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Physics A NRG Quest Topics Define Work. Define Power. Calculate
Physics A NRG Quest Topics Define Work. Define Power. Calculate

Lecture 04a
Lecture 04a

...  During the collision, the tennis ball exerts a force on the truck which is smaller than the force which the truck exerts on the tennis ball. TRUE or FALSE ? Equal and opposite forces! The tennis ball will suffer a larger acceleration during the collision than will the truck. TRUE or FALSE ? Accele ...
Tutorial 8 Angular Momentum and Planar Kinematics
Tutorial 8 Angular Momentum and Planar Kinematics

... forces are neglected, what velocity will it attain? The booster has two stages whose total mass is 9000 kg. Eighty percent of the mass of each stage is fuel, and the exhaust velocity of each stage is 1200 m/s. When the fuel of stage 1 is expended, it is discarded and the motor of stage 2 is ignited. ...
Rotation Torque, Rolling, & Angular Momentum
Rotation Torque, Rolling, & Angular Momentum

... perpendicular to the baton and goes through it’s center. It spins at 3*pi rad-per-sec. He lets go of it quickly, without getting in its way or altering its rotation. He then quickly grabs the end of it and spins the baton about a new axis that is parallel to the old one, but that goes through the ro ...
Topic 2 Mechanics Part 2 2015-17
Topic 2 Mechanics Part 2 2015-17

... Newton’s First Law of Motion – Inertia – At Rest or Constant Velocity Aristotle (384 -322 B.C.) believed that the natural state of a body was at rest and a force was required to keep an objection in motion. Furthermore, the greater the force the greater the speed. Some 2000 years later Galileo found ...
EOC_chapter8 - AppServ Open Project 2.4.9
EOC_chapter8 - AppServ Open Project 2.4.9

... Mi = 360 kg, including 330 kg of fuel and oxidizer. In interstellar space, it starts from rest at the position x = 0, turns on its engine at time t = 0, and puts out exhaust with relative speed ve = 1 500 m/s at the constant rate k = 2.50 kg/s. The fuel will last for an actual burn time of 330 kg/(2 ...
a formula for measurement of leg power in the vertical jump
a formula for measurement of leg power in the vertical jump

Physics 207: Lecture 2 Notes
Physics 207: Lecture 2 Notes

... A mass M is held in place by a force F. Find the tension in each segment of the rope and the magnitude of F. T4  Assume the pulleys are massless and frictionless. T1  Assume the rope is massless. T3 T2 The action of a massless frictionless pulley is to change the direction of a T5 F tension. M Her ...
physicsbowl 2016 - American Association of Physics Teachers
physicsbowl 2016 - American Association of Physics Teachers

CPO Skill and Practice
CPO Skill and Practice

12.1 Momentum #2
12.1 Momentum #2

... 10. If identical bullets are shot from a pistol and a rifle, a bullet shot from the rifle will travel at a higher speed than a bullet from the pistol. Why? (Hints: Assume shooting force is the same in each case. The barrel of the rifle is longer than the barrel of the pistol.) ...
A force.
A force.

... willing to send a few of our colleagues off to search for an experiment which demands a fifth force. If you can show that five forces are needed to explain the universe, I guarantee that you will win a Nobel prize. Please remember me when you cash the check. If you can show that less than four force ...
Class Notes Forces
Class Notes Forces

... 2. If I push on a box with a force of 10 Newtons [East] and you push with 15Newtons due west, the box will have a net force of 5-Newtons to the west. This net force of 5-Newtons due west will cause the block to accelerate in the same direction. (Remember both force and acceleration are vectors and b ...
PH 105-2 Exam I SOLUTION
PH 105-2 Exam I SOLUTION

Test hints
Test hints

... discuss types of problems and point out the equations that you will have available. It will also provide you with some strategies for solving certain problems. For more detailed information please consult the various unit handouts in your ten inch thick (sorry, 25.4 cm thick, the Physics Kahuna forg ...
Higher Revision Cards
Higher Revision Cards

Higher Revision Cards A4
Higher Revision Cards A4

Chapter 4 Slides
Chapter 4 Slides

The Correct Derivation of Magnetism from Electrostatics
The Correct Derivation of Magnetism from Electrostatics

... relative velocity of the positive charge carriers on the left and the negative charge carriers on the right and the distance of interaction to decrease and to increase for the positive charge carriers on the right and the negative charge carriers on the left and so a net force is obtained. ...
Chapter 12 Forces and Motion
Chapter 12 Forces and Motion

... the second object exerts an equal and opposite force on the first object 2. Momentum = Mass x Velocity 3. The object involved must be part of a closed system. 4. Because the speeds are equal, the eagle’s greater mass gives it more momentum. 5. It is incorrect because it is the force of the water aga ...
PHYS 342: Modern Physics
PHYS 342: Modern Physics

DYNAMICS AND RELATIVITY (PART II)
DYNAMICS AND RELATIVITY (PART II)

The Age of Einstein
The Age of Einstein

A solid disk with mass = 0
A solid disk with mass = 0

... c) If the skater decreases her rotational inertia to 25 kg.m2, what will be the skater’s new rotational speed? ...
Chapter 1 - asmasaid
Chapter 1 - asmasaid

... B) product of mass times angular velocity C) product of moment of inertia times velocity D) product of moment of inertia times angular velocity ...
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Classical mechanics

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