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Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Reteaching 7-1 Introduction to Geometry Pairs of Angles • Vertical angles are pairs of opposite angles formed by two intersecting lines. They are congruent. Example 1: < 1 and < 3, < 4 and < 2 • Adjacent angles have a common vertex and a common side, but no common interior points. Example 2: < 1 and < 2, < 1 and < 4 • Two angles who sum to 180° are supplementary. Example 3: < 1 and < 4 are supplementary angles. < 3 is also a supplement of <4. * If you know the measure of one supplementary angle, you can find the measure of the other. * If m < 4 is 120°, then m < 1 is 180° – 120°, or 60°. • Two angles who sum to 90° are complementary. Example 4: < 5 and < 6 are complementary angles. < 6 is a complement of < 5. *If you know the measure of one complementary angle, you can find the measure of the other.* If m < 5 is 30°, then m < 6 is 90° – 30°, or 60°. Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Reteaching 7-2 Introduction to Geometry Angles and Parallel Lines Look at the figure at the right. • suur suur suur suur Line AB is parallel to line CD (AB P CD ) • suur Line EF is a transversal. Alternate interior angles lie within a pair of lines and on opposite sides of the transversal. Example 1: < 3 and < 5, < 4 and < 6. Alternate interior angles are congruent. If m < 4 is 60°, then m < 6 is also 60°. Corresponding angles lie on the same side of the transversal and in corresponding positions. Example 2: < 1 and < 5, < 3 and < 7. Corresponding angles are congruent. If m < 1 is 120°, then m < 5 is also 120°. Supplementary angles are any two angles that sum to 180°. Example 3: < 1 and < 2, < 3 and < 8. If m < 1 is 120°, then its supplement (m < 2 ) is 180 – 120 = 60°. Complimentary angles are any two angles that sum to 90°. If m < 2 is 60°, then its compliment is 90 – 60 = 30°. Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Reteaching 7-3 Introduction to Geometry Congruent Figures Congruence statements reveal corresponding parts. Example 1 AB corresponds to DE . < C corresponds to < F. Corresponding parts are congruent ( ≅ ). Example 2: AB ≅ DE < C ≅ < F ΔABC ≅ ΔDEF Triangles are congruent if you can show just three parts are congruent. Side-Side-Side (SSS) (The marks show which parts are congruent.) Side-Angle-Side (SAS) (The arcs show which angels are congruent.) Angle-Side-Angle (ASA) Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Introduction to Geometry Reteaching 7-4 Similar Figures Similar polygons have congruent corresponding angles and corresponding sides that are in proportion. The symbol ~ means is similar to. Example: Is parallelogram ABCD ~ parallelogram KLMN? 1 Check corresponding angles. < A ≅ < K, < B ≅ < L, < C ≅ < M, and < D ≅ < N 2 Compare corresponding sides. AB 8 2 BC 12 2 = = = = KL 4 1 LM 6 1 CD 8 2 DA 12 2 = = = = MN 4 1 NK 6 1 Corresponding angles are congruent. Corresponding sides are in proportion. The parallelograms are similar. You can use proportions to find unknown lengths in similar figures. 1 To find EF, use a proportion. 2 Substitute. 3 Use cross products. 4 Solve. EF = 5 AB BC = DE EF 12 10 = 6 n 12n = 60 n=5 ΔABC ∼ ΔDEF Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Reteaching 7-5 Introduction to Geometry Proving Triangles Similar The angles of a triangle add to 180°. You can use the angle sum to find a missing angle measure. m∠Q + m∠R + m∠S = 180o o o o 46 + m∠R + 46 = 180 92o + m∠R = 180o 92o − 92o + m∠R = 180o − 92o m∠R = 88o ß Angle sum. ß Substitute. ß Simplify. ß Subtract. ß Simplify. You can also use angle measures to show that two triangles are similar. Step 1: Use the angle sum to find m < L. 90o + 58o + m∠L = 180o 148o + m∠L = 180o 148o −148o + m∠L = 180o −148o m∠L = 32o Step 2: Use AA similarity. m∠K ≅ m∠D m∠L ≅ m∠D ΔKLM ∼ ΔDEF Name _______________________________ Period ____________ Date __________________ Ch. 7 Review Packet Reteaching 7-6 Introduction to Geometry Angles and Polygons For a polygon with n sides, the sum of the measures of the interior angles is (n – 2)180°. Example 1: A quadrilateral is a 4-sided polygon. The sum of the angle measures is: (4 − 2) ×180 o = 2 ×180o = 360° m < 1 + m < 2 + m < 3 + m < 4= 360° Example 2: A heptagon has 7 sides. (n − 2)180o (7 − 2)180o 5 × 180o = 900o The sum of the measures of the interior angles of a heptagon is 900°. ** You can divide by the number of interior angles to find the measure of each angle for a REGULAR polygon. 900o ÷ 7 = 128.6o Each angle in a regular heptagon has a measure of 128.6°. An exterior angle of a polygon is an angle formed by a side and an extension of an adjacent side. The measure of an exterior angle of a triangle is equal to the sum of the measures of the interior angles at the other two vertices. m∠2 = m∠A + m∠B = 60o + 90o = 150o ß Exterior angle of triangle ß Substitute ¬Simplify