Properties of Real Numbers
... Commutative: a + b = b + a ab = ba Associative: (a+b)+c = a+(b+c) (ab)c = a(bc) Identity: a + 0 = 0 + a = a a*1 = 1*a = a ...
... Commutative: a + b = b + a ab = ba Associative: (a+b)+c = a+(b+c) (ab)c = a(bc) Identity: a + 0 = 0 + a = a a*1 = 1*a = a ...
POSITIVE AND NEGATIVE INTEGERS
... C. Rules for Multiplying and Dividing Positive and Negative Numbers With both multiplication and division, when the signs are the same, the answer will be positive Example #1: (+5) × (+7) = +35 Example #2: (-5) × (-7) = +35 Example #3: (+10) ÷ (+2) = +5 Example #4: (-10) ÷ (-2) = +5 ...
... C. Rules for Multiplying and Dividing Positive and Negative Numbers With both multiplication and division, when the signs are the same, the answer will be positive Example #1: (+5) × (+7) = +35 Example #2: (-5) × (-7) = +35 Example #3: (+10) ÷ (+2) = +5 Example #4: (-10) ÷ (-2) = +5 ...
Square Roots - Mr. Hooks Math
... have finite (ends) number of digits. (ex 2/5= 0.40 ) • Repeating decimal -rational numbers in decimal form that have a block for one or more digits that repeats continuously. (ex. 1.3=1.333333333) • Irrational numbers - numbers that cannot be expressed as a fraction including square roots of whole n ...
... have finite (ends) number of digits. (ex 2/5= 0.40 ) • Repeating decimal -rational numbers in decimal form that have a block for one or more digits that repeats continuously. (ex. 1.3=1.333333333) • Irrational numbers - numbers that cannot be expressed as a fraction including square roots of whole n ...
Solutions to Exercises Chapter 2: On numbers and counting
... 9 Logicians define a natural number to be the set of all its predecessors: so 3 is the set {0, 1, 2}. Why do they have to start counting at 0? Suppose that we start counting at 1 instead of 0. Either we define 3 to be the set of strict predecessors of 3, in which case there are only two of them (1 a ...
... 9 Logicians define a natural number to be the set of all its predecessors: so 3 is the set {0, 1, 2}. Why do they have to start counting at 0? Suppose that we start counting at 1 instead of 0. Either we define 3 to be the set of strict predecessors of 3, in which case there are only two of them (1 a ...
Strand 1: Number and Operations
... PO 2. Analyze and compare mathematical strategies for efficient problem solving; select and use one or more strategies to solve a problem. PO 3. Identify relevant, missing, and extraneous information related to the solution to a problem. PO 4. Represent a problem situation using multiple representat ...
... PO 2. Analyze and compare mathematical strategies for efficient problem solving; select and use one or more strategies to solve a problem. PO 3. Identify relevant, missing, and extraneous information related to the solution to a problem. PO 4. Represent a problem situation using multiple representat ...
solutions - NLCS Maths Department
... Let a, b, c, d, e, f be the numbers in the squares shown. Then the sum of the numbers in the four lines is 1 + 2 + 3 + … + 9 + b + n + e since each of the numbers in the corner squares appears in exactly one row and one column. So 45 + b + n + e = 4 × 13 = 52, that is b + n + e = 7. Hence b, n, e ar ...
... Let a, b, c, d, e, f be the numbers in the squares shown. Then the sum of the numbers in the four lines is 1 + 2 + 3 + … + 9 + b + n + e since each of the numbers in the corner squares appears in exactly one row and one column. So 45 + b + n + e = 4 × 13 = 52, that is b + n + e = 7. Hence b, n, e ar ...