
Question
... • However, heavier object will require more energy to escape! • Vescape= 40,000 km/hr = 11 km/sec from the surface of the Earth. Click image to start movie ...
... • However, heavier object will require more energy to escape! • Vescape= 40,000 km/hr = 11 km/sec from the surface of the Earth. Click image to start movie ...
gravitational fields
... • However, heavier object will require more energy to escape! • Vescape= 40,000 km/hr = 11 km/sec from the surface of the Earth. Click image to start movie ...
... • However, heavier object will require more energy to escape! • Vescape= 40,000 km/hr = 11 km/sec from the surface of the Earth. Click image to start movie ...
Rotational Dynamics - Piri Reis Üniversitesi
... • The rotational inertia depends not only on the mass of an object but also on the way its mass is distributed around the axis of rotation. • The angular acceleration is proportional to the torque and inversely proportional to the rotational inertia. •An object that is rotating has rotational kineti ...
... • The rotational inertia depends not only on the mass of an object but also on the way its mass is distributed around the axis of rotation. • The angular acceleration is proportional to the torque and inversely proportional to the rotational inertia. •An object that is rotating has rotational kineti ...
1 PHYSICS 231 Lecture 12: Keeping momentum
... The football player A football player throws a ball with an initial velocity of 40 m/s and an angle of 40o with respect to the field. At what distance from the player will the ball hit the field? Assume that the player’s length is negligible (i.e. the ball is thrown from a vertical height of 0.0 m) ...
... The football player A football player throws a ball with an initial velocity of 40 m/s and an angle of 40o with respect to the field. At what distance from the player will the ball hit the field? Assume that the player’s length is negligible (i.e. the ball is thrown from a vertical height of 0.0 m) ...
File - Mr. Dorsey: Physics
... The cat, mass of 4 kg sits 2 m from the center of rotation. Where should a boy of mass 50 kg sit to balance the system Solve: τcat = (2 m)(4 kg)(9.8 N/kg) = + 78.4 N-m τboy = (d)(50 kg)(9.8 N/kg) = - 490 d For rotational equilibrium, the net torque = zero. ...
... The cat, mass of 4 kg sits 2 m from the center of rotation. Where should a boy of mass 50 kg sit to balance the system Solve: τcat = (2 m)(4 kg)(9.8 N/kg) = + 78.4 N-m τboy = (d)(50 kg)(9.8 N/kg) = - 490 d For rotational equilibrium, the net torque = zero. ...
Vectors, Vector Components, and Vector Addition
... with in the 1st or 4th quadrant. Try this: (1) Use your calculator to take the tangent of 225°. (2) Now take the inverse tangent of your result. Your calculator should say 45°. The reason for this is there are actually an infinite number of solutions for θ to the equation tanθ = 1. In degrees, they ...
... with in the 1st or 4th quadrant. Try this: (1) Use your calculator to take the tangent of 225°. (2) Now take the inverse tangent of your result. Your calculator should say 45°. The reason for this is there are actually an infinite number of solutions for θ to the equation tanθ = 1. In degrees, they ...
PHYS2330 Intermediate Mechanics Quiz 13 Sept 2010
... 1. A particle of mass m moves in one dimension subject to a force F (t) = F0 e−bt . If the particle velocity is v0 at time t = 0, what is the velocity v(t) as a function of time? A. v(t) = v0 e−bt B. v(t) = (v0 /bm)e−bt C. v(t) = (F0 /bm)e−bt + v0 D. v(t) = (v0 /bm)(1 − e−bt ) E. v(t) = (F0 /bm)(1 − ...
... 1. A particle of mass m moves in one dimension subject to a force F (t) = F0 e−bt . If the particle velocity is v0 at time t = 0, what is the velocity v(t) as a function of time? A. v(t) = v0 e−bt B. v(t) = (v0 /bm)e−bt C. v(t) = (F0 /bm)e−bt + v0 D. v(t) = (v0 /bm)(1 − e−bt ) E. v(t) = (F0 /bm)(1 − ...
Relativistic angular momentum
""Angular momentum tensor"" redirects to here.In physics, relativistic angular momentum refers to the mathematical formalisms and physical concepts that define angular momentum in special relativity (SR) and general relativity (GR). The relativistic quantity is subtly different from the three-dimensional quantity in classical mechanics.Angular momentum is a dynamical quantity derived from position and momentum, and is important; angular momentum is a measure of an object's ""amount of rotational motion"" and resistance to stop rotating. Also, in the same way momentum conservation corresponds to translational symmetry, angular momentum conservation corresponds to rotational symmetry – the connection between symmetries and conservation laws is made by Noether's theorem. While these concepts were originally discovered in classical mechanics – they are also true and significant in special and general relativity. In terms of abstract algebra; the invariance of angular momentum, four-momentum, and other symmetries in spacetime, are described by the Poincaré group and Lorentz group.Physical quantities which remain separate in classical physics are naturally combined in SR and GR by enforcing the postulates of relativity, an appealing characteristic. Most notably; space and time coordinates combine into the four-position, and energy and momentum combine into the four-momentum. These four-vectors depend on the frame of reference used, and change under Lorentz transformations to other inertial frames or accelerated frames.Relativistic angular momentum is less obvious. The classical definition of angular momentum is the cross product of position x with momentum p to obtain a pseudovector x×p, or alternatively as the exterior product to obtain a second order antisymmetric tensor x∧p. What does this combine with, if anything? There is another vector quantity not often discussed – it is the time-varying moment of mass (not the moment of inertia) related to the boost of the centre of mass of the system, and this combines with the classical angular momentum to form an antisymmetric tensor of second order. For rotating mass–energy distributions (such as gyroscopes, planets, stars, and black holes) instead of point-like particles, the angular momentum tensor is expressed in terms of the stress–energy tensor of the rotating object.In special relativity alone, in the rest frame of a spinning object; there is an intrinsic angular momentum analogous to the ""spin"" in quantum mechanics and relativistic quantum mechanics, although for an extended body rather than a point particle. In relativistic quantum mechanics, elementary particles have spin and this is an additional contribution to the orbital angular momentum operator, yielding the total angular momentum tensor operator. In any case, the intrinsic ""spin"" addition to the orbital angular momentum of an object can be expressed in terms of the Pauli–Lubanski pseudovector.