
A Totient Function Inequality
... sufficiently large primorial integer Nk. This unconditional result is consistent with the Riemann hypothesis, and seems to prove the Nicolas inequality, Theorem 4 below, for all sufficiently large integers. Just a finite number of cases of primorial integers Nk N0 remain unresolved as possible cou ...
... sufficiently large primorial integer Nk. This unconditional result is consistent with the Riemann hypothesis, and seems to prove the Nicolas inequality, Theorem 4 below, for all sufficiently large integers. Just a finite number of cases of primorial integers Nk N0 remain unresolved as possible cou ...
A Brief on Linear Algebra
... Remark: We could just as well define P6 (R), where we take the scalars (including the coefficients) to be real. Likewise, we could take any integer n > 0 in place of the integer 6. Example 2.7 We take V = C([0, 1], R), the set of all continuous real-valued functions defined on the interval [0, 1] ov ...
... Remark: We could just as well define P6 (R), where we take the scalars (including the coefficients) to be real. Likewise, we could take any integer n > 0 in place of the integer 6. Example 2.7 We take V = C([0, 1], R), the set of all continuous real-valued functions defined on the interval [0, 1] ov ...