Momentum - USU Physics
... Example 1: A 100kg boulder rolling towards a castle gate at 3m/s. Momentum boulder: P = m.v = 100 x 3 = 300 kg.m/s Example 2: A 1 kg missile flying towards the castle gate at 300 m/s (speed of sound). Momentum missile: P = m.v = 1 x 300 = 300 kg.m/s • Result: Different objects can have the same mome ...
... Example 1: A 100kg boulder rolling towards a castle gate at 3m/s. Momentum boulder: P = m.v = 100 x 3 = 300 kg.m/s Example 2: A 1 kg missile flying towards the castle gate at 300 m/s (speed of sound). Momentum missile: P = m.v = 1 x 300 = 300 kg.m/s • Result: Different objects can have the same mome ...
Experiment 6 Newton`s Second Law A mass is allowed to fall
... Analysis Draw free-body diagrams for the two masses, m1 and m2 . Apply Newton's Second Law and derive (3). Complete the calculations of the average velocities for the data. First calculate the distance from one data point to the second data point away, s . Then find the average velocity by dividing ...
... Analysis Draw free-body diagrams for the two masses, m1 and m2 . Apply Newton's Second Law and derive (3). Complete the calculations of the average velocities for the data. First calculate the distance from one data point to the second data point away, s . Then find the average velocity by dividing ...
Forces between masses
... mass of the first point mass in kilograms (kg), m2 is the mass of the second point mass in kilograms (kg) and d is the distance between the two point masses in metres (m). For any large objects (not point masses) we use the distance from the centre of the object(s) to do the calculation. This is ver ...
... mass of the first point mass in kilograms (kg), m2 is the mass of the second point mass in kilograms (kg) and d is the distance between the two point masses in metres (m). For any large objects (not point masses) we use the distance from the centre of the object(s) to do the calculation. This is ver ...
Work and Kinetic Energy
... acting on an object when the point of application of that force moves through some distance and the force has a component along the line of motion. Next, we define kinetic energy, which is energy an object possesses because of its motion. In general, we can think of energy as the capacity that an obj ...
... acting on an object when the point of application of that force moves through some distance and the force has a component along the line of motion. Next, we define kinetic energy, which is energy an object possesses because of its motion. In general, we can think of energy as the capacity that an obj ...
Q1 – Linear Acceleration – revision
... A car is travelling at a uniform speed of 14 m s-1 when the driver notices a traffic light turning red 98 m ahead. Find the minimum constant deceleration required to stop the car at the traffic light, (i) if the driver immediately applies the brake (ii) if the driver hesitates for 1 second before ap ...
... A car is travelling at a uniform speed of 14 m s-1 when the driver notices a traffic light turning red 98 m ahead. Find the minimum constant deceleration required to stop the car at the traffic light, (i) if the driver immediately applies the brake (ii) if the driver hesitates for 1 second before ap ...
Chapter #5 energy-homework
... 4. What happens to an object’s velocity if there is work done by a friction force? Why? 5. An object is suspended from a spring and is at equilibrium; does the elastic force do any work? 6. It is known that water applies some pressure on a container; does water do any work in this case? 7. What kind ...
... 4. What happens to an object’s velocity if there is work done by a friction force? Why? 5. An object is suspended from a spring and is at equilibrium; does the elastic force do any work? 6. It is known that water applies some pressure on a container; does water do any work in this case? 7. What kind ...
PROBLEMS ON MECHANICS
... ing string or rod undergoes a virtual This allows us to write down the conlengthening of ∆x, then T = (∆Π − dition of torque balance for the hanging portion of the rope (as we know the ho∑i δ⃗xi · ⃗Fi )/∆x. rizontal coordinate of its centre of mass). The method can also be used for find- The next pr ...
... ing string or rod undergoes a virtual This allows us to write down the conlengthening of ∆x, then T = (∆Π − dition of torque balance for the hanging portion of the rope (as we know the ho∑i δ⃗xi · ⃗Fi )/∆x. rizontal coordinate of its centre of mass). The method can also be used for find- The next pr ...
Kinetic Energy & Work
... • The simple methods we’ve learned using Newton’s laws are inadequate when the forces are not constant. • In this chapter, the introduction of the new concepts of work, energy, and the conservation of energy will allow us to deal with such problems. ...
... • The simple methods we’ve learned using Newton’s laws are inadequate when the forces are not constant. • In this chapter, the introduction of the new concepts of work, energy, and the conservation of energy will allow us to deal with such problems. ...
AP® Physics B - Mater Academy Lakes High School
... II. The direction of any electric current is the direction of flow of positive charge (conventional current). III. For any isolated electric charge, the electric potential is defined as zero at an infinite distance from the charge. IV. For mechanics and thermodynamics equations, W represents the wor ...
... II. The direction of any electric current is the direction of flow of positive charge (conventional current). III. For any isolated electric charge, the electric potential is defined as zero at an infinite distance from the charge. IV. For mechanics and thermodynamics equations, W represents the wor ...
Meter Stick Balance
... location of the fulcrum to 3 significant figures. 3. Move both outer knife-edges inward until each is 8.0 cm from the actual fulcrum location. Adjust the masses of each hangar to exactly 145 grams total (this includes the mass of the hangar itself). 4. If necessary adjust the right-hand side mass to ...
... location of the fulcrum to 3 significant figures. 3. Move both outer knife-edges inward until each is 8.0 cm from the actual fulcrum location. Adjust the masses of each hangar to exactly 145 grams total (this includes the mass of the hangar itself). 4. If necessary adjust the right-hand side mass to ...
newton`s second law of motion—force and acceleration
... cannonball and a 1-kg stone dropped from an elevated position at the same time will fall together and strike the ground at practically the same time. This experiment, said to be done by Galileo from the Leaning Tower of Pisa and shown in Figure 6.8, demolished the Aristotelian idea that an object th ...
... cannonball and a 1-kg stone dropped from an elevated position at the same time will fall together and strike the ground at practically the same time. This experiment, said to be done by Galileo from the Leaning Tower of Pisa and shown in Figure 6.8, demolished the Aristotelian idea that an object th ...
Stacey Carpenter - University of Hawaii System
... Weight is a force. It is mass and acceleration multiplied. But where does the acceleration come from? Gravity. Just like all mass has inertia, all mass has gravity. All objects are attracted to each other by gravity. It is the force of gravity between Earth's mass and the mass of your body that caus ...
... Weight is a force. It is mass and acceleration multiplied. But where does the acceleration come from? Gravity. Just like all mass has inertia, all mass has gravity. All objects are attracted to each other by gravity. It is the force of gravity between Earth's mass and the mass of your body that caus ...
Classical central-force problem
In classical mechanics, the central-force problem is to determine the motion of a particle under the influence of a single central force. A central force is a force that points from the particle directly towards (or directly away from) a fixed point in space, the center, and whose magnitude only depends on the distance of the object to the center. In many important cases, the problem can be solved analytically, i.e., in terms of well-studied functions such as trigonometric functions.The solution of this problem is important to classical physics, since many naturally occurring forces are central. Examples include gravity and electromagnetism as described by Newton's law of universal gravitation and Coulomb's law, respectively. The problem is also important because some more complicated problems in classical physics (such as the two-body problem with forces along the line connecting the two bodies) can be reduced to a central-force problem. Finally, the solution to the central-force problem often makes a good initial approximation of the true motion, as in calculating the motion of the planets in the Solar System.