summer fun - West Windsor-Plainsboro Regional School District
... The first three chapters in your textbook reminded you of how to write formulas and balance equations. For the AP Chemistry exam, all equations must be written in net ionic form and you must be able to recognize types of reactions and then predict products. We will be writing net ionic equations all ...
... The first three chapters in your textbook reminded you of how to write formulas and balance equations. For the AP Chemistry exam, all equations must be written in net ionic form and you must be able to recognize types of reactions and then predict products. We will be writing net ionic equations all ...
A Voyage through Equations
... 2Na +Cl2 2NaCl 2. When solid copper reacts with aqueous silver nitrate, the products are aqueous copper(II) nitrate and silver metal. Cu + 2AgNO3 Cu(NO3)2 + 2Ag 3. Solid iron (III) oxide and carbon monoxide react to produce iron metal and carbon dioxide gas. Fe2O3 + 3CO 2Fe + 3CO2 4. Sulfuric ...
... 2Na +Cl2 2NaCl 2. When solid copper reacts with aqueous silver nitrate, the products are aqueous copper(II) nitrate and silver metal. Cu + 2AgNO3 Cu(NO3)2 + 2Ag 3. Solid iron (III) oxide and carbon monoxide react to produce iron metal and carbon dioxide gas. Fe2O3 + 3CO 2Fe + 3CO2 4. Sulfuric ...
Chemistry – Higher level Marking Scheme
... 4. (a) 2 x 3; (b) 6; (c) 6; (d) 6; (e) 6; (f) 2 x 3; (g) 2 x 3; (h) 6; (i) 2 x 3; (j) 2 x 3; (k) A 6, B 2 x 3. 5. (a) Define 3, 3, 2; (b) Increase 2 x 3, Drops 3 x 3; (c) Down II 2 x 3; (d) Explain 6, 3; (e) 2nd – 3rd 6 or 3, Next 3, Reason 3. 6. (a) Which 4, Reason 4; (b) Names 3, 3, 3, 3, 3; (c) C ...
... 4. (a) 2 x 3; (b) 6; (c) 6; (d) 6; (e) 6; (f) 2 x 3; (g) 2 x 3; (h) 6; (i) 2 x 3; (j) 2 x 3; (k) A 6, B 2 x 3. 5. (a) Define 3, 3, 2; (b) Increase 2 x 3, Drops 3 x 3; (c) Down II 2 x 3; (d) Explain 6, 3; (e) 2nd – 3rd 6 or 3, Next 3, Reason 3. 6. (a) Which 4, Reason 4; (b) Names 3, 3, 3, 3, 3; (c) C ...
Stoichiometry
... • We learned how much product SHOULD be produced. This is not always what we get. • Reasons: 1) some may not react 2) some may be lost in transferring 3) some may react w/ a side reaction • Percent yield = the ratio of the actual yield to the theoretical yield expressed as a percent – The percent yi ...
... • We learned how much product SHOULD be produced. This is not always what we get. • Reasons: 1) some may not react 2) some may be lost in transferring 3) some may react w/ a side reaction • Percent yield = the ratio of the actual yield to the theoretical yield expressed as a percent – The percent yi ...
Redox - edl.io
... 5. Oxygen is usually assigned an oxidation state of -2. Exceptions to this rule include peroxides (compound containing the O22- group), where each oxygen is assigned an oxidation state of -1, as in hydrogen peroxide (H2O2), and OF2 in which oxygen is assigned a +2 oxidation state. 6. In its covalent ...
... 5. Oxygen is usually assigned an oxidation state of -2. Exceptions to this rule include peroxides (compound containing the O22- group), where each oxygen is assigned an oxidation state of -1, as in hydrogen peroxide (H2O2), and OF2 in which oxygen is assigned a +2 oxidation state. 6. In its covalent ...
![Neutral ionic liquid [BMIm]BF4 promoted highly selective](http://s1.studyres.com/store/data/017897985_1-047f9869d5604c115b21339541ccfffe-300x300.png)
Equilibrium a.k.a. The Up Hill Climb
... It must be less than 5% of the original concentration to be valid. 2. If "x" is necessary, then see if the problem may be a perfect square and thus, ease the steps of solving. (Sometimes you must use the quadratic formula!) ...
... It must be less than 5% of the original concentration to be valid. 2. If "x" is necessary, then see if the problem may be a perfect square and thus, ease the steps of solving. (Sometimes you must use the quadratic formula!) ...
Chemical Equilibrium - Shailendra Kumar Chemistry
... 2B (g) + 3C (g). If the concentration of C at equilibrium is increased by a factor 2, it will cause the equilibrium concentration of B to change to: (a) two times of its original value (b) one half of its original value (c) 2√2 times of its original value (d) 1/2√2 times of its original value ...
... 2B (g) + 3C (g). If the concentration of C at equilibrium is increased by a factor 2, it will cause the equilibrium concentration of B to change to: (a) two times of its original value (b) one half of its original value (c) 2√2 times of its original value (d) 1/2√2 times of its original value ...
Chemical Changes and Structure Homework Booklet
... 12Mg are two different kinds of magnesium atom. a. What word is used to describe these types of atoms? b. Explain why they can be regarded as atoms of the same element? c. The relative atomic mass of magnesium is 24.3. What does this tell you about the relative amounts of each atom? An atom has atom ...
... 12Mg are two different kinds of magnesium atom. a. What word is used to describe these types of atoms? b. Explain why they can be regarded as atoms of the same element? c. The relative atomic mass of magnesium is 24.3. What does this tell you about the relative amounts of each atom? An atom has atom ...
INFLUENCE OF BENZENE ON THE PROCESS OF n
... benzene saturation and isomerization of n-paraffins and cycloparaffins is carried out in one process step; a special process configuration and catalyst are required. In parallel with the isomerization reactions, hydrogenation reaction of benzene to cyclohexane and its isomerization to methyl-cyclope ...
... benzene saturation and isomerization of n-paraffins and cycloparaffins is carried out in one process step; a special process configuration and catalyst are required. In parallel with the isomerization reactions, hydrogenation reaction of benzene to cyclohexane and its isomerization to methyl-cyclope ...
August 2007
... The solution in one half-cell is initially an orange colour due to the mixture of the pale green Fe2+ ions and the orange Fe3+ ions. The other half is coloured blue due to the Cu2+ ions. Describe the colour changes the student would see in each half of the cell if the reaction proceeded until no fur ...
... The solution in one half-cell is initially an orange colour due to the mixture of the pale green Fe2+ ions and the orange Fe3+ ions. The other half is coloured blue due to the Cu2+ ions. Describe the colour changes the student would see in each half of the cell if the reaction proceeded until no fur ...
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... In this second of two courses that comprise Chemistry, the student will explore the fundamental concepts of chemistry as he engages in reading and responding exercises, hands-on and virtual lab experiments, and interdisciplinary problem-solving activities. Throughout the course the student will anal ...
... In this second of two courses that comprise Chemistry, the student will explore the fundamental concepts of chemistry as he engages in reading and responding exercises, hands-on and virtual lab experiments, and interdisciplinary problem-solving activities. Throughout the course the student will anal ...
Catalysis
Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst. With a catalyst, reactions occur faster and require less activation energy. Because catalysts are not consumed in the catalyzed reaction, they can continue to catalyze the reaction of further quantities of reactant. Often only tiny amounts are required.