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Engineering 43
Oscilloscope
Phase-Angle
Measurement
Bruce Mayer, PE
Licensed Electrical & Mechanical Engineer
BMayer@ChabotCollege.edu
Engineering-43: Engineering Circuit Analysis
1
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Oscope Summarized
An Oscope does ONE thing:
Draws a PLOT
of VOLTAGE vs
TIME
And That’s IT!
Engineering-43: Engineering Circuit Analysis
2
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Amplitude Measurements
These are Easy
1. Check the
VOLTS/DIV setting
on the Scope
•
FILL screen
vertically
5.1 Div
High
2. Count VERTICAL
Deflection Divisions
•
i.e; Count Squares
3. Multiply DIVs times
VOLTS/DIV
Engineering-43: Engineering Circuit Analysis
3
0.5V
V pp 5.1DIV
2.55V
DIV
VM V pp 2 1.28V
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Vertical (V) Scale for Digital Scope
Engineering-43: Engineering Circuit Analysis
4
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Phase Angle,
The Equation for a Phase-SHIFTED
Sinusoidal Electrical-Potential Signal
vX t VXM cos(t )
Where
• VXM The AMPLITUDE (Max, or Peak
Value) of the Sinusoid in Volts
• The PHASE Angle in DEGREES
– MAGNITUDE <180°
– SIGN can be POSITIVE or NEGATIVE
Engineering-43: Engineering Circuit Analysis
5
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Scope Phase-Angle
The Scope Trace Tells us
NOTHING about the MAGNITUDE
and SIGN of the Phase Angle
•
It Doesn’t Even give a Starting Point
•
All we get is TWO v(t) Traces
The Steps to Get to
1. Define (pick) a BASELINE Signal
2. Get ± from shifted-Signal LEAD or LAG
3. Get -Magnitude from TIME-SHIFT, td
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
1. Define the BaseLine Signal
For ANY Steady-State AC Signal
(SS-AC) We, as Ckt Analysts, get to
PICK ONE Node-Voltage exOR BranchCurrent as having a ZERO Phase Angle
• i.e., We can SET the point where = 0°
• Analogous to Selecting a GND
Since the Scope ONLY measures
Potential we can Pick any Node
VOLTAGE as the BaseLine Signal
which has ZERO Phase
Engineering-43: Engineering Circuit Analysis
7
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
1. Define the BaseLine Signal
The BaseLine Signal is USUALLY (not
Always) the +Side of the Supply
vS t VSM cos(t 0) VS VSM 0
rads
e.g. , 5V cos 377
t 5V0 5V
sec
On the Scope The BaseLine Signal
is typically
• The “A” or CH1 Trace
• The Trigger Source
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
2. Determine the Sign of
Looking at the Traces we can
OBSERVE whether the Unknown, or “X”
Signal LEADS or LAGS the BaseLine
• See Next Slide
The Question Then becomes: Does
• LEAD Imply POSITIVE-?
– Then Lag implies NEGATIVE-
• LAG Imply POSITIVE-?
– Then Lead implies NEGATIVE-
Engineering-43: Engineering Circuit Analysis
9
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
This is the BASELINE Signal
The X-Signal LAGS the BASELINE;
its PEAK occurs LATER in Time
vS(ωt)
Engineering-43: Engineering Circuit Analysis
10
vX(ωt±||)
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
2. Lead or Lab = +/− by MATLAB
Vx LAGS by 53°
Vx LEADS by 53°
10
10
Vs(t)
Vx(t)
6
6
4
4
2
0
-2
-4
2
0
-2
-4
-6
-6
-8
-8
-10
0
1
2
3
4
time (mS)
5
6
7
8
vX t VXM cos(t 53)
LEADING →
POSITIVE
Engineering-43: Engineering Circuit Analysis
11
Vs(t)
Vx(t)
8
Electrical Potenial (V)
Electrical Potenial (V)
8
-10
0
1
2
3
4
time (mS)
5
6
7
vX t VXM cos(t 53)
LAGGING →
NEGATIVE
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
8
3. -Magnitude
Notice from the Scope Trace that ONE
Sinusoidal CYCLE-TIME-PERIOD, T,
corresponds to 360°: T↔ 360°
Further Notice from the Dual-Trace
Display that the X-Signal will Lead or
Lag the BaseLine by the TIME-Shift, td
Now Realize that td will be some
FRACTION of a Period; Thus
• Find td by SEC/DIV, Multiply by 360°/T
Engineering-43: Engineering Circuit Analysis
12
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
td = 1.6DIV
vX Lagging
VXpp = 4.6DIV
T = 4.1DIV
T = 360°
Engineering-43: Engineering Circuit Analysis
13
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Horizontal (t) Scale for digital scope
Engineering-43: Engineering Circuit Analysis
14
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
3. -Magnitude
From The Scope Time-Measurements
on the on the Last Slide Find
• T = 4.1 DIV = 360°
• td = 1.6 DIV, Lagging
• SEC/DIV = 0.5 millisec/Div
Calc T &
0.5mS
T 4.1DIV
2.05mS
DIV
0.5mS
t d 1.6 DIV
0.8mS
DIV
Engineering-43: Engineering Circuit Analysis
15
f
488 Hz
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
3. -Magnitude
Now since td/T is a Fraction of a Period
td
Multiply td/T by 360° to Find
360
T
In this Case
1Period
360
1.6 DIV
0.8mS
360 140.5
2.05mS Period 4.1DIV
Use the LAGGING observation to
apply the sign of as NEGATIVE
td - Lagging 140.5 2.452rads
Engineering-43: Engineering Circuit Analysis
16
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Complete The Example
From The Scope VoltageMeasurements on the on the “” Slide
Find
• VXpp = 4.6 DIV
• VOLTS/DIV = 0.5 V/Div
Calc VXM
0.5V
VXpp 4.6 DIV
2.3V
Div
VXM VXpp 2 1.15V
Engineering-43: Engineering Circuit Analysis
17
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Complete the Example
Now Can Fully
Characterize the
Unknown Sinusoid
Relative to the
BaseLine
vX
Using The Results
of the Phase and
Amplitude Calcs
v X t 1.15V cos2 488t 2.452
t 2.452
j 3066rads
sec
1.15V Re e
• Note that ω = 2πf
Alternatively in Std
Phasor Form
VX 1.15V 140.5
Engineering-43: Engineering Circuit Analysis
18
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Example: Find H(f) = VC/VS
Find Vc in the Scope-Measured Series
RC Circuit
9.7V0°
Engineering-43: Engineering Circuit Analysis
19
SCOPE
BaseLine
Vc
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Series Ckt: GND => Vs => R => C => GND
10
8
6
Vc LAGS
2
T = 0.77 mS
0
Vcm =6.15V
Potential to GND (V)
4
-2
-4
PARAMETERS
• Vs = (9.7V)? 0°
• R = 6.8 kΩ
-6
-8
•
C
•
f
=
=
2
1
2
3
n
0
0
td = 0.11 mS
Vs (V)
F
H
z
Vc (V)
-10
0.0
0.1
0.2
file = CR_RC_Phase-Difference_0601.xls
Engineering-43: Engineering Circuit Analysis
20
0.3
0.4
0.5
0.6
0.7
Time (mS)
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
0.8
0.9
The RC Series Ckt Phasor
Calc The Frequency Parameters
f 1 cycle T 1 cycle 0.77mS 1.3kHz
2 Rad
kCycle
kRad
f 2 1.3
8.17
1 Cycle
sec
sec
9.7V0°
Vc
Calc noting that Vc LAGS
td
11
360 360 51 0.89rads
T
77
Then Vc
by 6.15V
Amplitude
Engineering-43: Engineering Circuit Analysis
21
8170
vC t 6.15V cos
t 0.89
sec
VC 6.15V 51
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
The RC Transfer Function
The Transfer Function for the R→C
Circuit at 1.3 kHz
VC 6.15V 51
H f 1.3kHz
VS
9.7V0
or
VC
H f 1.3kHz
0.6833 51
VS
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Example: Swap C↔R for H(f)
Find Vr in the Scope-Measured Series
CR Circuit
9.7V0°
Engineering-43: Engineering Circuit Analysis
23
SCOPE
BaseLine
Vr
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Series Ckt: GND => Vs => C => R => GND
10
Vr LEADS
8
6
td = 0.084 mS
2
T = 0.77 mS
0
Vrm = 7.5V
Potential to GND (V)
4
-2
-4
PARAMETERS
• Vs = (9.7V)? 0°
• R = 6.8 kΩ
-6
•
C
•
f
=
2
2
n
Vs (V)
F
-8
=
1
3
0
0
H
z
Vr (V)
-10
0.0
0.1
0.2
file = CR_RC_Phase-Difference_0601.xls
Engineering-43: Engineering Circuit Analysis
24
0.3
0.4
0.5
0.6
0.7
Time (mS)
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
0.8
0.9
The CR Series Ckt Phasor
Calc The Frequency Parameters
f 1 cycle T 1 cycle 0.77mS 1.3kHz
2 Rad
kCycle
kRad
f 2 1.3
8.17
1 Cycle
sec
sec
Calc noting that Vr LEADS
9.7V0°
360 84
t d
360 39 0.68 rads
T
770
Then Vr
8170
vR t 7.5V cos
t 0.68
by 7.5V
sec
Amplitude V 7.5V39
R
Engineering-43: Engineering Circuit Analysis
25
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
Vr
The CR Transfer Function
The Transfer Function for the C→R
Circuit at 1.3 kHz
VC 6.15V 51
H f 1.3kHz
VS
9.7V0
or
VC
H f 1.3kHz
0.6833 51
VS
Engineering-43: Engineering Circuit Analysis
26
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
All Done with the Tutorial
PhasErs
on
Stun...
A phaser RIFLE
(often referred to as a
type-3 phaser)
Engineering-43: Engineering Circuit Analysis
27
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
MATLAB Script-Code
% B. Mayer
% ENGR43 * 19Jan06
% Phase-Shift Lag Plot
%
% Parameters
w = 1500; % Angular Freqency in rad/sec
Vsa = 9.7; % Voltage Source Amplitude in Volts
AR = .73; % Attenuation Ratio
phi = -0.925; % phase Angle in Rads
phi_deg = 180*phi/pi % degrees
%
%
% Calc period
T = 2*pi/w % seconds
%
% Define t vector over 1.2 periods
t = linspace(0, 2.2*T, 200);
%
% Calc Vs & Vc over 1.2 periods
Vs = Vsa*cos(w*t);
Vx = AR*Vsa*cos(w*t + phi);
%
% Plot both
plot(1000*t, Vs, 1000*t, Vx, '--'), xlabel('time (mS)'),...
ylabel('Electrical Potenial (V)'),...
legend('Vs(t)', 'Vx(t)'), title('Vx LAGS by 53°')
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt
More Scope Traces
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Scope_Phase-Angle_Tutorial.ppt