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...  199 / s . t d 25. The linear speed of a point on Earth’s surface depends on its distance from the axis of rotation. To solve for the linear speed, we use v = r, where r is the radius of its orbit. A point on Earth at a latitude of 40° moves along a circular path of radius r = R cos 40°, where R ...
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... Because this torque is balanced by the torque produced by the bolt on the wrench, an equal torque is produced on the bolt. Because there are six points where a force is applied to the bolt, we have Fbolt = (/r)/6 = (80 m · N)/6(0.0075 m) = 1.8 103 N. 34. The moment of inertia of a sphere about an ...
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... Because this torque is balanced by the torque produced by the bolt on the wrench, an equal torque is produced on the bolt. Because there are six points where a force is applied to the bolt, we have Fbolt = (/r)/6 = (80 m · N)/6(0.0075 m) = 1.8 103 N. 34. The moment of inertia of a sphere about an ...
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... Applying the Law of Gravitation, continued • Cavendish applied Newton’s law of universal gravitation to find the value of G and Earth’s mass. • When two masses, the distance between them, and the gravitational force are known, Newton’s law of universal gravitation can be used to find G. • Once the v ...
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PHY 203: Solutions to Problem Set 9
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