Physics Final - Winter 2000
... The final will cover the relevant sections of Chapters 1 through 8: 1-D kinematics - motion in one dimension 2-D kinematics - motion in two dimensions and projectiles Forces - Fundamental forces and Newton's Laws Conservation of energy Conservation of momentum Uniform circular motion and ...
... The final will cover the relevant sections of Chapters 1 through 8: 1-D kinematics - motion in one dimension 2-D kinematics - motion in two dimensions and projectiles Forces - Fundamental forces and Newton's Laws Conservation of energy Conservation of momentum Uniform circular motion and ...
Chapter 5
... the gravitational force acting on the ball, it will increase its speed slightly as it falls from point A to point B, and decreases its speed slightly as it rises from point B to point A. This also implies that the tension in the string increases as the ball falls and decreases as the ball rises. ...
... the gravitational force acting on the ball, it will increase its speed slightly as it falls from point A to point B, and decreases its speed slightly as it rises from point B to point A. This also implies that the tension in the string increases as the ball falls and decreases as the ball rises. ...
Mark the following statements true or false
... 2. (a) Potential energy is necessarily a positive quantity. (b) Kinetic energy is necessarily a positive quantity. (c) The change in potential energy of an object is equal to the net work done on the object. 3. (a) I pick up a 50-lb crate and set it on a shelf 4ft off the floor. The mechanical energ ...
... 2. (a) Potential energy is necessarily a positive quantity. (b) Kinetic energy is necessarily a positive quantity. (c) The change in potential energy of an object is equal to the net work done on the object. 3. (a) I pick up a 50-lb crate and set it on a shelf 4ft off the floor. The mechanical energ ...
Homework 8 – David McIntyre - Physics | Oregon State University
... Note: A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstretched length L0 , the cord folds and its tension is zero. For simplicity, neglect the cord’s own weight and inertia as well as the air drag on the ball and the cord. ...
... Note: A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstretched length L0 , the cord folds and its tension is zero. For simplicity, neglect the cord’s own weight and inertia as well as the air drag on the ball and the cord. ...
Slides
... (only for a fraction of a second). So, in this time period, the truck accelerated (backwards) up to some speed. After the fly was squashed, it no longer exerted a force, and the truck simply continued moving at constant speed. Follow-up: What is the truck doing 5 minutes after the fly hit it? ...
... (only for a fraction of a second). So, in this time period, the truck accelerated (backwards) up to some speed. After the fly was squashed, it no longer exerted a force, and the truck simply continued moving at constant speed. Follow-up: What is the truck doing 5 minutes after the fly hit it? ...
Document
... usually just call speed. Points on the outside of a rotating object have greater linear speed than those inside closer to the axis. The speed of something moving along a circular path can also be called tangential speed, since the direction is tangent to the circle. • Rotational speed (angular speed ...
... usually just call speed. Points on the outside of a rotating object have greater linear speed than those inside closer to the axis. The speed of something moving along a circular path can also be called tangential speed, since the direction is tangent to the circle. • Rotational speed (angular speed ...
Metropolissolutions
... (e) How much work is done by the friction force of the track as the carriages move from A to B? 3.82 x 104 J (f) Work done = Force x Distance. What is the size of the friction force between the track and the carriages over this 90m section of track? Friction Force = Work done / displacement = 3.82 x ...
... (e) How much work is done by the friction force of the track as the carriages move from A to B? 3.82 x 104 J (f) Work done = Force x Distance. What is the size of the friction force between the track and the carriages over this 90m section of track? Friction Force = Work done / displacement = 3.82 x ...
Chapter 9, Solids and Fluids
... We will work with ‘ideal fluids’. Characteristics of an ideal fluid Nonviscous, there is no internal friction force between adjacent layers in the liquid. Incompressible, the density is constant. Motion is steady, the velocity, density, and pressure at each point don’t change with time. No turbulenc ...
... We will work with ‘ideal fluids’. Characteristics of an ideal fluid Nonviscous, there is no internal friction force between adjacent layers in the liquid. Incompressible, the density is constant. Motion is steady, the velocity, density, and pressure at each point don’t change with time. No turbulenc ...
Centripetal Force
... • A metal bar is used to pry a rock out of the ground by pivoting the bar under the rock and pushing down the on the other end. The end is pushed with a force of 200 N. If 2.2 m of the metal bar is extended out from under the rock, how much torque is being applied to the ...
... • A metal bar is used to pry a rock out of the ground by pivoting the bar under the rock and pushing down the on the other end. The end is pushed with a force of 200 N. If 2.2 m of the metal bar is extended out from under the rock, how much torque is being applied to the ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.