Momentum and Impulse - Oakland Schools Moodle
... Momentum is a vector quantity • To fully describe the momentum of a 5-kg bowling ball moving westward at 2 m/s, you must include information about both the magnitude and the direction of the bowling ball • p=m*v • p = 5 kg * 2 m/s west • p = 10 kg * m / s west ...
... Momentum is a vector quantity • To fully describe the momentum of a 5-kg bowling ball moving westward at 2 m/s, you must include information about both the magnitude and the direction of the bowling ball • p=m*v • p = 5 kg * 2 m/s west • p = 10 kg * m / s west ...
Calculate the density of the 17.2-g object to the left. For all problems
... The pages that follow contain the many of the shortsheets that we completed collaboratively in class. I have given you these again to review and practice. Since, we completed all of these exclusively in class, you should have all of the answers in your science notebook in the shortsheet section to c ...
... The pages that follow contain the many of the shortsheets that we completed collaboratively in class. I have given you these again to review and practice. Since, we completed all of these exclusively in class, you should have all of the answers in your science notebook in the shortsheet section to c ...
chapter7_PC
... The booster rocket casing of 1500 kg is separated from a 12,000 kg spaceship by explosive bolts. An impulse of at least 480 Ns is needed for safe separation. The speed of the booster casing relative to the spaceship after separation is: ...
... The booster rocket casing of 1500 kg is separated from a 12,000 kg spaceship by explosive bolts. An impulse of at least 480 Ns is needed for safe separation. The speed of the booster casing relative to the spaceship after separation is: ...
Extra Credit Problems
... the chain has fallen through a distance x. Answer: F = 61.25x Newtons 15) Sand from a stationary hopper falls onto a moving conveyor belt at the rate of 5 kg/s. The conveyor belt is supported by frictionless rollers and moves at a constant speed of .75 m/s under the action of a constant horizontal e ...
... the chain has fallen through a distance x. Answer: F = 61.25x Newtons 15) Sand from a stationary hopper falls onto a moving conveyor belt at the rate of 5 kg/s. The conveyor belt is supported by frictionless rollers and moves at a constant speed of .75 m/s under the action of a constant horizontal e ...
1443-501 Spring 2002 Lecture #3
... For an inertial frame observer, the forces being exerted on the ball are only T and Fg. The acceleration of the ball is the same as that of the box car and is provided by the x component of the tension force. In the non-inertial frame observer, the forces being exerted on the ball are T, Fg, and Ffi ...
... For an inertial frame observer, the forces being exerted on the ball are only T and Fg. The acceleration of the ball is the same as that of the box car and is provided by the x component of the tension force. In the non-inertial frame observer, the forces being exerted on the ball are T, Fg, and Ffi ...
Homework #5: Momentum
... the speed and direction of each ball after the collision? 21. (II) A softball of mass 0.220 kg that is moving with a speed of 8.5 m s collides head-on and elastically with another ball initially at rest. Afterward the incoming softball bounces backward with a speed of 3.7 m s . Calculate (a) the vel ...
... the speed and direction of each ball after the collision? 21. (II) A softball of mass 0.220 kg that is moving with a speed of 8.5 m s collides head-on and elastically with another ball initially at rest. Afterward the incoming softball bounces backward with a speed of 3.7 m s . Calculate (a) the vel ...
PHYSICS 12 CIRCULAR MOTION WORKSHEET 1 1. A race car
... A 0.30 kg mass is attached to a long string and revolves clockwise (looking down from the top) in a horizontal circle of radius 0.10 m with a speed of 0.50 m/s and a period of 1.3 s. a) Calculate the change in velocity ∆v (magnitude & direction) between the point when it is travelling due north and ...
... A 0.30 kg mass is attached to a long string and revolves clockwise (looking down from the top) in a horizontal circle of radius 0.10 m with a speed of 0.50 m/s and a period of 1.3 s. a) Calculate the change in velocity ∆v (magnitude & direction) between the point when it is travelling due north and ...
