HIGH SCHOOL MATHEMATICS CURRICULUM GUIDE June 2011
... semester; otherwise repeat Intensive A) + Geometry Intensive A + Algebra 1 Intensive A or G + Algebra 1 (Could theoretically stop Algebra 1 if EOC is passed at end of first semester) Intensive G + Geometry ...
... semester; otherwise repeat Intensive A) + Geometry Intensive A + Algebra 1 Intensive A or G + Algebra 1 (Could theoretically stop Algebra 1 if EOC is passed at end of first semester) Intensive G + Geometry ...
7.4 SAS - Van Buren Public Schools
... If two sides and the included angle of one triangle are congruent to the corresponding sides and the included angle of the second triangle, then the triangles are congruent. (SAS) ...
... If two sides and the included angle of one triangle are congruent to the corresponding sides and the included angle of the second triangle, then the triangles are congruent. (SAS) ...
4.2 Triangle Congruence by SSS and SAS
... 4.3 Triangle Congruence by ASA and AAS • You can prove that two triangles are congruent without having to show that all corresponding parts are congruent. – You will prove triangles congruent by using one pair of corresponding sides and two pairs of corresponding angles. ...
... 4.3 Triangle Congruence by ASA and AAS • You can prove that two triangles are congruent without having to show that all corresponding parts are congruent. – You will prove triangles congruent by using one pair of corresponding sides and two pairs of corresponding angles. ...
Properties of Triangles
... Is the shape of the Federal Triangle a triangle? How many sides does the Federal Triangle have? What is the actual shape of the Federal Triangle? What is the sum of the internal angles of the Federal Triangle? What portion of the area is actually a triangle? Do some research and find the lengths of ...
... Is the shape of the Federal Triangle a triangle? How many sides does the Federal Triangle have? What is the actual shape of the Federal Triangle? What is the sum of the internal angles of the Federal Triangle? What portion of the area is actually a triangle? Do some research and find the lengths of ...
Right Triangle Notes Packet
... To prove that two right triangles are similar you can show that _____________________________ of one of the triangles is _________________________ to______________ of the ___________________ of the other triangle. Theorem 9.1 (Use 3x5 Card to Explore): If the altitude is drawn to the hypotenuse of a ...
... To prove that two right triangles are similar you can show that _____________________________ of one of the triangles is _________________________ to______________ of the ___________________ of the other triangle. Theorem 9.1 (Use 3x5 Card to Explore): If the altitude is drawn to the hypotenuse of a ...
Geometry Opener(s) 11/10
... Rudolfo V. (2x) Tito G. (10x) Ashley P. (9x) Erika G. (115x) Joshua M. (20x) Jacob D. (2x) Christian R. (2x) Karyme E. (4x) Beatriz F. (4x) Crispin G. (8x) Matt B. (4x) Frankie R. (11x) Leslie G. (7x) Randy R. (3x) Natalia G. (6x) Yesenia R. (4x) Jose M. (1x) Adrian R. (2x) David D. (4x) Alex H. (2x ...
... Rudolfo V. (2x) Tito G. (10x) Ashley P. (9x) Erika G. (115x) Joshua M. (20x) Jacob D. (2x) Christian R. (2x) Karyme E. (4x) Beatriz F. (4x) Crispin G. (8x) Matt B. (4x) Frankie R. (11x) Leslie G. (7x) Randy R. (3x) Natalia G. (6x) Yesenia R. (4x) Jose M. (1x) Adrian R. (2x) David D. (4x) Alex H. (2x ...
Acute Angle - An angle that measures less than 90
... Perpendicular lines or line segments– two lines or line segments that intersect at right angles; line segments or rays that lie on perpendicular lines are perpendicular to each other; the symbol ┴ means “is perpendicular to” ...
... Perpendicular lines or line segments– two lines or line segments that intersect at right angles; line segments or rays that lie on perpendicular lines are perpendicular to each other; the symbol ┴ means “is perpendicular to” ...
Junior - CEMC - University of Waterloo
... • We could use trial and error with the top right and middle square and since there are only 5 numbers not being used this approach is not too tedious. • Another approach is to first find the magic constant. We are not given the magic constant, but we know that every row must add up to this value an ...
... • We could use trial and error with the top right and middle square and since there are only 5 numbers not being used this approach is not too tedious. • Another approach is to first find the magic constant. We are not given the magic constant, but we know that every row must add up to this value an ...
Inversive Plane Geometry
... Given a circle C with center O, and a point P, we define the inverse P′ of P in C as follows. The inverse of every point of C is itself (P′ = P). The inverse of O is ∞, and the inverse of ∞ is O. If P is inside C (but different from O) then extend the line OP beyond the circle C and erect a perpend ...
... Given a circle C with center O, and a point P, we define the inverse P′ of P in C as follows. The inverse of every point of C is itself (P′ = P). The inverse of O is ∞, and the inverse of ∞ is O. If P is inside C (but different from O) then extend the line OP beyond the circle C and erect a perpend ...
