I(k-1)
... can make n cents of postage by making n-1 cents of postage and then doing one of: take out two 7c stamps and add five 3c stamps or (if there are fewer than two 7c stamps), take out two 3c stamps and add a 7c stamp. What additional base case (if any) do we need? a. n = 6 b. n = 13 c. n = n-1 d. no ad ...
... can make n cents of postage by making n-1 cents of postage and then doing one of: take out two 7c stamps and add five 3c stamps or (if there are fewer than two 7c stamps), take out two 3c stamps and add a 7c stamp. What additional base case (if any) do we need? a. n = 6 b. n = 13 c. n = n-1 d. no ad ...
1 (1 mark) (1 mark) (2 marks) (3 marks) (2 marks) (4 marks) (2 marks
... One of the congruences 1599x ≡ 15 (mod 2010) and 1599x ≡ 16 (mod 2010) has no solutions. Which is it? Find all solutions to the other, expressing your answers in the form x ≡ a (mod m). ...
... One of the congruences 1599x ≡ 15 (mod 2010) and 1599x ≡ 16 (mod 2010) has no solutions. Which is it? Find all solutions to the other, expressing your answers in the form x ≡ a (mod m). ...
dmodules ja
... to results of Musson [10]. We provide a direct proof using simplifications due to Jones [6]. The fourth section contains the proof of Theorem 1.1. We establish this result for both left and right -modules. In general, there is an equivalence between these and we show how this is induced at the level ...
... to results of Musson [10]. We provide a direct proof using simplifications due to Jones [6]. The fourth section contains the proof of Theorem 1.1. We establish this result for both left and right -modules. In general, there is an equivalence between these and we show how this is induced at the level ...
1.2. Probability Measure and Probability Space
... σ-field containing C: FC = σ(C) by adding complements and countable unions. FC is the σ-field generated by C. (5) For uncountable outcomes set it is usually not possible to give an explicit description of F . 1.2.3. Borel σ-field Most important σ-field defined on real line R −→ B(R) How to define B( ...
... σ-field containing C: FC = σ(C) by adding complements and countable unions. FC is the σ-field generated by C. (5) For uncountable outcomes set it is usually not possible to give an explicit description of F . 1.2.3. Borel σ-field Most important σ-field defined on real line R −→ B(R) How to define B( ...
