Math for Developers
... n! – the product of all positive integers, less than or equal to n n should be non-negative n! = (n – 1)! x n Example: 5! = 5 x 4 x 3 x 2 x 1 = 120 ...
... n! – the product of all positive integers, less than or equal to n n should be non-negative n! = (n – 1)! x n Example: 5! = 5 x 4 x 3 x 2 x 1 = 120 ...
Numbers: Fun and Challenge
... Consider a non-trivial integer solution of the equation s4 + 4t4 = u2 with gcd(s, t, u) = 1. It is easy to see that u and s are both odd. Adjusting the signs, we may assume that u > 0. Since 4t2 = (u − s2 )(u + s2 ), there exist positive integers a, b such that u − s2 = 2b2 , u + s2 = 2a2 , t2 = ab ...
... Consider a non-trivial integer solution of the equation s4 + 4t4 = u2 with gcd(s, t, u) = 1. It is easy to see that u and s are both odd. Adjusting the signs, we may assume that u > 0. Since 4t2 = (u − s2 )(u + s2 ), there exist positive integers a, b such that u − s2 = 2b2 , u + s2 = 2a2 , t2 = ab ...
YEAR 5 BLOCK A UNIT 1 (AUTUMN)
... zero, ten, twenty, …, one hundred, two hundred, …, one thousand, count in ones, twos, threes, fours, fives and so on, odd, even, pattern, sequence, continue, partition numbers compare, order, larger, greater than, smaller, less than, between, halfway between, difference between, round, nearest 10, t ...
... zero, ten, twenty, …, one hundred, two hundred, …, one thousand, count in ones, twos, threes, fours, fives and so on, odd, even, pattern, sequence, continue, partition numbers compare, order, larger, greater than, smaller, less than, between, halfway between, difference between, round, nearest 10, t ...
Full text
... All the equations (i)-(vi) involve contradictions. Of these, perhaps (ii) is the least obvious. Let us therefore examine (ii), which is true for m = 2 (even) leading to c2 = 1, cx = 2 from (ii) and (8). Now c2 = 1 = a2 - h2 implies that a2 = 2 (b2 = 1) or a2 - 1 (b2 = 0), i.e., a2 ^ 0, which contrad ...
... All the equations (i)-(vi) involve contradictions. Of these, perhaps (ii) is the least obvious. Let us therefore examine (ii), which is true for m = 2 (even) leading to c2 = 1, cx = 2 from (ii) and (8). Now c2 = 1 = a2 - h2 implies that a2 = 2 (b2 = 1) or a2 - 1 (b2 = 0), i.e., a2 ^ 0, which contrad ...
1 The Natural Numbers
... approaches the non-rational number 2, a fact well known since antiquity. We want to remedy this deficiency: we want to construct an ordered field F containing the rational numbers, which is “complete” in the following sense: (C1) Every increasing13 bounded14 sequence15 of elements in F converges16 t ...
... approaches the non-rational number 2, a fact well known since antiquity. We want to remedy this deficiency: we want to construct an ordered field F containing the rational numbers, which is “complete” in the following sense: (C1) Every increasing13 bounded14 sequence15 of elements in F converges16 t ...