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A program for the countable choice axiom
A program for the countable choice axiom

chapter end test solutions
chapter end test solutions

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Lecture2-1

Zero Product Principle
Zero Product Principle

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Part 1: Al-Khw¯arizm¯ı, Quadratic Equations, and the Birth of Algebra

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Pythagorean triples in elementary number theory

Math 308: Defining the rationals and the reals
Math 308: Defining the rationals and the reals

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Discrete Mathematics Lecture 2 Logic of Quantified Statements

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7.5 The Converse of the Pythagorean Theorem

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On perfect and multiply perfect numbers

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CPSC 411 Design and Analysis of Algorithms

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Graduate Algebra Homework 3

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Lecture 20

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Why we cannot divide by zero - University of Southern California

Finite Fields
Finite Fields

... A multiplicative group G is said to be cyclic if there is an element a ∈ G such that for any b ∈ G there is some integer j with b = aj . Such an element is called a generator of the cyclic group, and we write G = hai. Note we may have more than one generator, e.g. either 1 or −1 can be used to gener ...
lecture notes as PDF
lecture notes as PDF

Continued fractions and transcendental numbers Boris
Continued fractions and transcendental numbers Boris

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lindsaythurber.rdpsd.ab.ca

Complex numbers via rigid motions
Complex numbers via rigid motions

Trigonometric sums
Trigonometric sums

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Here

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Fundamental theorem of algebra

The fundamental theorem of algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This includes polynomials with real coefficients, since every real number is a complex number with an imaginary part equal to zero.Equivalently (by definition), the theorem states that the field of complex numbers is algebraically closed.The theorem is also stated as follows: every non-zero, single-variable, degree n polynomial with complex coefficients has, counted with multiplicity, exactly n roots. The equivalence of the two statements can be proven through the use of successive polynomial division.In spite of its name, there is no purely algebraic proof of the theorem, since any proof must use the completeness of the reals (or some other equivalent formulation of completeness), which is not an algebraic concept. Additionally, it is not fundamental for modern algebra; its name was given at a time when the study of algebra was mainly concerned with the solutions of polynomial equations with real or complex coefficients.
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