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DIVISIVILITY By:
0, 2, 4, 6, 8, 10, 12, . .
Examples:
20
2976
58
458
10000
If the sum of the digits is divisible by 3
129: 1 + 2 + 9 = 12
12 is divisible by 3
129 is divisible by 3
456
15400
2975
580
10000
168
432
Multiply the last two digits by 2, then
subtract the product from the remaining
digits. Repeat if necessarily. If the
remainder is divisible by 7, the number
is divisible by 7.
84
3206
682
3206
682
68
320
4
- 12
64 ÷ 7 = 9 R1
So, 682 is not divisible by 7.
308
-16
14÷7 = 2 Therefore 3206 is divisible by 7.
1,192
14,000
297
5805
5805
3213
5 + 8 + 0 + 5 = 18
Since 18 is divisible by 9, 5805 id divisible by 9.
2150
580
10000
81917
8 + 9 + 7 =24
1+ 1 = 2
Divisible by 11
24 – 2 =22:
The GCF of two or more numbers is the biggest number
by which each of the given numbers can be divided.
The LCM of two or more numbers is the smallest number
that is divisible by each of the given numbers
GCF = 4
12 = 12 ÷ 4 = 3
20 ÷ 4
20
5
GCF = 12
24 = 24 ÷ 12 = 2
5
60 ÷ 12
60
3
6
36 = 3
48
4
8
4
Or just divide numerator and denominator by common
factor(s) until they have no more common factor
GCF
12 = 3 × 4
5× 4
20
= 4
3
=
5
GCF = 12
24 = 2 × 12 = 2
5 × 12
60
5
12
3
=
20
5
24 =
60
12 =
30
6 = 2
5
15
13
5
13 ÷ 5 = 2 r.3
13
3
= 2
5
5
3
2
5
1. Multiply the whole number part of the mixed
number by the denominator of the fractional part.
2
8 3
5
5 x 8 +3 = 40 + 3 = 43
8 3 = 43
5
5
3
1
4
8
2
3
77
7
8
72
9
11
Since 3 < 8,
Since 77 > 72,
1<2
4 3
7 > 9
8
11
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Php
Or 75, 000 x .18 x 1.5 = Php 20, 250
Php
+ √4 + √4
S + S + S/2 + S/2 =36
S
S
S
S/2
3S = 36
S = 12 cm, the length
of the square
, the area of the square
Liters
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