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EXAM 3 NAME____KEY –Answers highlighted______(1 pt.) Dr
EXAM 3 NAME____KEY –Answers highlighted______(1 pt.) Dr

... 14. Specific heat capacity is a) the quantity of heat needed to change 1.00 g of a substance by 1.00 K. b) the mass of a substance that 1.00 J of energy will heat by 1.00 K. c) the mass of a substance that 1.00 cal of energy will heat by 1.00 K. d) the temperature change undergone when 1.00 g of a ...
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1st Olympiad of Metropolises Chemistry Theoretical Problems

... under heating of furan with ammonia (amines) above 400 C in the presence of alumina. In a laboratory, the sequence of furan hydrolysis followed by Paal-Knorr reaction with ammonia (amine) is used for this transformation. This sequence can be realized as a two-step procedure or as a domino reaction. ...
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1 Unit 11-12: Equilibrium and Acid/Bases Notes Colligative

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Unit 7: Chemical Equations & Reactions

... • Adjust the coefficients to obtain the same number of atoms of this element on both sides. • Balance polyatomic ions as a unit (if possible). • Re-write H2O as H-OH if hydroxide is present 3. Balance the remaining atoms • End with the least-complex substance ...
final-H-2006-07-v1
final-H-2006-07-v1

... 63. Activation energy is the energy required to form the a. original bonds. c. reaction complex. b. activated complex. d. reactant molecules. 64. Which of the following factors does NOT affect the speed of a chemical reaction? a. the size of the beaker in which the reaction proceeds. b. temperature. ...
final-H-2006-07-v2
final-H-2006-07-v2

... 67. Activation energy is the energy required to form the a. original bonds. c. reaction complex. b. activated complex. d. reactant molecules. 68. Which of the following factors does NOT affect the speed of a chemical reaction? a. the size of the beaker in which the reaction proceeds. b. temperature. ...
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chemistry important question i

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Chemistry Final Exam Review 2006-2007

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Chemical Equations

... 1. Write the reactants and products using formula and state for each substance 2. Count the number of atoms of each element on the left-hand side of the equation. Do the same for the right-hand side and compare for each element. If any of these numbers do not match, the equation is not balanced and ...
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Transition Metals - Ligand Stability and Chelation

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AP Chem Stoichiometry Topic#4 Questions WS Name: Date: Per

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Syllabus for Chemical Sciences Inorganic 1. Atomic structure and

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Activity Series Unit

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Chapter 3 Stoichiometry: Calculations with Chemical Formulas and

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Module 3 -- Lesson 4

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Complex Ions and Free Energy

... • LT 8.7 – I can calculate the formation constant for complex ions and relate that to the Ksp for a slightly soluble compound. • LT 8.8 – I can calculate the free energy of a chemical reaction by utilizing my knowledge the value of K. ...
Chapter 5—Chemical Reactions
Chapter 5—Chemical Reactions

... • Balanced chemical equation—the number of atoms of each element in the reactants is equal to the number of atoms of that same element in the products. • Reactions must be balanced to obey the law of conservation of mass. • Coefficients are written to the left of each reactant or product in order to ...
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Kinetics and Chemical Equilibrium

solutions - UMass Chemistry
solutions - UMass Chemistry

... a gas with molar mass 100 g/mol at 200 K Kinetic Molecular Theory says that all gases at the same temperature have the same molecular kinetic a gas with molar mass 20 g/mol at 10 K ...
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Chapter 4:Chemical Quantities and Aqueous Reactions:

... When mixing a solute with the solvent, attractions between the like substances must break while attractions between solute-solvent are formed. If the new solute-solvent attractions are strong enough, the solute will dissolve. Water is a polar molecule with uneven distribution of electrons: (more on ...
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Catalysis



Catalysis is the increase in the rate of a chemical reaction due to the participation of an additional substance called a catalyst. With a catalyst, reactions occur faster and require less activation energy. Because catalysts are not consumed in the catalyzed reaction, they can continue to catalyze the reaction of further quantities of reactant. Often only tiny amounts are required.
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