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					Chapter 1 Equations and Inequalities 1.1 Linear Equations Definition 1 An equation in one variable is a statement in which two expressions, at least one containing the variable, are equal. Example 1 Solve the equation 3x  5  4. Definition 2 A linear equation in one variable is an equation that can be written in the form ax  b  0 , where a and b are real numbers and a ≠ 0. Remark A linear equation is also called a first-degree equation. Solving Linear Equations in One Variable (1) Clear fractions: Multiply on both sides by the LCD to clear the equations of fractions if they occur. (2) Remove parentheses: Use the distributive property to remove parentheses if they occur. (3) Simplify: Simplify each side of the equation by combining like terms. (4) Isolate the variable: Get all variable terms on one side and all numbers on the other side by using the addition property of equality. (5) Solve: Get the variable alone by using the multiplication property of equality. Example 2 Solve the equation 3(2x – 4) = 7 – (x + 5). Example 3 Solve the equation 1 1 ( x  5)  4  (2 x  1). 2 3 1 Example 4 Solve the equation (2 y  1)( y  1)  ( y  5)( 2 y  5). Example 5 Solve the equation 3 1 7   . x  2 x  1 ( x  1)( x  2) Example 6 Solve the equation 3x 3 2 . x 1 x 1 2 Solving for a Specified Variable All other letters are considered as numbers. Example 7 Solve PV = nRT for T. Example 8 Solve C  5 ( F  32) for F. 9 Steps for Setting Up Applied Problems (1) Read the problem carefully and identify what you are looking for. (2) Assign a letter (variable) to represent what you are looking for, and, if necessary, express any remaining unknown quantities in terms of this variable. (3) Make a list of all the known facts, and translate them into mathematical expressions. Set up the equation. (4) Solve the equation for the variable, and then answer the question, usually using a complete sentence. (5) Check the answer with the facts in the problem. Example 9 A total of $18,000 is invested, some in stocks and some in bonds, if the amount invested in bonds is half that invested in stocks, how much is invested in each category? 3 Example 10 Shannon grossed $435 one week by working 52 hours. Her employer pays time-and-a-half for all hours worked in excess of 40 hours. With this information, can you determine Shannon’s regular hourly wage? 1.2Quadratic Equations Definition 1 A quadratic equation is an equation which can be written in the form ax 2  bx  c  0 , where a, b and c are real numbers and a ≠ 0. Remark A quadratic equation written in the form of ax 2  bx  c  0 is said to be in standard form. Remark A quadratic equation is also called a second-degree equation. Solving Quadratic Equations 1) Solving a Quadratic Equation by Factoring Zero-product Property If ab  0 , then a=0 or b=0. Example 1 Solve x 2  6 x  0. 4 Example 2 Solve 2 x 2  x  3. Remark When the left side factors into two linear equations with the same solution, the quadratic equation is said to have a repeated solution. We also call this solution a root of multiplicity 2, or a double root. Example 3 Solve x 2  6 x  9  0. 2) The Square Root Method If x 2  p and p  0 , then x  Example 4 Solve (a) x 2  5 p or x   p . (b) ( x  2) 2  16 3) Complete square Procedure for completing a square Start Add m x 2  mx ( )2 2 Result m m x 2  mx  ( ) 2  ( x  ) 2 2 2 5 Example 5 Determine the number that must be added to each expression to complete the square. Then factor the resulted expression. (1) x 2  8 x (2) x 2  20 x Example 6 Solve by completing the square. (1) x 2  5 x  4  0 (2) 2 x 2  8 x  5  0 4) The Quadratic Formula For ax 2  bx  c  0 , a  0 , we have the quadratic formula b 2  4ac (1) If (2) If (3) If  b  b 2  4ac . x 2a is called the discriminant of the quadratic equation. b 2  4ac  0 , there are two unequal real solutions. b 2  4ac  0 , there is a repeated solution, a root of multiplicity 2. b 2  4ac  0 , there is no solution. 6 Example 7 Solve 3x 2  5 x  1  0 Example 8 Solve 25 2 x  30 x  18  0. 2 Example 9 Solve 3x 2  2  4 x 7 Example 10 Solve 9  3 2   0, x  0 x x2 1.4 Radical Equations; Equations Quadratic in Form; Factorable Equations Definition 1 When the variable in an equation occurs in a radical (square root, cube root, and so on), the equation is called a radical equation. To solve a radical equation, (1) Isolate the most complicated radical on one side of the equation. (2) Eliminate it by raising each side to a power equal to the index of the radical. (3) We need to check all answers when working with radical equations. Example 1 Solve 3 2 x  4  2  0. 8 Example 2 Solve x  1  x  7. Example 3 Solve 2 x  3  x  2  2. Definition 2 If an appropriate substitution u transforms an equation in the form au 2  bu  c  0, u ≠ 0 then the original equation is called an equation quadratic in form. 9 Example 4 Solve ( x  2) 2  11( x  2)  12  0. Example 5 Solve x 6  9 x 3  8  0. 10 Example 6 Solve 3  2 x  x. Factorable Equations Example 7 Solve x 4  4 x 2 . Example 8 Solve x 3  x 2  4 x  4  0. 11 1.5 Solving Inequalities Intervals INTERVAL Open interval (a, b) Closed interval [a, b] Half-open interval [a, b) Half-open interval (a, b] Interval [a, ) Interval (a, ) Interval (, a] Interval ( , a ) Interval (, ) INEQUALITY GRAPH Example 1 Write each inequality using interval notation. (a) 1  x  3 , (b)  4  x  0 , (c) x  5 , (d) x  1 Example 2 Write each interval as an inequality involving x (a) [1,4), (b) (2,  ), (c) [2,3], (d) (- ,3 ) Properties of Inequalities  Nonnegative Property: a 2  0 .  Addition Property for Inequalities: If a < b, then a + c < b + c. If a > b, then a + c > b + c.  Multiplication Properties for Inequalities: If a < b and if c > 0, then ac < bc. If a > b and if c > 0, then ac > bc. If a < b and if c < 0, then ac > bc. If a > b and if c < 0, then ac < bc. 12  Reciprocal Properties: 1 0. a 1 If a  0 , then  0 . a If a  0 , then Example 3 (a) If x  5 , then (b) If x  2 , then Example 4 (a) If 2x  6 , then (b) If x  12 , then 3 (c) If  4x  8 , then Solving Inequalities Example 5 Solve the inequality 3  2x  5 . Example 6 Solve the inequality 4x  7  2x  3 . Solving Combined Inequalities (1) Keep the variable in the middle. (2) Work with all three expressions at the same time. 13 Example 7 Solve the inequality  5  3x  2  1 . Example 8 Solve the inequality  1  3  5x 9. 2 Example 9 Solve the inequality (4 x  1) 1  0 . Example 10 If  1  x  4 , find a and b so that a  2x  1  b . 14 1.6 Equations and Inequalities Involving Absolute Value Equations Involving Absolute Value If a is a positive real number and if u is an algebraic expression, then |u| = a is equivalent to u = a, or u = -a. Example 1 Solve the equation x  4  13 . Example 2 Solve the equation 2 x  3  2  7. Example 3 Solve the equation x 2  x  1  1 . Inequalities Involving Absolute Value (I) If a is a positive real number and if u is an algebraic expression, then |u| < a is equivalent to -a <u < a |u|  a is equivalent to -a  u  a 15 Example 4 Solve the inequality 2 x  4  3 . Example 5 Solve the inequality 1  4 x  1  6 . Inequalities Involving Absolute Value (II) If a is a positive real number and if u is an algebraic expression, then |u| > a is equivalent to u < -a or u > a |u| ≥ a is equivalent to u  -a or u ≥ a Example 6 Solve the inequality 2 x  5  3 . Example 7 Solve the inequality x  3  1  1 . 16 1.7 Applications: Interest, Mixture, Uniform Motion, Constant Rate Jobs 1) Solve Interest Problems Simple Interest Formula If a principal of P dollars is borrowed for a period of t years at a per annum interest rate r, expressed as a decimal, the interest I charged is I = Prt. Example 1 Candy has $70,000 to invest and requires an overall rate of return of 9%. She can invest in a safe, government-insured certificate of deposit, but it only pays 8%. To obtain 9%, she agrees to invest some of her money in noninsured corporate bonds paying 12%. How much should be placed in each investment to achieve her goal? 2) Solve Mixture Problems Example 2 The manager of a Starbucks store decides to experiment with a new blend of coffee. She will mix some B grade coffee that sells for $5 per pound with some A grade coffee that sells for $10 per pound to get 100 pounds of the new blend. The selling price of the new blend is to be $7 per pound, and there is no difference in revenue from selling the new blend versus selling the other types. How many pounds of the B grade and A grade coffees are required? 17 3) Solve Uniform Motion Problems Uniform Motion Formula If an object moves at an average velocity v, the distance s covered in time t is given by S = vt. That is, Distance = Velocity ∙ Time Example 3 Tanya, who is a long-distance runner, runs at an average velocity of 8 miles per hour (mi/hr). Two hours after Tanya leaves your house, you leave in your Honda and follow the same route. If your average velocity is 40mi/hr, how long will it be before you catch up to Tanya? How far will each of you be from your home? 4) Solve Constant Rate Job Problems If a job can be done in t units of time, 1 of the job is done in 1 unit of time. t Example 4 One computer can do a job twice as fast as another. Working together, both computers can do the job in 2 hours. How long would it take each computer, working alone, to do the job? 18
 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
									 
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                             
                                            