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BHS 120.2 – Optics II Notetaker: Michael Christian Date: 01/29/2013, 2nd hour Page1 We had recitation second hour….. Q1 Your patient reads 1.0 M print size @ 100 cm. You enlarge the print to measure 2.5 M and position it @ 40 cm. Find angular Magnification. M r.s. = New size/ Old size = 2.5/1.0 = 2.5x M r.d. = q/q’ =100/40 = 2.5x M ang. = (M r.d. )(M r.s). = 6.25 X Q2 Patient uses a +10.00 D hand-held magnifier. You tell him to hold the magnifier at 10 cm from his eye. The angular Mag will be Less than Effective Mag. Effective mag M25 = Pe/4 = 10.00/4 = 2.50x Angular Mag M ang= kPe+1 = (0.10)(10)+1 = 1+1 = 2.00x Q3 Patient’s BCVA= 0.3/4.0M Target visual acuity= 1.0M Which of the following options is most suitable for your 65 y/o patient? +13.33 D hand-held magnifier with target print located -7.5cm from the magnifier. Target Acuity= ¼ of BCVA Equivalent viewing distance= 30cm/4= 7.5 cm Equivalent viewing power= 1/0.075 m = 13.33 D Q4 Your patient is using a +15 D hand held magnifier while holding it 5 cm from his +2 D Bifocal ADD. The equivalent power of the magnifier-ADD combo is greater than the power of the magnifier alone. Pe = P1+P2-(c)(P1)(P2) = 15+2- [(0.05)(15)(2)] = +15.50 D Q5 Where must the patient hold the magnifier in relation to the object so that there is no accommodative demand? 1/Pe = 1/15.5 D = 6.45 cm BHS 120.2 – Optics II Notetaker: Michael Christian Date: 01/29/2013, 2nd hour Page2 Q6 The objective lens of a telescope has a secondary focal length of +12 cm. The ocular lens has a primary focal length of +4 cm. Select the INCORRECT statement: A) The exit pupil is virtual. B) Tube length of this TS is afocal setting is 8cm. C) It is a Galilean TS. D) The image formed by this TS is inverted. M T.S.= f’ obj/ f ocular = 12/4 = 3X This means the image is magnified and UPRIGHT. NOT inverted. Q7 The objective lens of a given telescope has a secondary focal length of +12cm. The eye piece has a primary focal length of -3.00cm. Select the CORRECT statement. 1) It is a Galilean TS. 2) Image formed by this TS is upright. 3) Tube length of this TS in afocal setting is 9.00cm. 4) Exit pupil is real. Q8 Decreasing the tube length of the telescope creates Divergence in the telescope. Q9 Increasing the tube length of the telescope adapts it for an uncorrected Hyperope. Q10 Your patient lifts her stand magnifier (Pe = +15.00 D; column height = 3.5 cm) so that the base of the magnifying lens is 4.5 cm off the printed material. Describe the resulting image. 1) Virtual 2) Inverted 3) Minified 4) Located between PPF and 2 PPF Q11) Patient’s BCVA is 0.4/2.0 M. Target acuity is 0.5 M. You prescribe a stand magnifier with +13 D lens, fixed at 3.5cm from its base. Select the statement that is INCORRECT. 1) The equivalent viewing distance is -10cm. 2) The enlargement ratio is +4.00 X 3) The virtual image is located at -6.42cm from magnifier. 4) None of the above. Q12 A stand magnifier with an enlargement ratio of 3.00X creates an image at |10cm| from the magnifying lens. Find the dioptric power of the magnifying lens. M=3X l= -10cm L’=-10D L=3.00/-10.00=-30 D L’=L+P P=+20D