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Chapter 4 Analyzing Linear Equations 4.1 Rate of Change & Slope • Rate of Change- a ratio that describes, on average, how much one quantity changes compared to another Change in y Rate of change= x Change in x y Negative slope Ex: Time Walking(sec) +1 +1 +1 Distance Walked(ft) 1 4 2 8 3 12 4 Positive slope 16 4 +4 = 4 ft/sec Rate of change = +4 +4 1 Zero slope Undefined slope • Slope- the ratio of the change in y-coordinates over the change in x-coordinates for a line rise Slope= Slope: y2 – y1 run m= x2 – x1 Ex: Find the slope (4, 6) (-1, 2) x1 y1 x2 y2 Ex: 26 4 4 m 1 4 5 5 Ex: m 5 5 10 5 6 11 Find the value of r so that the line through (10, r) and (3, 4) has x y x y a slope of -2/7 2(7) 7(4 r ) 2 4r 14 28 7r 1 7 3 10 Plug in the m and the coordinates for the slope Simplify and solve for r -28 -28 -14= -7r /-7 /-7 1 2 r=2 2 4.2 Slope and Direct Variation • Direct Variation- a proportional relationship y = kx *this represents a constant rate of change and k is the constant of variation Ex: a. Name the constant of variation k = -1/2 b. Find the slope m 20 2 1 40 4 2 c. Compare slope and the constant of variation. What do you notice? They are the same thing • y Graph a direct Variation: 1. Write the slope as a ratio 2. Start at the origin (0, 0) 3. Move up and across according to the slope 4. Draw a line to connect the ordered pairs x a. y = 4x 4 m 1 Up 4 and right 1 b. y = -1/3x m 1 3 Down 1 and right 3 4.3 Slope-Intercept Form y = mx + b slope y-intercept Ex: Write an equation in slopeintercept form given slope and the y-intercept a. Slope = 3 y-intercept = -5 y = 3x - 5 b. y-intercept= (0, 6) m = 2/5 y = 2/5x + 6 Ex: Graph from an equation: Write an equation in slope-intercept form given a graph. 1. write the slope as a ratio and yintercept as an ordered pair 2. Graph the y-intercept 2 3 5 m 0 3 3 3. Use slope to find other points and connect with a line y-intercept= (0, 2) So b=2 Graph an equation given in slope-intercept form Ex: y a. y = -2/3x + 1 m = -2/3 y-int= (0, 1) y = 5/3x + 2 b. 5x – 3y = 6 x 5x – 3y = 6 -5x -5x -3y = -5x + 6 /-3 y = 5/3x - 2 /-3 m = 5/3 y-int= (0, -2) 6.7 Graphing Inequalities with Two Variables • • The equation makes the line to define the boundary The shaded region is the half-plane 1. 2. Get the equation into slope-intercept form List the intercept as an ordered-pair and the slope as a ratio Graph the intercept and use the slope to find at least 2 more points Draw the line (dotted or solid) Test an ordered-pair not on the line 3. 4. 5. 1. 2. If it is true shade that side of the line If it is false shade the other side of the line Ex1: < or > or Dotted Line Solid Line y 2x - 3 m= 2 1 b = -3 = (0, -3) Use a solid line because it is Test: (0, 0) 0 2(0) – 3 0 0 – 3 0 -3 false (shade other side) • Ex2: y – 2x < 4 y – 2x < 4 + 2x +2x y < 2x + 4 m= 2 Use a dotted line because it is < 1 b = 4 = (0, 4) Test: (0, 0) 0 < 2(0) + 4 0 < 0+4 0 <4 true (shade this side) • Ex3: 3y - 2 > -x + 7 3y – 2 > -x + 7 +2 +2 3y > -x + 9 /3 /3 /3 1 x+3 3 y>- 1 m=Use a dotted line because it is > 3 b = 3 = (0, 3) Test: (0, 0) 1 3 0 > - (0) + 3 0 > 0+3 0 >3 false (shade other side) 4.4 Writing Equations in SlopeIntercept Form y = mx + b slope y-intercept Write an equation given slope and one point Ex. Write the equation of the line that passes through (1, 5) with slope 2 y = mx + b y = 2x + b Replace m with the slope 5 = 2(1) + b Replace the x and y with the ordered pair coordinates 5=2+b Solve for b (the y-intercept) -2 -2 3=b y = 2x + 3 Replace the numbers for slope and the y-intercept Write an equation given two points Ex. Write an equation for the line that passes through (-3, -1) and (6, -4) y = mx + b m 4 1 3 1 6 3 9 3 Find slope y = -1/3x + b Replace m with the slope -1 = -1/3(-3) + b Replace the x and y with one of the ordered pair coordinates -1 = 1 + b -1 -1 Solve for b (the y-intercept) -2 = b y = -1/3x - 2 Replace the numbers for slope and the y-intercept 4.5 Writing Equations in Point-Slope Form Point-Slope Form: y – y1 = m(x – x1) Ex: Write an equation given slope and one point Write the equation of a line that passes through (6, -2) with slope 5 y – y1 = m(x – x1) Replace m with the slope and y1 and x1 with the ordered pair y – -2= 5(x – 6) Simplify y + 2 = 5(x – 6) Ex: Write an equation of a horizontal line Write the equation for the line that passes through (3, 2) and is horizontal y – y1 = m(x – x1) y – 2 = 0(x – 3) y – 2 =0 y=2 Replace m with the slope and y1 and x1 with the ordered pair Simplify Ex: Write an equation in Standard Form y + 5= -5/4(x -2) 4[y + 5= -5/4(x -2)] Multiply by 4 Distribute 4y + 20= -5(x -2) 4y + 20= -5x + 10 Add 5x(move it to the other side) +5x +5x 5x + 4y + 20= 10 - 20 -20 5x + 4y = -10 Subtract 20(move it to the other side) Ex: Write an equation in SlopeIntercept Form y -2= ½(x+ 5) 2[y -2= ½(x+ 5)] 2y -4= x+ 5 +4= +4 2y = x+ 9 /2 /2 y = 1/2x+ 9/2 Multiply by 2 Add 4(move it to the other side) Divide by 2 Simplify Simplify Ex: Write an equation in Point-Slope Form given two points Write the equation for the line that passes through (2, 1) (6, 4) 4 1 3 m 62 4 y - 1= 3/4(x -2) or y - 4= 3/4(x -6) Find slope Replace m with slope and y1 and x1 with one of the ordered pairs 4.6 Statistics: Scatter Plots and Lines of Fit • Scatter Plot- a graph in which two sets of data are plotted as ordered pairs in a coordinate plane – Used to investigate a relationship between two quantities Positive Correlation Negative Correlation No Correlation • If the data points do not lie in a line, but are close to making a line you can draw a Line of Fit – This line describes the trend of the data (once you have this line you can use ordered pairs from it to write an equation) years Ex: Vertical Drop 1 3 5 8 12 12 13 15 151 156 225 230 306 300 255 400 a. Make a scatter plot 500 400 300 b. Draw a line of fit. What correlation do you find? Positive correlation c. Write an equation in slope-intercept form for the line (8, 230) (12, 306) Find slope 200 m= 19 100 1 3 5 7 9 11 13 15 Plug in an ordered pair and slope to find the y-intercept y = 19x +78 4.7 Geometry : Parallel and Perpendicular Lines • Parallel lines- do not • Perpendicular linesintersect and have the make right angles and same slope have opposite slopes c a b Line a has slope 6/5 Line b has slope 6/5 d Line c has slope 3/2 Line d has slope -2/3