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Identity & Inverse Matrices Identity What does “identity” mean to you? What is the multiplicative identity for the real numbers? In other words, 5 * __= 5? The identity for multiplication is 1 because anything multiplied by 1 will be itself. Inverses What does “inverse” mean to you? What is the inverse of multiplication? What do we multiply by to get the identity? In other words, 5 * ___=1? a * -1 a = 1 Any number multiplied by its inverse will be the identity. Identity Matrix The multiplicative identity for matrices is a square matrix with ones on the main diagonal and zeros everywhere else. 1 0 I   0 1  1 0 0   I  0 1 0  0 0 1 Identity Matrix Just like 5*1 = 5… AI= A 2 1  8 IA= A  3 1 0  2       17  0 1  1     8  3  17   Or 1 0  2  3  2  3     0 1 1 17  1 17    8     8 Identity Matrix Any matrix multiplied by its inverse will be the identity matrix. A * -1 A -1 A = I *A = I 2x2 Identity Matrix 1 0 I   0 1  3x3 Identity Matrix 1 0 0   I  0 1 0  0 0 1 Ex. 1 Determine whether A and B are inverses.  2  1  2 3 A 2 B   1 3 6     3 YES Ex. 2 Determine whether A and B are inverses.  4 3  5  3 B A    7 5  7 4  NO The Inverse of a 2x2 Matrix a b  A  c d  -1 A = 1 A If ad-cd=0, then the matrix has no inverse!!!!  d b   c a    1  d b     ad  bc  c a  As long as ad-cb =0 Ex. 3 Find A-1, if it exists.  2 3 A  5 7  -1 A = 1  7  3   14  15  5 2   7 3  A    5  2 1 Ex. 4 Find A-1, if it exists. 2 1 A   4 0 -1 A = 1   0 0  1    1  4     1  4  4 2  1   2  Ex. 5 Find A-1, if it exists. 3 4    A   2  6 1 0  Does not exist, because it’s not square. Now let’s learn how to use our calculator!!! Find the inverse!  2 3 A  5 7  2 1 A   4 0 Yes, now you can add, subtract, multiply, and find the determinant in you calculator!!  Solving Systems using Matrices and Inverses Solving Matrix Equations Suppose ax = b How do you solve for x? We cannot divide matrices, but we can multiply by the inverse. A-1 AX =A-1 B IX = A-1B X = A-1B Solving a Matrix Equation Solve the matrix equation AX=B for the 2x2 matrix X  4  1  8  5 X   3 1   6 3      X = A-1B  2  2 X    0  3 Ex. Solve  3 4  3 8  X   5  7  2  2      29  48 X     21  34 Solving Systems Using Inverse Matrices 5x  2 y  3 4x  2 y  4 Setting Up the Matrices • Matrix A will be the coefficients of the system • Matrix X will be the variables • Matrix B will be constants (what the system of equations are equal to) Matrix Equation A linear system can be written as a matrix equation AX=B 5  4  x  8 1 2   y   6      Constant Coefficient matrix Variable matrix matrix 5x  4 y  8 1x  2 y  6 Example 1 5x  4 y  8 1x  2 y  6 5  4  x  8 1 2   y   6      Example 2: Use matrices to solve the linear system 5x  2 y  3 4x  2 y  4 5 2  x  4 2  y       3 4   Type in [A]-1 [B] Find the inverse  1 1 3  x     5    y     2  4  2 (-1, 4) Example 3: Use matrices to solve the linear system 4x  2 y  8 x  2 y  12  4 2  x   8  1 2   y   12      Type in [A]-1 [B] Find the inverse  x   .2 .2  8   y    .1 .4  12      (4, 4) Example 4: Use matrices to solve the linear system x  y  2z  3 2 x  y  3z  4 4 x  3 y  z  18 2  x  3  1 1 2  1 3   y     4       4  3  1  z   18 Type in [A]-1 [B] (-2, 3, 1) Example 5: Use matrices to solve the linear system 2x  z  2 5x  y  z  5 x  2 y  2z  0  2 0 1   x   2  5 1 1   y   5        1 2 2  z  0  Type in [A]-1 [B] (2, 3, -2) Let’s apply this… You have $18 to spend for lunch during a 5 day school week. It costs you $1.50 to make lunch at home and $5 to buy lunch. How many times each week do you make a lunch at home? x y 5 1.5 x  5 y  18 (2, 3)  1 1  x   5  1.5 5  y   18      Type in [A]-1 [B] You make lunch at home 2 times a week. A word problem…!! • A small corporation borrowed $1,500,000 to expand its product line. Some of the money was borrowed at 8%, some at 9% and some at 12%. How much was borrowed at each rate if the annual interest was $133,000 and the amount borrowed at 8% was 4 times the amount borrowed at 12%? $800,000 at 8% $500,000 at 9% $200,000 at 12% Homework