104 Homework Packet - Rogue Community College
... According to Le Chatelier’s Principle, adding reactants (or removing products) drives the equilibrium to the __________, adding products (or removing reactants) drives the equilibrium to the __________, increasing temperature favors the ___________________ reaction, decreasing temperature favors the ...
... According to Le Chatelier’s Principle, adding reactants (or removing products) drives the equilibrium to the __________, adding products (or removing reactants) drives the equilibrium to the __________, increasing temperature favors the ___________________ reaction, decreasing temperature favors the ...
Thursday, March 27, 2008
... A 100.00-gram sample of naturally occurring boron contains 19.78 grams of boron-10 (atomic mass = 10.01 atomic mass units) and 80.22 grams of boron-11 (atomic mass = 11.01 atomic mass units). Which numerical setup can be used to determine the atomic mass of naturally occurring boron? ...
... A 100.00-gram sample of naturally occurring boron contains 19.78 grams of boron-10 (atomic mass = 10.01 atomic mass units) and 80.22 grams of boron-11 (atomic mass = 11.01 atomic mass units). Which numerical setup can be used to determine the atomic mass of naturally occurring boron? ...
Chapter 10 - Chemical Reactions
... However, you should be familiar with the rules which describe balanced chemical reactions. 1. Number of Atoms of each element conserved in reactants and products 2. Cannot change formula of reactants or products 3. Can only change coefficients to balance equation Hints to help in balancing equations ...
... However, you should be familiar with the rules which describe balanced chemical reactions. 1. Number of Atoms of each element conserved in reactants and products 2. Cannot change formula of reactants or products 3. Can only change coefficients to balance equation Hints to help in balancing equations ...
Types of Chemical Reactions
... The ability of one metal to displace another depends on their relative ease of oxidation—a more active metal (one that is more easily oxidized) displaces a less active metal. In the first reaction above, lead is more active than copper. The relative activities of metals can be tabulated in an activi ...
... The ability of one metal to displace another depends on their relative ease of oxidation—a more active metal (one that is more easily oxidized) displaces a less active metal. In the first reaction above, lead is more active than copper. The relative activities of metals can be tabulated in an activi ...
Avogadro`s Law is relation between
... 3- Given the same number of moles of two gases at STP conditions, how do the volumes of two gases compare? How do the masses of the two gas samples compare? 4- How many moles of helium are contained in each volume at STP: (a) 5.0 L; (b) 11.2 L; (c) 50.0 mL? 5- How many moles of argon are contained i ...
... 3- Given the same number of moles of two gases at STP conditions, how do the volumes of two gases compare? How do the masses of the two gas samples compare? 4- How many moles of helium are contained in each volume at STP: (a) 5.0 L; (b) 11.2 L; (c) 50.0 mL? 5- How many moles of argon are contained i ...
1442 Final Review
... 35. What is the best definition of a Brønsted-Lowry base? a) electron-pair acceptor b) electron-pair donor *c) proton acceptor d) proton donor e) produces hydroxide ions in aqueous solutions 36. If the concentration of hydroxide ion in a certain solution is 5.8 x 10-3 M, what is the pH of the soluti ...
... 35. What is the best definition of a Brønsted-Lowry base? a) electron-pair acceptor b) electron-pair donor *c) proton acceptor d) proton donor e) produces hydroxide ions in aqueous solutions 36. If the concentration of hydroxide ion in a certain solution is 5.8 x 10-3 M, what is the pH of the soluti ...
Corrections to Noggle, Physical Chemistry, 3rd Edition, 1st Printing
... the necessary information to inform the reader of what variable is held constant. A similar problem is seen in the last line of this example. The correct answer to part b should read: “Because ( RT ) / T P R and ( RP ) / P T R , RTdP RPdT is an exact differential.” Note that, in each c ...
... the necessary information to inform the reader of what variable is held constant. A similar problem is seen in the last line of this example. The correct answer to part b should read: “Because ( RT ) / T P R and ( RP ) / P T R , RTdP RPdT is an exact differential.” Note that, in each c ...
Chemistry Chapter 12
... of the substances in the compound -can use this mole relationship to go from one substance to another -for this calculation it makes no difference if you are working with reactants or products -when the phrase "an excess of" is used in the wording of the problem, this simply means that not all of th ...
... of the substances in the compound -can use this mole relationship to go from one substance to another -for this calculation it makes no difference if you are working with reactants or products -when the phrase "an excess of" is used in the wording of the problem, this simply means that not all of th ...
CO 2 (g)
... chemical reactions are conducted • If the mass and specific heat of the solvent (water) is known, q can be calculated if ΔT of the water is measured • qsoln = - qrxn and qrxn = - qsoln ...
... chemical reactions are conducted • If the mass and specific heat of the solvent (water) is known, q can be calculated if ΔT of the water is measured • qsoln = - qrxn and qrxn = - qsoln ...
Unit Powerpoint
... does the potential energies of the molecules. Chemists therefore consider the total energy of the system when calculating these energy changes. Chemists define the total internal energy of a system at constant pressure as Enthalpy . Enthalpy is given the symbol H. Chemists have no method of measurin ...
... does the potential energies of the molecules. Chemists therefore consider the total energy of the system when calculating these energy changes. Chemists define the total internal energy of a system at constant pressure as Enthalpy . Enthalpy is given the symbol H. Chemists have no method of measurin ...
Chapter 3
... Theoretical Yield • The theoretical yield is the maximum amount of product that can be made. – In other words, it’s the amount of product possible as calculated through the stoichiometry problem. • This is different from the actual yield, which is the amount one actually produces and measures. ...
... Theoretical Yield • The theoretical yield is the maximum amount of product that can be made. – In other words, it’s the amount of product possible as calculated through the stoichiometry problem. • This is different from the actual yield, which is the amount one actually produces and measures. ...
Transition state theory
Transition state theory (TST) explains the reaction rates of elementary chemical reactions. The theory assumes a special type of chemical equilibrium (quasi-equilibrium) between reactants and activated transition state complexes.TST is used primarily to understand qualitatively how chemical reactions take place. TST has been less successful in its original goal of calculating absolute reaction rate constants because the calculation of absolute reaction rates requires precise knowledge of potential energy surfaces, but it has been successful in calculating the standard enthalpy of activation (Δ‡Hɵ), the standard entropy of activation (Δ‡Sɵ), and the standard Gibbs energy of activation (Δ‡Gɵ) for a particular reaction if its rate constant has been experimentally determined. (The ‡ notation refers to the value of interest at the transition state.)This theory was developed simultaneously in 1935 by Henry Eyring, then at Princeton University, and by Meredith Gwynne Evans and Michael Polanyi of the University of Manchester. TST is also referred to as ""activated-complex theory,"" ""absolute-rate theory,"" and ""theory of absolute reaction rates.""Before the development of TST, the Arrhenius rate law was widely used to determine energies for the reaction barrier. The Arrhenius equation derives from empirical observations and ignores any mechanistic considerations, such as whether one or more reactive intermediates are involved in the conversion of a reactant to a product. Therefore, further development was necessary to understand the two parameters associated with this law, the pre-exponential factor (A) and the activation energy (Ea). TST, which led to the Eyring equation, successfully addresses these two issues; however, 46 years elapsed between the publication of the Arrhenius rate law, in 1889, and the Eyring equation derived from TST, in 1935. During that period, many scientists and researchers contributed significantly to the development of the theory.