Chap4-Conceptual Modules
... When the fly hit the truck, it exerted a force on the truck (only for a fraction of a second). So, in this time period, the truck accelerated (backwards) up to some speed. After the fly was squashed, it no longer exerted a force, and the truck simply continued moving at constant speed. Follow-up: Wh ...
... When the fly hit the truck, it exerted a force on the truck (only for a fraction of a second). So, in this time period, the truck accelerated (backwards) up to some speed. After the fly was squashed, it no longer exerted a force, and the truck simply continued moving at constant speed. Follow-up: Wh ...
Physics Revision: Vectors and Scalars
... (to the right) at 900 to the 4 km and make it exactly 6cm long (1 km ≙ 2 cm; 3km ≙ 6cm). At the end of this line (at 6 cm) you have found the exact position of B. You now join A to B and measure the length of AB. You will find it to be 10 cm long. Now you use the scale in reverse. For every 2 cm you ...
... (to the right) at 900 to the 4 km and make it exactly 6cm long (1 km ≙ 2 cm; 3km ≙ 6cm). At the end of this line (at 6 cm) you have found the exact position of B. You now join A to B and measure the length of AB. You will find it to be 10 cm long. Now you use the scale in reverse. For every 2 cm you ...
MatLab#2 - labsanywhere.net
... Whenever an object moves in a fluid (gas or liquid), the object experiences a drag force that opposes the motion of the object. This is sometimes referred to air resistance in car design, or water resistance in boat hull design. The amount of drag force depends on the speed. The faster something mov ...
... Whenever an object moves in a fluid (gas or liquid), the object experiences a drag force that opposes the motion of the object. This is sometimes referred to air resistance in car design, or water resistance in boat hull design. The amount of drag force depends on the speed. The faster something mov ...
Chapter 2.3
... b) He takes off one of his boots (m = 10 kg) and throws it with a velocity of 10 m/s in the opposite direction of the shore. What’s his velocity (speed and direction)? c) ...
... b) He takes off one of his boots (m = 10 kg) and throws it with a velocity of 10 m/s in the opposite direction of the shore. What’s his velocity (speed and direction)? c) ...
21_Simple_Harmonic_Motion_Edline
... The pendulum will have the same period when it’s moving just a little as when it is moving a lot. The period of a simple pendulum depends on the length of the string and the acceleration of gravity. For a simple pendulum the frequency can be described by the following equation: ...
... The pendulum will have the same period when it’s moving just a little as when it is moving a lot. The period of a simple pendulum depends on the length of the string and the acceleration of gravity. For a simple pendulum the frequency can be described by the following equation: ...
Name
... When an object is in motion on a surface or through a viscous medium, there will be a resistance to the motion o This is due to the interactions between the object and its environment ...
... When an object is in motion on a surface or through a viscous medium, there will be a resistance to the motion o This is due to the interactions between the object and its environment ...
1 Work Hard – Get Smart – No Excuses. Scientist`s Name: FORCES
... Sixth Stop: Find your weight on Other Planets…MASS VS. WEIGHT! http://www.exploratorium.edu/ronh/weight/ 1. Enter in your weight and click “calculate”. On which planet do you weigh the most? _________________ On which planet do you weight the least? _____________________ 2. How much do you weigh on ...
... Sixth Stop: Find your weight on Other Planets…MASS VS. WEIGHT! http://www.exploratorium.edu/ronh/weight/ 1. Enter in your weight and click “calculate”. On which planet do you weigh the most? _________________ On which planet do you weight the least? _____________________ 2. How much do you weigh on ...
Newton`s 1st Law of Motion
... c. What about a ball rolling along a level surface? Since it would not be moving with or against gravity, it would have a constant velocity. Galileo stated that if friction were absent, the ball would move horizontally forever. Initial position ...
... c. What about a ball rolling along a level surface? Since it would not be moving with or against gravity, it would have a constant velocity. Galileo stated that if friction were absent, the ball would move horizontally forever. Initial position ...
Conservation of Momentum AIM To determine the momentum of a
... AIM To determine the momentum of a system before and after an interaction, and to compare these two quantities. Momentum of an object is defined as the product of its mass and velocity. momentum = mass x velocity The symbol for momentum is (logically!?) 'p'. We can therefore write the above definiti ...
... AIM To determine the momentum of a system before and after an interaction, and to compare these two quantities. Momentum of an object is defined as the product of its mass and velocity. momentum = mass x velocity The symbol for momentum is (logically!?) 'p'. We can therefore write the above definiti ...
Rigid Body Dynamics chapter 10 continues
... opening and closing valves. In Figure P10.29, the cam is a circular disk rotating on a shaft that does not pass through the center of the disk. In the manufacture of the cam, a uniform solid cylinder of radius R is first machined. Then an off-center hole of radius R/2 is drilled, parallel to the axi ...
... opening and closing valves. In Figure P10.29, the cam is a circular disk rotating on a shaft that does not pass through the center of the disk. In the manufacture of the cam, a uniform solid cylinder of radius R is first machined. Then an off-center hole of radius R/2 is drilled, parallel to the axi ...
9-Momentum and impulse
... Impulse does NOT change in a collision Ex: a car colliding with another car Equation: J = F∆t • J = impulse (N*s) • F = force (N) • ∆t = time (s) ...
... Impulse does NOT change in a collision Ex: a car colliding with another car Equation: J = F∆t • J = impulse (N*s) • F = force (N) • ∆t = time (s) ...
Mechanics Notes 2011
... ABOVE EQUATIONS TO DISTINGUISH THEM. How much of the following table can you complete? Equation Quantities SI Units ...
... ABOVE EQUATIONS TO DISTINGUISH THEM. How much of the following table can you complete? Equation Quantities SI Units ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.