Cancer Research Project
... 2. What does the normal (functional) version of the gene do in the cell? 3. What does the mutated version of the gene do that contributes to cancer? 4. What cancers is the mutated version of the gene associated with? 5. What are the symptoms and physiological problems of this cancer? 6. What signali ...
... 2. What does the normal (functional) version of the gene do in the cell? 3. What does the mutated version of the gene do that contributes to cancer? 4. What cancers is the mutated version of the gene associated with? 5. What are the symptoms and physiological problems of this cancer? 6. What signali ...
teacherstryscience.org
... Francois Jacob and Jacques Monod Experiments with E. Coli showed that it is capable of regulating the expression of its genes An operon consists of the following elements 1. Promoter - where RNA polymerase attaches, signalling the start of the gene 2. Operator - where a repressor binds, stopping th ...
... Francois Jacob and Jacques Monod Experiments with E. Coli showed that it is capable of regulating the expression of its genes An operon consists of the following elements 1. Promoter - where RNA polymerase attaches, signalling the start of the gene 2. Operator - where a repressor binds, stopping th ...
Name Date ______ Period _____
... o When genes are being used, the DNA is stretched out in the form of chromatin so that the information it contains can be used to direct the synthesis of proteins. Cell division o DNA replicates (it makes a copy of itself) o DNA condenses into chromosomes by coiling around proteins, which makes them ...
... o When genes are being used, the DNA is stretched out in the form of chromatin so that the information it contains can be used to direct the synthesis of proteins. Cell division o DNA replicates (it makes a copy of itself) o DNA condenses into chromosomes by coiling around proteins, which makes them ...
Mitochondrial genome
... There is no universal system of sex determination; can be either genetic or environmental Humans and fruit flies have the XY genetic system ...
... There is no universal system of sex determination; can be either genetic or environmental Humans and fruit flies have the XY genetic system ...
Exam Week
... Describe how errors could occur(e.g. nondisjunction) and that those errors can result in offspring with a different number of chromosomes and the exemplifies the problems that could cause. ...
... Describe how errors could occur(e.g. nondisjunction) and that those errors can result in offspring with a different number of chromosomes and the exemplifies the problems that could cause. ...
CONNECT!
... • What mistake occurred in the middle cell? • The gametes should all be haploid, which means a chromosome # of ___ for this species. • How many of the gametes have the proper # of chromosomes? • What is this type of mistake called? ...
... • What mistake occurred in the middle cell? • The gametes should all be haploid, which means a chromosome # of ___ for this species. • How many of the gametes have the proper # of chromosomes? • What is this type of mistake called? ...
I. The Emerging Role of Genetics and Genomics in Medicine
... 6. Mode of inheritance refers to whether a trait is dominant or recessive, autosomal or carried on a sex chromosome. 7. An autosomal condition is equally likely to affect either sex. 8. X-linked characteristics affect males much more than females. 9. Recessive conditions can skip a generation becaus ...
... 6. Mode of inheritance refers to whether a trait is dominant or recessive, autosomal or carried on a sex chromosome. 7. An autosomal condition is equally likely to affect either sex. 8. X-linked characteristics affect males much more than females. 9. Recessive conditions can skip a generation becaus ...
9.3 Male or Female? - Alvarado Intermediate School
... • Some have patterns of inheritance that are different from the ones Mendel discovered. • We have learned that some traits do show complete dominance. ...
... • Some have patterns of inheritance that are different from the ones Mendel discovered. • We have learned that some traits do show complete dominance. ...
DNA info
... base pairs of varying lengths are called genes. Each gene contains a piece of genetic information that tells the cell to make a specific protein. Thousands of genes are found on each strand of DNA that makes up your chromosomes. It has been thought that much of the length of DNA does not seem to cod ...
... base pairs of varying lengths are called genes. Each gene contains a piece of genetic information that tells the cell to make a specific protein. Thousands of genes are found on each strand of DNA that makes up your chromosomes. It has been thought that much of the length of DNA does not seem to cod ...
VIII. Nervous system Used for rapid communication Parts: CNS
... autosomal vs. sex-linked (on the X or Y chromosome) monohybrid cross; one trait; 3:1 (Aa x Aa); 1:1 (Aa x aa) or 4:1 (AA x_), (aa x aa) dihybrid cross; 9:3:3:1 genotype (AaBb x AaBb) or test cross 1:1:1:1(AaBb x aabb) Thomas Hunt Morgan- fruit flies, X- linked traits o male- heterozygous XY; ...
... autosomal vs. sex-linked (on the X or Y chromosome) monohybrid cross; one trait; 3:1 (Aa x Aa); 1:1 (Aa x aa) or 4:1 (AA x_), (aa x aa) dihybrid cross; 9:3:3:1 genotype (AaBb x AaBb) or test cross 1:1:1:1(AaBb x aabb) Thomas Hunt Morgan- fruit flies, X- linked traits o male- heterozygous XY; ...
Document
... 5. Identify how each of the following is represented in a pedigree chart. a. Male Square b. Female Circle c. A male with the trait Completely filled square d. A female with the trait Completely filled circle e. A carrier Half colored circle or square f. A normal male (does not have the trait) ...
... 5. Identify how each of the following is represented in a pedigree chart. a. Male Square b. Female Circle c. A male with the trait Completely filled square d. A female with the trait Completely filled circle e. A carrier Half colored circle or square f. A normal male (does not have the trait) ...
Topic 3 - GEOCITIES.ws
... The use of E. Coli in gene techonology is well documented. Most of its DNA is in one circular chromosome but it also has plasmids (smaller circles of DNA helix). These plasmids can be removed and cleaved by restriction enzymes at target sequences. Originally developed by bacteria for defense against ...
... The use of E. Coli in gene techonology is well documented. Most of its DNA is in one circular chromosome but it also has plasmids (smaller circles of DNA helix). These plasmids can be removed and cleaved by restriction enzymes at target sequences. Originally developed by bacteria for defense against ...
Biology 122, Spring 2014 Activities for the week of March 10
... You should be caught up on previous cinelectures and study the cinelectures for the week of 3/10-3/14 before doing these assignments. Assignment 1. Write a brief essay describing the cell cycle, and the ways that cyclins and their dependent kinases control the cell cycle, concentrating on the G1>S c ...
... You should be caught up on previous cinelectures and study the cinelectures for the week of 3/10-3/14 before doing these assignments. Assignment 1. Write a brief essay describing the cell cycle, and the ways that cyclins and their dependent kinases control the cell cycle, concentrating on the G1>S c ...
Human Heredity - Fort Bend ISD
... Remember that meiosis is the reductional cell division that divides one diploid cell to produce four haploid gametes (sex cells, sperm or egg). Normally gametes have one copy of each chromosome. 1. Sometimes chromosomes might not separate properly during meiosis; this is called nondisjunction. 2. If ...
... Remember that meiosis is the reductional cell division that divides one diploid cell to produce four haploid gametes (sex cells, sperm or egg). Normally gametes have one copy of each chromosome. 1. Sometimes chromosomes might not separate properly during meiosis; this is called nondisjunction. 2. If ...
Régulation de SRY - Département de biologie
... the inactive X chromosomes) is approximately 50:50, but in females with Xlinked dominant disorders this ratio can be different because of a disadvantage for cells expressing a mutant X-linked allele. Divergence from the 50:50 ratio, known as skewing of XCI, can be different in various tissues and in ...
... the inactive X chromosomes) is approximately 50:50, but in females with Xlinked dominant disorders this ratio can be different because of a disadvantage for cells expressing a mutant X-linked allele. Divergence from the 50:50 ratio, known as skewing of XCI, can be different in various tissues and in ...
The Human Genome
... – You can tell if male or female by spots because genes that controls spots is located on X chromosome. Males will have one color of spot and females will have 2 colors if Barr Bodies are expressed at different times. Why? ...
... – You can tell if male or female by spots because genes that controls spots is located on X chromosome. Males will have one color of spot and females will have 2 colors if Barr Bodies are expressed at different times. Why? ...
Can You Divide - Cell Reproduction Notes
... Asexual Reproduction (cont)… • In other words, the new cells are an exact copy of its parent (allow for little variation among species) ...
... Asexual Reproduction (cont)… • In other words, the new cells are an exact copy of its parent (allow for little variation among species) ...
Section 3 Exam
... 33. A dihybrid cross mates two individuals that are both _____________ for ________ gene (or genes). A. Heterozygous, two B. Heterozygous, one C. Homozygous, two D. Homozygous, one 34. Mendel’s dihybrid pea plant crosses yielded phenotypic ratios in F 2 offspring of: A. 1:2:2:1:4:1:2:2:1 B. 9:3:3:1 ...
... 33. A dihybrid cross mates two individuals that are both _____________ for ________ gene (or genes). A. Heterozygous, two B. Heterozygous, one C. Homozygous, two D. Homozygous, one 34. Mendel’s dihybrid pea plant crosses yielded phenotypic ratios in F 2 offspring of: A. 1:2:2:1:4:1:2:2:1 B. 9:3:3:1 ...
Prenatal Microarray Testing - Scotland`s Health on the Web
... Microarray testing allows the detection of chromosome imbalances which are too small to be seen by the routine chromosome tests offered during a pregnancy. Why have you been offered microarray testing? Your serum screening results or your ultrasound has shown that there is an increased chance that y ...
... Microarray testing allows the detection of chromosome imbalances which are too small to be seen by the routine chromosome tests offered during a pregnancy. Why have you been offered microarray testing? Your serum screening results or your ultrasound has shown that there is an increased chance that y ...
Updated BioI_Unit3_Voc
... 18 formation of proteins based on information in DNA & carried out by RNA 19 nitrogenous bases with double rings of carbon and nitrogen atoms, e.g. adenine & guanine 20 nitrogenous bases with a single ring of carbon and nitrogen atoms, e.g. thymine & cytosine 21 the Y-shaped region of DNA resulting ...
... 18 formation of proteins based on information in DNA & carried out by RNA 19 nitrogenous bases with double rings of carbon and nitrogen atoms, e.g. adenine & guanine 20 nitrogenous bases with a single ring of carbon and nitrogen atoms, e.g. thymine & cytosine 21 the Y-shaped region of DNA resulting ...
Genetics and Inheritance - Harford Community College
... • Spermatogenesis – creation of sperm – A single stem cell divides twice to produce four spermatozoa (sperm cell) – This process occurs along the nearly half mile of seminiferous tubules in each testis – The seminiferous tubules drain into the epididymus. There spermatozoa mature up to 2 weeks in t ...
... • Spermatogenesis – creation of sperm – A single stem cell divides twice to produce four spermatozoa (sperm cell) – This process occurs along the nearly half mile of seminiferous tubules in each testis – The seminiferous tubules drain into the epididymus. There spermatozoa mature up to 2 weeks in t ...
Biology 212 General Genetics
... Parental types = 497 + 472 = 969/1000 = 96.9% non-recombinant Recombinant types = 19 + 12 = 31/1000 = 3.1% recombinant types Construct a linkage map of the two genes ...
... Parental types = 497 + 472 = 969/1000 = 96.9% non-recombinant Recombinant types = 19 + 12 = 31/1000 = 3.1% recombinant types Construct a linkage map of the two genes ...
Standard 3—Genetics
... randomly switched off. This chromosome forms a dense region in the nucleus known as a Barr body. Barr bodies are generally not found in males because their single ___ chromosome is still active. ...
... randomly switched off. This chromosome forms a dense region in the nucleus known as a Barr body. Barr bodies are generally not found in males because their single ___ chromosome is still active. ...
X-inactivation
X-inactivation (also called lyonization) is a process by which one of the two copies of the X chromosome present in female mammals is inactivated. The inactive X chromosome is silenced by its being packaged in such a way that it has a transcriptionally inactive structure called heterochromatin. As nearly all female mammals have two X chromosomes, X-inactivation prevents them from having twice as many X chromosome gene products as males, who only possess a single copy of the X chromosome (see dosage compensation). The choice of which X chromosome will be inactivated is random in placental mammals such as humans, but once an X chromosome is inactivated it will remain inactive throughout the lifetime of the cell and its descendants in the organism. Unlike the random X-inactivation in placental mammals, inactivation in marsupials applies exclusively to the paternally derived X chromosome.