Acid + Base Class # 1
... In our class we will discuss all 4 bases, sodium hydroxide, potassium hydroxide, calcium hydroxide, and ammonia. ALL aqueous ionic compound containing hydroxides are also bases, such as LiOH, RbOH, Sr(OH)2, etc. 16. Ammonia does not have hydroxides in its formula, but since it is a common and “norma ...
... In our class we will discuss all 4 bases, sodium hydroxide, potassium hydroxide, calcium hydroxide, and ammonia. ALL aqueous ionic compound containing hydroxides are also bases, such as LiOH, RbOH, Sr(OH)2, etc. 16. Ammonia does not have hydroxides in its formula, but since it is a common and “norma ...
Document
... (a) The number of protons is the atomic number of the element. A periodic table or list of elements tells us that the element with atomic number 22 is titanium (Ti). The mass number (protons plus neutrons) of this isotope of titanium is 22 + 26 = 48. Because the ion has three more protons than elect ...
... (a) The number of protons is the atomic number of the element. A periodic table or list of elements tells us that the element with atomic number 22 is titanium (Ti). The mass number (protons plus neutrons) of this isotope of titanium is 22 + 26 = 48. Because the ion has three more protons than elect ...
Document
... • In both acid–base and gas-evolution reactions, as in precipitation reactions, the reactions occur when the anion from one reactant combines with the cation of the other. – Many gas-evolution reactions are also acid– base reactions. ...
... • In both acid–base and gas-evolution reactions, as in precipitation reactions, the reactions occur when the anion from one reactant combines with the cation of the other. – Many gas-evolution reactions are also acid– base reactions. ...
Extraction lecture - UCLA Chemistry and Biochemistry
... Why do we need Extraction? • Chemical reactions usually lead to a mixture of compounds: product, byproducts, reactants and catalyst • It is one way to facilitate the isolation of the target compound – Extraction: aims at the target compound – Washing: removes impurities from the organic layer ...
... Why do we need Extraction? • Chemical reactions usually lead to a mixture of compounds: product, byproducts, reactants and catalyst • It is one way to facilitate the isolation of the target compound – Extraction: aims at the target compound – Washing: removes impurities from the organic layer ...
Practice Test 2
... What volume (in liters) of hydrogen gas at STP is released by mixing 5.34 g of iron with 5.00 mL of 1.250 M HCl? (15 pts) ...
... What volume (in liters) of hydrogen gas at STP is released by mixing 5.34 g of iron with 5.00 mL of 1.250 M HCl? (15 pts) ...
Example 1: An experiment shows that 64g of
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
Wet Chemical Etching
... H3O+ hereby reduced to hydrogen as follows: metal + H+ metal+ + H Concerning base metals, this reaction is always exothermic: Since base metals have a standard potential E0 < 0 which is smaller than the standard potential of hydrogen (arbitrarily set to zero), energy is released (DU < 0) when H+ ion ...
... H3O+ hereby reduced to hydrogen as follows: metal + H+ metal+ + H Concerning base metals, this reaction is always exothermic: Since base metals have a standard potential E0 < 0 which is smaller than the standard potential of hydrogen (arbitrarily set to zero), energy is released (DU < 0) when H+ ion ...
HONG KONG DIPLOMA OF SECONDARY EDUCATION
... Mars is the fourth planet from the Sun. Mars has a very different atmosphere from that of the Earth. The atmosphere is relatively thin with an average pressure of 0.6 kilopascals (kPa) (compared to Earth’s 101.3 kPa). It is actually less than 1% the atmospheric density of Earth. Therefore, there is ...
... Mars is the fourth planet from the Sun. Mars has a very different atmosphere from that of the Earth. The atmosphere is relatively thin with an average pressure of 0.6 kilopascals (kPa) (compared to Earth’s 101.3 kPa). It is actually less than 1% the atmospheric density of Earth. Therefore, there is ...
Chapter 4. Aqueous Reactions and Solution Stoichiometry
... • Use the stoichiometric coefficients to move between reactants and products. • This step requires the balanced chemical equation. • Convert the laboratory units back into the required units. • Convert moles to grams using molar mass. • Convert moles to molarity or volume using M = mol/L. ...
... • Use the stoichiometric coefficients to move between reactants and products. • This step requires the balanced chemical equation. • Convert the laboratory units back into the required units. • Convert moles to grams using molar mass. • Convert moles to molarity or volume using M = mol/L. ...
3 - Study Hungary
... B: 2HNO3 + Na2CO3 → 2NaNO3 + H2O + CO2 C: Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3 D: 2HNO3 + Ca(OH)2 → Ca(NO3)2 + 2H2O E: 2HNO3 + 3H2S → 2NO + 3S + 4H2O ...
... B: 2HNO3 + Na2CO3 → 2NaNO3 + H2O + CO2 C: Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3 D: 2HNO3 + Ca(OH)2 → Ca(NO3)2 + 2H2O E: 2HNO3 + 3H2S → 2NO + 3S + 4H2O ...
CP - Fundamentals
... Now Davis makes a big deal about ions not being able to form molecules. Thus, NaCl is not a molecule; it is just a simple way of describing the appropriate ratio of ions which come together to form regularly packed crystals. For example, shown in Figure 2 are ball and stick and space-filled models o ...
... Now Davis makes a big deal about ions not being able to form molecules. Thus, NaCl is not a molecule; it is just a simple way of describing the appropriate ratio of ions which come together to form regularly packed crystals. For example, shown in Figure 2 are ball and stick and space-filled models o ...
pH scale. Buffer solutions. Colligative properties of solutions
... Buffer solutions The amount of carbon dioxide in the blood is coupled to the amount present in the lungs. Second, the equilibrium between carbonic acid and bicarbonate ion: H2CO3 (aq) ↔ HCO3− (aq) + H+ (aq), pK = 6.37. These reactions lead to the presence in solution the conjugate pair HCO3−/H2CO3 ...
... Buffer solutions The amount of carbon dioxide in the blood is coupled to the amount present in the lungs. Second, the equilibrium between carbonic acid and bicarbonate ion: H2CO3 (aq) ↔ HCO3− (aq) + H+ (aq), pK = 6.37. These reactions lead to the presence in solution the conjugate pair HCO3−/H2CO3 ...
06 Salts of carboxylic acids,saturated amino acids of aliphatic series
... Proteins are essential components of all living matter. As cellular components, proteins perform numerous functions. The chemical reactions fundamental to the life of the cell are catalyzed by proteins called enzymes. Other proteins are structural constituents of protoplasm and cell membranes. Some ...
... Proteins are essential components of all living matter. As cellular components, proteins perform numerous functions. The chemical reactions fundamental to the life of the cell are catalyzed by proteins called enzymes. Other proteins are structural constituents of protoplasm and cell membranes. Some ...
Practice Problem Set #6
... 1. Write balanced chemical equations for the reaction of hydrogen gas with oxygen, chlorine, and nitrogen. 2. Write a balanced chemical equation for the preparation of H2 (and CO) by the reaction of CH4 and water. Using a table of thermodynamic data, calculate ∆H°, ∆G°, and ∆S° for this reaction. ...
... 1. Write balanced chemical equations for the reaction of hydrogen gas with oxygen, chlorine, and nitrogen. 2. Write a balanced chemical equation for the preparation of H2 (and CO) by the reaction of CH4 and water. Using a table of thermodynamic data, calculate ∆H°, ∆G°, and ∆S° for this reaction. ...
Final Review Answers
... 15)Differentiate between the properties of ionically and covalently bonded compounds. Ionic - made up of cations & anions, usually metal and nonmetal elements, High MP & BP, electrically netural cmpds, can conduct electricity in aq and molten states; Covalent - made up of nonmetals, forms stable mol ...
... 15)Differentiate between the properties of ionically and covalently bonded compounds. Ionic - made up of cations & anions, usually metal and nonmetal elements, High MP & BP, electrically netural cmpds, can conduct electricity in aq and molten states; Covalent - made up of nonmetals, forms stable mol ...
Unit 6 Chemical Equations and Reactions Balancing Equations
... Balance the following chemical equations using coefficients 1 1Al(OH)3(s) + 3HCl (aq) → 1AlCl3 (aq) + 3H2O (l) 2. 3Fe2O3 (s) + 1CO (g) → 2Fe3O4(s) + 1CO2 (g) 3. 4FeO (s) + 1O2 (g) → 2Fe2O3 (s) 4. 2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (g) 5. 3Ca(OH)2 (aq) + 2H3PO4 (aq) → 6H2O (l) + 1Ca3(PO4)2 (s) 6 ...
... Balance the following chemical equations using coefficients 1 1Al(OH)3(s) + 3HCl (aq) → 1AlCl3 (aq) + 3H2O (l) 2. 3Fe2O3 (s) + 1CO (g) → 2Fe3O4(s) + 1CO2 (g) 3. 4FeO (s) + 1O2 (g) → 2Fe2O3 (s) 4. 2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (g) 5. 3Ca(OH)2 (aq) + 2H3PO4 (aq) → 6H2O (l) + 1Ca3(PO4)2 (s) 6 ...
Example 1: An experiment shows that 64g of
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
Example 1: An experiment shows that 64g of
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
... 1. 416 g anhydrous barium chloride were obtained when 488g of the hydrated salt were heated. Calculate n in the formula BaCl2.nH2O 2. A sample of magnesium sulphate crystals weighing 0.942 g was heated to drive off the water of crystallization. When it reached constant mass, the mass of the residue ...
IGCSE Revision Guide (Double Award) | PDF
... Recall the charge on common ions – both metals and non-‐metals – and compound ions e.g. SO42-‐, CO32-‐ , NH4+ , NO3-‐ . Deduce the charge of an ion from the electronic configuration of the ...
... Recall the charge on common ions – both metals and non-‐metals – and compound ions e.g. SO42-‐, CO32-‐ , NH4+ , NO3-‐ . Deduce the charge of an ion from the electronic configuration of the ...
Bellin College Homework Supplement
... 51. Carbon material in the bones of humans and animals assimilates carbon until death. Using radiocarbon dating, the number of half-lives of carbon-14 from a bone sample determines the age of the bone. Suppose a sample is obtained from a prehistoric animal and used for radiocarbon dating. We can cal ...
... 51. Carbon material in the bones of humans and animals assimilates carbon until death. Using radiocarbon dating, the number of half-lives of carbon-14 from a bone sample determines the age of the bone. Suppose a sample is obtained from a prehistoric animal and used for radiocarbon dating. We can cal ...
5H2O → CuSO4 + 5H2O(g)
... number of -1 (except when bonded to oxygen or in polyatomic ions). 4) The sum of oxidation numbers is 0 for a neutral compound and is equal to the net charge for a polyatomic ion. ...
... number of -1 (except when bonded to oxygen or in polyatomic ions). 4) The sum of oxidation numbers is 0 for a neutral compound and is equal to the net charge for a polyatomic ion. ...
Hydroxide
Hydroxide is a diatomic anion with chemical formula OH−. It consists of an oxygen and hydrogen atom held together by a covalent bond, and carries a negative electric charge. It is an important but usually minor constituent of water. It functions as a base, a ligand, a nucleophile and a catalyst. The hydroxide ion forms salts, some of which dissociate in aqueous solution, liberating solvated hydroxide ions. Sodium hydroxide is a multi-million-ton per annum commodity chemical. A hydroxide attached to a strongly electropositive center may itself ionize, liberating a hydrogen cation (H+), making the parent compound an acid.The corresponding electrically neutral compound •HO is the hydroxyl radical. The corresponding covalently-bound group -OH of atoms is the hydroxyl group.Hydroxide ion and hydroxyl group are nucleophiles and can act as a catalyst in organic chemistry.Many inorganic substances which bear the word ""hydroxide"" in their names are not ionic compounds of the hydroxide ion, but covalent compounds which contain hydroxyl groups.