
Multiple Choice
... 1993M3. A long, uniform rod of mass M and length l is supported at the left end by a horizontal axis into the page and perpendicular to the rod, as shown above. The right end is connected to the ceiling by a thin vertical thread so that the rod is horizontal. The moment of inertia of the rod about ...
... 1993M3. A long, uniform rod of mass M and length l is supported at the left end by a horizontal axis into the page and perpendicular to the rod, as shown above. The right end is connected to the ceiling by a thin vertical thread so that the rod is horizontal. The moment of inertia of the rod about ...
Document
... A person holds a 1.42 N baseball in his hand, a distance of 2L = 34 cm from the elbow joint, as shown in the figure. The biceps, attached at a distance of d = 2.75 cm from the elbow, exert an upward force of 12.8 N on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.39 ...
... A person holds a 1.42 N baseball in his hand, a distance of 2L = 34 cm from the elbow joint, as shown in the figure. The biceps, attached at a distance of d = 2.75 cm from the elbow, exert an upward force of 12.8 N on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.39 ...
Conservation of impulse and momentum
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
... is often applied when particles collide or interact. When particles impact, only impulsive forces cause a change of linear momentum. The sledgehammer applies an impulsive force to the stake. The weight of the stake is considered negligible, or non-impulsive, as compared to the force of the sledgeham ...
AP Physics-1 Forces HW-2 Read Textbook Chapter 5, sections 5.1
... example. If your answer is no, explain why not. A friend tells you that since his car is at rest, there are no forces acting on it. How would you reply? You drop two objects from the same height at the same time. Object 1 has a greater mass than object 2. If the upward force due to air resistance is ...
... example. If your answer is no, explain why not. A friend tells you that since his car is at rest, there are no forces acting on it. How would you reply? You drop two objects from the same height at the same time. Object 1 has a greater mass than object 2. If the upward force due to air resistance is ...
Circular motion
... centripetal acceleration is determined from the free-body diagram (tension, gravity, friction, normal force, etc). Since F=ma and ac=v2/r, the magnitude of the centripetal force equals mv2/r or, written together, Fc=mv2/r. The direction of the centripetal force is the same as the centripetal acc ...
... centripetal acceleration is determined from the free-body diagram (tension, gravity, friction, normal force, etc). Since F=ma and ac=v2/r, the magnitude of the centripetal force equals mv2/r or, written together, Fc=mv2/r. The direction of the centripetal force is the same as the centripetal acc ...
9 Systems of Particles - Florida State University
... Perfectly Elastic Collisions Perfectly Elastic Collisions: Kinetic energy after = kinetic energy before ...
... Perfectly Elastic Collisions Perfectly Elastic Collisions: Kinetic energy after = kinetic energy before ...
17.4 Inertia and Newton`s 1st law of motion
... moving, it resists being slowed down, speeded up, or changed in direction. The tendency of mass to keep doing whatever it is – standing still or moving in a straight line – is called inertia. Inertia is almost the same thing as mass – the more the mass the more the inertia. The diagram (right) shows ...
... moving, it resists being slowed down, speeded up, or changed in direction. The tendency of mass to keep doing whatever it is – standing still or moving in a straight line – is called inertia. Inertia is almost the same thing as mass – the more the mass the more the inertia. The diagram (right) shows ...
MOTION, FORCES, AND WORK
... 9. Air resistance: the friction experienced by objects falling through the air 10. Weight: the force of gravity on an object at the surface of a planet 11. Work: Force exerted on an object that causes it to move. 12. Joule: a unit of work equal to one Newton-meter 13. Machine: a device that changes ...
... 9. Air resistance: the friction experienced by objects falling through the air 10. Weight: the force of gravity on an object at the surface of a planet 11. Work: Force exerted on an object that causes it to move. 12. Joule: a unit of work equal to one Newton-meter 13. Machine: a device that changes ...
Powerpoint 2
... “a device that is used to manipulate the amount and/or direction of force when work is done” A common misconception is that machines are used to do a task with less work than would be needed to do the task without the machine. They do not! In fact (mainly because of friction), you actually do more w ...
... “a device that is used to manipulate the amount and/or direction of force when work is done” A common misconception is that machines are used to do a task with less work than would be needed to do the task without the machine. They do not! In fact (mainly because of friction), you actually do more w ...
Lecture 06
... potential V at a point in an electric field is defined as the potential energy per unit charge at the point. The electrical potential difference between two points will therefore be: VB - VA = WAB/q0 = Ed This gives the relationship between potential difference and electric field for a simple case. ...
... potential V at a point in an electric field is defined as the potential energy per unit charge at the point. The electrical potential difference between two points will therefore be: VB - VA = WAB/q0 = Ed This gives the relationship between potential difference and electric field for a simple case. ...
Chapter 3
... puck B. Imagine that we apply the same constant force to each puck for the same interval of time dt. How do the pucks’ kinetic energies compare at the end of this interval? ...
... puck B. Imagine that we apply the same constant force to each puck for the same interval of time dt. How do the pucks’ kinetic energies compare at the end of this interval? ...
Document
... If a force F is applied to an object of mass m it can accelerate it and increase its speed v and kinetic energy K. Similarly F can decelerate m and decrease its kinetic energy. We account for these changes in K by saying that F has transferred energy W to or from the object. If energy it transferred ...
... If a force F is applied to an object of mass m it can accelerate it and increase its speed v and kinetic energy K. Similarly F can decelerate m and decrease its kinetic energy. We account for these changes in K by saying that F has transferred energy W to or from the object. If energy it transferred ...
The Physics of Basketball
... Acceleration is speed, increasing, or decreasing, or coming to or There is great momentum in this sport. from a stop. Players of varied masses and speeds of their own. In basketball, we want to keep our acceleration under control The more momentum; the more force. We want to speed up when we ...
... Acceleration is speed, increasing, or decreasing, or coming to or There is great momentum in this sport. from a stop. Players of varied masses and speeds of their own. In basketball, we want to keep our acceleration under control The more momentum; the more force. We want to speed up when we ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.