Physical Science (Forces)
... field, the two objects experience electric forces that can attract or repel them, depending on the charges involved. Electric force weakens rapidly with increasing distance. Magnetic fields exist around magnetic objects. If a second magnetic object is placed in the field, the two objects experience ...
... field, the two objects experience electric forces that can attract or repel them, depending on the charges involved. Electric force weakens rapidly with increasing distance. Magnetic fields exist around magnetic objects. If a second magnetic object is placed in the field, the two objects experience ...
Newton`s First Law WebPkt.
... Two bricks are resting on edge of the lab table. Shirley Sheshort stands on her toes and spots the two bricks. She acquires an intense desire to know which of the two bricks are most massive. Since Shirley is vertically challenged, she is unable to reach high enough and lift the bricks; she can howe ...
... Two bricks are resting on edge of the lab table. Shirley Sheshort stands on her toes and spots the two bricks. She acquires an intense desire to know which of the two bricks are most massive. Since Shirley is vertically challenged, she is unable to reach high enough and lift the bricks; she can howe ...
Forces Accelerate
... accelerate things as they push or pull them. Remember that a force is a push or a pull. Acceleration means a change in speed. So when you stand on a scale, or place a rock on the triple beam balance gravity is actually accelerating you towards the center of the Earth. And we can measure that acceler ...
... accelerate things as they push or pull them. Remember that a force is a push or a pull. Acceleration means a change in speed. So when you stand on a scale, or place a rock on the triple beam balance gravity is actually accelerating you towards the center of the Earth. And we can measure that acceler ...
Acceleration
... Let the students research one of their favorite scientists. (Oral presentations next meeting, 1 minute each) ...
... Let the students research one of their favorite scientists. (Oral presentations next meeting, 1 minute each) ...
Rotational Kinematics (Part I from chapter 10)
... Point P will rotate about the origin in a circle of radius r Every particle on the disc undergoes circular motion about the origin, O Polar coordinates are convenient to use to represent the position of P (or any other point) P is located at (r, q) where r is the distance from the origin to P and q ...
... Point P will rotate about the origin in a circle of radius r Every particle on the disc undergoes circular motion about the origin, O Polar coordinates are convenient to use to represent the position of P (or any other point) P is located at (r, q) where r is the distance from the origin to P and q ...
Notes and Hints for AP Physics Summer Assignment
... COMPRESSED, WHILE LIQUIDS CAN NOT (liquids have a definite volume). One key property when dealing with fluids is DENSITY, which is the amount of mass a substance has per unit of volume. Density is given by the equation: ρ=m/V density (in kg/m3) = mass (in kg) / volume (in m3) Note that the first sym ...
... COMPRESSED, WHILE LIQUIDS CAN NOT (liquids have a definite volume). One key property when dealing with fluids is DENSITY, which is the amount of mass a substance has per unit of volume. Density is given by the equation: ρ=m/V density (in kg/m3) = mass (in kg) / volume (in m3) Note that the first sym ...
1 PHYSICS 231 Lecture 18: equilibrium & revision
... point in her swing, which of the following is true? A) The tension in the robe is equal to her weight B) The tension in the robe is equal to her mass times her acceleration C) Her acceleration is downward and equal to g (9.8 m/s2) D) Her acceleration is zero E) Her acceleration is equal to her veloc ...
... point in her swing, which of the following is true? A) The tension in the robe is equal to her weight B) The tension in the robe is equal to her mass times her acceleration C) Her acceleration is downward and equal to g (9.8 m/s2) D) Her acceleration is zero E) Her acceleration is equal to her veloc ...
Presentation
... mass m and radius r. The three objects are arranged so that an axis of rotation passes through the center of each object. The rotation axis is perpendicular to the plane of the flat disk. Which of the three objects has the largest moment of inertia? a) The solid sphere and hollow sphere have the sam ...
... mass m and radius r. The three objects are arranged so that an axis of rotation passes through the center of each object. The rotation axis is perpendicular to the plane of the flat disk. Which of the three objects has the largest moment of inertia? a) The solid sphere and hollow sphere have the sam ...
Forces
... • When a big object collides with a little one, the big one hits the little one harder than the little one hits the big one. Wrong! The 3rd Law says they hit it each other with the same force. ...
... • When a big object collides with a little one, the big one hits the little one harder than the little one hits the big one. Wrong! The 3rd Law says they hit it each other with the same force. ...
Ch 8 HW Day 5 (Collisions and Ballistic Pendulum): p 254 – 265, #`s
... Picture the Problem Take the origin to be at the initial position of the right-hand end of raft and let the positive x direction be to the left. Let w denote the woman and r the raft, d be the distance of the end of the raft from the pier after the woman has walked to its front. The raft moves t ...
... Picture the Problem Take the origin to be at the initial position of the right-hand end of raft and let the positive x direction be to the left. Let w denote the woman and r the raft, d be the distance of the end of the raft from the pier after the woman has walked to its front. The raft moves t ...
Work and Energy
... horizontal. The car is acted on by three forces; (i) the normal force; (ii) a force due to air resistance (F=1000 N); (iii) the force of weight. Find work done by each force, and the total work done on the car as it travels a distance of 25 m down the slope. ...
... horizontal. The car is acted on by three forces; (i) the normal force; (ii) a force due to air resistance (F=1000 N); (iii) the force of weight. Find work done by each force, and the total work done on the car as it travels a distance of 25 m down the slope. ...
Forces - Urbana School District #116
... • When a big object collides with a little one, the big one hits the little one harder than the little one hits the big one. Wrong! The 3rd Law says they hit it each other with the same force. ...
... • When a big object collides with a little one, the big one hits the little one harder than the little one hits the big one. Wrong! The 3rd Law says they hit it each other with the same force. ...
Work Done by a Variable Force
... W = K-K0= ½ mv2 – ½ mv02 (50.0 N)(cos180)(d ) = ½(60.0kg)(0m/s)2-1/2(60.0 kg)(25.0 m/s)2 ...
... W = K-K0= ½ mv2 – ½ mv02 (50.0 N)(cos180)(d ) = ½(60.0kg)(0m/s)2-1/2(60.0 kg)(25.0 m/s)2 ...
Kinetic Energy and the Work
... This means that the object has acquired a kinetic energy equal to m g h. Because we can object to a height h, and then drop is and have is acquire a kinetic energy equal to m g h we call the quantity m g h gravitational potential energy. It is potential energy, because it can be turned into actual k ...
... This means that the object has acquired a kinetic energy equal to m g h. Because we can object to a height h, and then drop is and have is acquire a kinetic energy equal to m g h we call the quantity m g h gravitational potential energy. It is potential energy, because it can be turned into actual k ...
Preview for Makeup and Final Exam
... d. Newton's Laws 1. Know Newton’s Second Law and be able to use it in a problem e. Free-Body Diagrams 1. Be able to draw the free-body diagram and solve a complex force problem from start to finish 4. Work/Energy a. Work 1. Be able to use the definition of work to find the work done by various force ...
... d. Newton's Laws 1. Know Newton’s Second Law and be able to use it in a problem e. Free-Body Diagrams 1. Be able to draw the free-body diagram and solve a complex force problem from start to finish 4. Work/Energy a. Work 1. Be able to use the definition of work to find the work done by various force ...
Gravity: a force of attraction between objects that is due to their mass
... unless another force acts upon it. • If it is moving at a certain speed it will stay at that speed unless a force acts on it. • If it is still, then it will stay still unless a force acts on it ...
... unless another force acts upon it. • If it is moving at a certain speed it will stay at that speed unless a force acts on it. • If it is still, then it will stay still unless a force acts on it ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.