force is present. LAW OF UNIVERSAL GRAVITATION: Every object in the universe attracts every other object in the universe with a force that is directly related to the product of ...
... 2. GRAVITATIONAL force is the force of attraction between two different masses. The larger the mass, the more gravitational force is present. LAW OF UNIVERSAL GRAVITATION: Every object in the universe attracts every other object in the universe with a force that is directly related to the product of ...
6. APPLICATION OF NEWTON`S LAWS Concepts: 6.1 FRICTION
... would you think the K would be greater or smaller than the weak spring? Why? For great distances, Hooke’s law does not work. The spring breaks down and doesn’t pull or push. ...
... would you think the K would be greater or smaller than the weak spring? Why? For great distances, Hooke’s law does not work. The spring breaks down and doesn’t pull or push. ...
Name ID
... The hand is pushing with the same force as before on the new system of blocks. The new system has a larger mass, so the acceleration of the system is smaller than before. Since all the blocks are moving together, the acceleration of block A, which is equal to that of the system, is also smaller than ...
... The hand is pushing with the same force as before on the new system of blocks. The new system has a larger mass, so the acceleration of the system is smaller than before. Since all the blocks are moving together, the acceleration of block A, which is equal to that of the system, is also smaller than ...
5 N
... Forces • If all forces are balanced there is no acceleration in any direction. – (Either Zero Motion or Constant Velocity) ...
... Forces • If all forces are balanced there is no acceleration in any direction. – (Either Zero Motion or Constant Velocity) ...
Midterm
... 40. The orientation of the collagen fibers at the superficial tangential zone of an articular cartilage is _____ to the articular surface in order to withstand _____ stresses. a. parallel, shear b. oblique, twist c. vertical, compression d. random, any kind of 41. The strength of a bone is defined a ...
... 40. The orientation of the collagen fibers at the superficial tangential zone of an articular cartilage is _____ to the articular surface in order to withstand _____ stresses. a. parallel, shear b. oblique, twist c. vertical, compression d. random, any kind of 41. The strength of a bone is defined a ...
LAHS Physics - LAPhysics.com
... following statements is true concerning the tension in the string if air resistance is not ignored? A) The tension is zero newtons. B) The tension points downward. C) The tension is equal to the weight of the rock. D) The tension is less than the weight of the rock. E) The tension is greater than th ...
... following statements is true concerning the tension in the string if air resistance is not ignored? A) The tension is zero newtons. B) The tension points downward. C) The tension is equal to the weight of the rock. D) The tension is less than the weight of the rock. E) The tension is greater than th ...
work
... an object is positive, the kinetic energy of the object will increase. – When net work due to all forces acting upon an object is negative, the kinetic energy of the object will decrease. – When there is no net work acting upon an object, the kinetic energy of the object will be ...
... an object is positive, the kinetic energy of the object will increase. – When net work due to all forces acting upon an object is negative, the kinetic energy of the object will decrease. – When there is no net work acting upon an object, the kinetic energy of the object will be ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.