
Physics 430
... So we see that the (x, y) part of the trajectory is a circle that may be offset from our coordinate system. However, choosing our coordinate system origin to be the center of the circle, we simply have: x x iy Ceiwt Note, however, that the position at t = 0 is not zero, but rather is x (0) ...
... So we see that the (x, y) part of the trajectory is a circle that may be offset from our coordinate system. However, choosing our coordinate system origin to be the center of the circle, we simply have: x x iy Ceiwt Note, however, that the position at t = 0 is not zero, but rather is x (0) ...
Momentum - college physics
... B. The total momentum of a system is conserved when the internal forces add up to zero. C. The total momentum is conserved when there are no internal forces. D. The total momentum of a system can not be conserved it the objects are interacting. ...
... B. The total momentum of a system is conserved when the internal forces add up to zero. C. The total momentum is conserved when there are no internal forces. D. The total momentum of a system can not be conserved it the objects are interacting. ...
Back Questions on Momentum
... make the time that the force is in contact with the object as small as possible. make the time that the force is in contact with the object as large as possible. make the force causing the change perpendicular to the direction pi. make the force causing the change perpendicular to the direction pf. ...
... make the time that the force is in contact with the object as small as possible. make the time that the force is in contact with the object as large as possible. make the force causing the change perpendicular to the direction pi. make the force causing the change perpendicular to the direction pf. ...
Unit 1 content
... 2 m s-2 = m. a = 1000 x 2 = 2 000 N Total force applied accelerates tractor and car at 2 m s-2 = m. a = 6000 x 2 = 12 000 N ...
... 2 m s-2 = m. a = 1000 x 2 = 2 000 N Total force applied accelerates tractor and car at 2 m s-2 = m. a = 6000 x 2 = 12 000 N ...
Solutions - Young Engineering and Science Scholars
... The average force exerted by a bat on a baseball during the time of contact, 0.002 s, is 6600 N. The mass of a baseball is 0.145 kg and its speed is 75 mph just before the bat collides with it. (a) What is the impulse of the ball hitting the bat? Answer: Let the positive x direction be the direction ...
... The average force exerted by a bat on a baseball during the time of contact, 0.002 s, is 6600 N. The mass of a baseball is 0.145 kg and its speed is 75 mph just before the bat collides with it. (a) What is the impulse of the ball hitting the bat? Answer: Let the positive x direction be the direction ...
+ Rotational motion about its CM
... Man on rotating platform Example12: A platform is rotating about its center axis, and a man standing on it (treat as a particle) starts to move. How does change if he goes: a) to point o; b) along the edge with relative speed v. Solution: a) Conservation of angular momentum ...
... Man on rotating platform Example12: A platform is rotating about its center axis, and a man standing on it (treat as a particle) starts to move. How does change if he goes: a) to point o; b) along the edge with relative speed v. Solution: a) Conservation of angular momentum ...
Centripetal acceleration
... A space ship rotates with a linear velocity of 50 m/s. What should the distance from the central axis to the crew’s cabin’s be so that the crew feels like they are on earth? (the floor of the cabins is the inside of the outer edge of the spaceship) ...
... A space ship rotates with a linear velocity of 50 m/s. What should the distance from the central axis to the crew’s cabin’s be so that the crew feels like they are on earth? (the floor of the cabins is the inside of the outer edge of the spaceship) ...
PHYS2330 Intermediate Mechanics Fall 2009 Final Exam
... A 1 cm2 detector sits 1m away, at an angle such that the differential cross section is 10−20 cm2 per sterradian. The number of detector particles is approximately A. 10. B. 100. C. 1000. D. 10,000. E. 100,000. 2. Given two relativistic four-momenta p1 and p2 , which of the following will generally h ...
... A 1 cm2 detector sits 1m away, at an angle such that the differential cross section is 10−20 cm2 per sterradian. The number of detector particles is approximately A. 10. B. 100. C. 1000. D. 10,000. E. 100,000. 2. Given two relativistic four-momenta p1 and p2 , which of the following will generally h ...
PH212 Chapter 10 Solutions
... Jane-Vine-Tarzan system is conserved about the point at which the vine swings. Before and after that, mechanical energy is conserved. S ET U P : Take upward and at the ground. The center of mass of the vine is 4.00 m from either end. Treat the motion in three parts: (i) Jane swinging to where the vi ...
... Jane-Vine-Tarzan system is conserved about the point at which the vine swings. Before and after that, mechanical energy is conserved. S ET U P : Take upward and at the ground. The center of mass of the vine is 4.00 m from either end. Treat the motion in three parts: (i) Jane swinging to where the vi ...
uniform circular motion
... • A) Objects 1 and 2 have the same linear velocity, v, and the same angular velocity, . • B) Objects 1 and 2 have the same linear velocity, v, and the different angular velocities, . • C) Objects 1 and 2 have different linear velocities, v, and the same angular velocity, . • D) Objects 1 and 2 h ...
... • A) Objects 1 and 2 have the same linear velocity, v, and the same angular velocity, . • B) Objects 1 and 2 have the same linear velocity, v, and the different angular velocities, . • C) Objects 1 and 2 have different linear velocities, v, and the same angular velocity, . • D) Objects 1 and 2 h ...
Tuesday, June 21, 2005
... Example for Linear Momentum Conservation A type of particle, a neutral kaon (K0), decays (breaks up) into a pair of particles called pions (p+ and p-) that are oppositely charged but have equal mass. Assuming the K0 is initially produced at rest, prove that the two pions must have momenta that are ...
... Example for Linear Momentum Conservation A type of particle, a neutral kaon (K0), decays (breaks up) into a pair of particles called pions (p+ and p-) that are oppositely charged but have equal mass. Assuming the K0 is initially produced at rest, prove that the two pions must have momenta that are ...
Phys 172 Exam 1, 2010 fall, Purdue University
... top box in this situation? What objects in its surroundings is the top box interacting significantly with? The second student is correct. The worker is not interacting significantly with the top box because he is not in contact with it. The top box is interacting significantly with the Earth and wit ...
... top box in this situation? What objects in its surroundings is the top box interacting significantly with? The second student is correct. The worker is not interacting significantly with the top box because he is not in contact with it. The top box is interacting significantly with the Earth and wit ...
momentum
... pushing it to the left. At the same time, the pin exerts an equal force on the ball, pushing it to the right. CAN YOU THINK OF SOME OTHER FORCE PAIRS? ...
... pushing it to the left. At the same time, the pin exerts an equal force on the ball, pushing it to the right. CAN YOU THINK OF SOME OTHER FORCE PAIRS? ...
chapter7_PC
... Units of angular acceleration are rad/s² Positive angular accelerations are in the counterclockwise direction and negative accelerations are in the clockwise direction When a rigid object rotates about a fixed axis, every portion of the object has the same angular speed and the same angular accelera ...
... Units of angular acceleration are rad/s² Positive angular accelerations are in the counterclockwise direction and negative accelerations are in the clockwise direction When a rigid object rotates about a fixed axis, every portion of the object has the same angular speed and the same angular accelera ...
Document
... • Velocity and momentum vectors point in the same direction. • SI unit for momentum: kg·m/s (no special name). ...
... • Velocity and momentum vectors point in the same direction. • SI unit for momentum: kg·m/s (no special name). ...
Relativistic angular momentum
""Angular momentum tensor"" redirects to here.In physics, relativistic angular momentum refers to the mathematical formalisms and physical concepts that define angular momentum in special relativity (SR) and general relativity (GR). The relativistic quantity is subtly different from the three-dimensional quantity in classical mechanics.Angular momentum is a dynamical quantity derived from position and momentum, and is important; angular momentum is a measure of an object's ""amount of rotational motion"" and resistance to stop rotating. Also, in the same way momentum conservation corresponds to translational symmetry, angular momentum conservation corresponds to rotational symmetry – the connection between symmetries and conservation laws is made by Noether's theorem. While these concepts were originally discovered in classical mechanics – they are also true and significant in special and general relativity. In terms of abstract algebra; the invariance of angular momentum, four-momentum, and other symmetries in spacetime, are described by the Poincaré group and Lorentz group.Physical quantities which remain separate in classical physics are naturally combined in SR and GR by enforcing the postulates of relativity, an appealing characteristic. Most notably; space and time coordinates combine into the four-position, and energy and momentum combine into the four-momentum. These four-vectors depend on the frame of reference used, and change under Lorentz transformations to other inertial frames or accelerated frames.Relativistic angular momentum is less obvious. The classical definition of angular momentum is the cross product of position x with momentum p to obtain a pseudovector x×p, or alternatively as the exterior product to obtain a second order antisymmetric tensor x∧p. What does this combine with, if anything? There is another vector quantity not often discussed – it is the time-varying moment of mass (not the moment of inertia) related to the boost of the centre of mass of the system, and this combines with the classical angular momentum to form an antisymmetric tensor of second order. For rotating mass–energy distributions (such as gyroscopes, planets, stars, and black holes) instead of point-like particles, the angular momentum tensor is expressed in terms of the stress–energy tensor of the rotating object.In special relativity alone, in the rest frame of a spinning object; there is an intrinsic angular momentum analogous to the ""spin"" in quantum mechanics and relativistic quantum mechanics, although for an extended body rather than a point particle. In relativistic quantum mechanics, elementary particles have spin and this is an additional contribution to the orbital angular momentum operator, yielding the total angular momentum tensor operator. In any case, the intrinsic ""spin"" addition to the orbital angular momentum of an object can be expressed in terms of the Pauli–Lubanski pseudovector.