End-semester Examination 2013 Mechanics (PHY102A/N
... (b) Einstein’s theory of relativity is valid for high speeds, but not for small speeds.! (c) √ According to Einstein’s theory of relativity, no particle can have velocity greater than speed of light.! (d) √ Time interval between two events remains invariant under Galilean transformation.! 3. Which ...
... (b) Einstein’s theory of relativity is valid for high speeds, but not for small speeds.! (c) √ According to Einstein’s theory of relativity, no particle can have velocity greater than speed of light.! (d) √ Time interval between two events remains invariant under Galilean transformation.! 3. Which ...
Unit 7 Bell Ringers - Trimble County Schools
... = distance (centimeters) divided by time (seconds) Momentum = mass x velocity ...
... = distance (centimeters) divided by time (seconds) Momentum = mass x velocity ...
1 D.2. Energetic quantities: kinetic energy, work, total energy Force
... Remark. In (D9) W12 is the work on the path from the point (1) to the point (2). In 2D or 3D this work depends in general on the actual pathway. In the particular case when work does not depend on the actual path, one says the force is conservative, or that the force is given by a potential. Then an ...
... Remark. In (D9) W12 is the work on the path from the point (1) to the point (2). In 2D or 3D this work depends in general on the actual pathway. In the particular case when work does not depend on the actual path, one says the force is conservative, or that the force is given by a potential. Then an ...
111
... a) The net force acting on the object is zero. b) A net force acts on the object opposite to the direction of motion. c) A single constant force acts on the object in the direction of motion. d) No forces act on the object. e) None of these. 3) The average velocity and the instantaneous velocity of ...
... a) The net force acting on the object is zero. b) A net force acts on the object opposite to the direction of motion. c) A single constant force acts on the object in the direction of motion. d) No forces act on the object. e) None of these. 3) The average velocity and the instantaneous velocity of ...
A constant net force is applied to a person on
... A book is resting on a table. Since the book is not moving 1. There is not a force acting on it 2. The table is pushing up with a greater force than gravity is pulling down with 3. Gravity is pulling down with a greater force than the table is pushing up with 4. The net force on the book must be zer ...
... A book is resting on a table. Since the book is not moving 1. There is not a force acting on it 2. The table is pushing up with a greater force than gravity is pulling down with 3. Gravity is pulling down with a greater force than the table is pushing up with 4. The net force on the book must be zer ...
P5.28 (p.138)
... An inertia frame of reference is a coordinate system (or frame) in which Newton’s Law’s hold. We will assume that the Earth’s surface is an inertial frame and not make errors greater than ...
... An inertia frame of reference is a coordinate system (or frame) in which Newton’s Law’s hold. We will assume that the Earth’s surface is an inertial frame and not make errors greater than ...
Slide 1
... (besides at infinity) is the electric potential zero? a) Only at one point, on the x axis, to the left of both. b) Only at one point, on the x axis, between the two. c) Only at one point, on the x axis, to the right of both. d) At two points, both on the x axis. One between the two, and the other to ...
... (besides at infinity) is the electric potential zero? a) Only at one point, on the x axis, to the left of both. b) Only at one point, on the x axis, between the two. c) Only at one point, on the x axis, to the right of both. d) At two points, both on the x axis. One between the two, and the other to ...
KD-4 power point review
... Calculate the maximum speed a 1200 kg car can travel around a curve of 35 m radius if the frictional force between the tires and the road surface is 2.4 X 103 N. Fc = m v2 / r 2.4 x 103 = 1200 v2 / 35 V = 8.4 m/s ...
... Calculate the maximum speed a 1200 kg car can travel around a curve of 35 m radius if the frictional force between the tires and the road surface is 2.4 X 103 N. Fc = m v2 / r 2.4 x 103 = 1200 v2 / 35 V = 8.4 m/s ...
2 nd Law
... F=ma The acceleration of an object is directly proportional to the net force acting on the object… …and inversely proportional to the mass of the object. ...
... F=ma The acceleration of an object is directly proportional to the net force acting on the object… …and inversely proportional to the mass of the object. ...
Newton`s laws, forces
... object in motion remains in uniform motion (i.e. constant velocity, no change in speed nor direction) unless acted on by a net external force. ...
... object in motion remains in uniform motion (i.e. constant velocity, no change in speed nor direction) unless acted on by a net external force. ...
P221_2009_week5
... • 1) W1 moves the bar only in a y-direction, his force of pulling bar up is greater than the force of gravity pulling the weight down. 2)W2 the lifter feels the force of gravity pulling the bar back down. thus to keep the bar from going down he must provide a normal force to keep it from moving for ...
... • 1) W1 moves the bar only in a y-direction, his force of pulling bar up is greater than the force of gravity pulling the weight down. 2)W2 the lifter feels the force of gravity pulling the bar back down. thus to keep the bar from going down he must provide a normal force to keep it from moving for ...
Unit 4 SG
... 5. Draw a velocity versus time graph showing the following: A zebra moves from rest to a constant speed of 2 m/s for 2 seconds, then it stops for 4 seconds to drink water, and then takes off running at 4 m/s for 2 seconds. ...
... 5. Draw a velocity versus time graph showing the following: A zebra moves from rest to a constant speed of 2 m/s for 2 seconds, then it stops for 4 seconds to drink water, and then takes off running at 4 m/s for 2 seconds. ...
Chapter 11a
... (r = 1 m) with a force F = 500 N at an angle F1 = 80 °; the other pulls at the middle of wrench with the same force and at an angle F2 = 90 °. What is the net torque the two mechanics are applying to the screw? ...
... (r = 1 m) with a force F = 500 N at an angle F1 = 80 °; the other pulls at the middle of wrench with the same force and at an angle F2 = 90 °. What is the net torque the two mechanics are applying to the screw? ...
Newton`s Second Law, X
... If the dragster is traveling with a known velocity and the magnitude of the opposing drag force at any instant is given as a function of velocity, can we determine the time and distance required for dragster to come to a stop if its engine is shut off? How ? ...
... If the dragster is traveling with a known velocity and the magnitude of the opposing drag force at any instant is given as a function of velocity, can we determine the time and distance required for dragster to come to a stop if its engine is shut off? How ? ...
Circular Motion
... Determine the centripetal force acting upon a 40-kg child who makes 10 revolutions around the Cliffhanger in 29.3 seconds. The radius of the barrel is 2.90 meters. A 900-kg car makes a 180-degree turn with a speed of 10.0 m/s. The radius of the circle through which the car is turning is 25.0 m. Dete ...
... Determine the centripetal force acting upon a 40-kg child who makes 10 revolutions around the Cliffhanger in 29.3 seconds. The radius of the barrel is 2.90 meters. A 900-kg car makes a 180-degree turn with a speed of 10.0 m/s. The radius of the circle through which the car is turning is 25.0 m. Dete ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.