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Section 1.4 Lines Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Find the slope of the line containing the points (-1, 4) and (2, -3). 3 4 7 m 2 1 3 43 7 m 1 2 3 7 The average rate of change of y with respect to x is 3 Copyright © 2013 Pearson Education, Inc. All rights reserved Compute the slopes of the lines L1, L2, L3, and L4 containing the following pairs of points. Graph all four lines on the same set of coordinate axes. Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Graph the equation: x = –2 y (-2,4) (-2,2) (-2,0) (-2,1) x Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Find the equation of a line with slope –3 and containing the point (–1, 4). y 4 3 x 1 y y 4 3x 3 Run = 1 Rise = -3 y 3 x 1 x Copyright © 2013 Pearson Education, Inc. All rights reserved Find the equation of a horizontal line containing the point (2, – 4). y 4 0 x 2 y x y40 y 4 Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Find an equation of the line L containing the points (–1, 4) and (3, –1). Graph the line L. 5 y 4 x 1 4 5 y 4 x 1 4 5 1 4 m 4 3 1 (-1, 4) (3, -1) Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Find the slope m and y-intercept b of the equation 3x – 2y = 6. Graph the equation. 3x – 2y = 6 – 2y = –3x+6 3 y x 3 2 (2, 0) 2 3 3 y x 3 2 (0, -3) Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Graph the linear equation 3x + 2y = 6 by finding its intercepts. 3x + 2(0) = 6 3(0) + 2y = 6 3x = 6 2y = 6 x=2 y=3 (0, 3) The x-intercept is at the point (2, 0) (2, 0) The y-intercept is at the point (0, 3) Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved L1 : 3x 2 y 12 L2 : 6 x 4 y 0 2 y 3 x 12 3 y x6 2 3 Slope ; y -intercept 6 2 4 y 6 x 3 y x 2 3 Slope ; y -intercept 0 2 y x Copyright © 2013 Pearson Education, Inc. All rights reserved Find an equation for the line that contains the point (1,3) and is parallel to the line 3x 4 y 12. 4 y 3x 12. y y1 m x x1 y 3 y x 3 4 x 3 y 3 x (1) 4 3 15 y x 4 4 3 So a line parallel to this one would have a slope of . 4 Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Copyright © 2013 Pearson Education, Inc. All rights reserved Find the slope of a line perpendicular to a line with slope 4 m2 3 mperpendicular 4 3 m1 3 4 . 3 4 Copyright © 2013 Pearson Education, Inc. All rights reserved Find an equation for the line that contains the point (1,3) and is perpendicular to the line 3x 4 y 12. y y1 m x x1 4 y 3x 12. y 3 y x 3 4 x 4 y 3 x (1) 3 4 5 y x 3 3 4 So a line perpendicular to this one would have a slope of . 3 Copyright © 2013 Pearson Education, Inc. All rights reserved