Survey
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
* Your assessment is very important for improving the work of artificial intelligence, which forms the content of this project
Evidence that DNA can transform bacteria • Frederick Griffith (1928) – Streptococcus pneumoniae bacteria – transformation • Mouse Experiment • Experiment proved that transformation can happen • Avery and colleagues (1944) – announced transformation agent was DNA Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.2 Can the genetic trait of pathogenicity be transferred between bacteria? EXPERIMENT Bacteria of the “S” (smooth) strain of Streptococcus pneumoniae are pathogenic because they have a capsule that protects them from an animal’s defense system. Bacteria of the “R” (rough) strain lack a capsule and are nonpathogenic. Frederick Griffith injected mice with the two strains as shown below: Living S (control) cells Living R Heat-killed (control) cells (control) S cells Mixture of heat-killed S cells and living R cells RESULTS Mouse dies Mouse healthy Mouse healthy Mouse dies Living S cells are found in blood sample. CONCLUSION Griffith concluded that the living R bacteria had been transformed into pathogenic S bacteria by an unknown, heritable substance from the dead S cells. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Evidence that viral DNA can program cells • Alfred Hershey and Martha Chase (1952) – bacteriophages or phages (viruses that infect bacteria) – discovered DNA is the genetic material NOT protein • Blender experiment Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.3 Viruses infecting a bacterial cell Phage head Tail Tail fiber Bacterial cell Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 100 nm DNA Additional evidence that DNA is the genetic material • Erwin Chargaff (1947) – Chargaff’s rules – The equivalences for any given species between the number of A and T and G and C bases are equal. • Analyzed DNA from different organisms – Humans 30.3% of bases were A’s – E. Coli 26% of bases were A’s Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Rosalind Franklin – (1950’s) – X-ray diffraction photo of DNA – helped Watson and Crick develop their model of DNA structure Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.6 Rosalind Franklin and her X-ray diffraction photo of DNA (a) Rosalind Franklin Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (b) Franklin’s X-ray diffraction Photograph of DNA Structure of DNA • Watson & Crick – (1953) – 1 page paper in the British journal Nature “Molecular Structure of Nucleic Acids: A Structure for Deoxynucleic acids” Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.1 Watson and Crick with their DNA model Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.5 The structure of a DNA strand Sugar-phosphate backbone 5 end 5 O P O CH2 Nitrogenous bases CH3 O– O– 4 H H 3 O H O 1 N N H H O Thymine (T) H 2 H O O P O CH2 O– H H N O H H H H Adenine (A) H H O P O H N N H O N N H CH2 O– H O H N H N H N H H O Cytosine (C) H O O 5 P O CH2 H O 1 O– 4 H H Phosphate H H 2 3 H OH Sugar (deoxyribose) 3 end N O N Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings N N H N H H Guanine (G) DNA nucleotide Figure 16.7 The double helix G 5 end C O A T –O T A P OH O H2C Hydrogen bond O O C C 3.4 nm G –O P O O G T A –O A T O CH2 G O P O O H2C O O A T P O– O T A OH 3 end G C 0.34 nm A CH2 O O– P O O O C O O O O O– P C O H2C A CH2 O O H2C O G T O O T A C –O P A T 1 nm G 3 end OH T (a) Key features of DNA structure O CH2 O O– P O O 5 end (b) Partial chemical structure Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (c) Space-filling model Figure 16.8 Base pairing in DNA H N N N N Sugar O H H CH3 N N N O Sugar Thymine (T) Adenine (A) H O N N Sugar N H H N N N N N H Guanine (G) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings H O Sugar Cytosine (C) Unnumbered Figure p. 298 Purine + Purine: too wide Pyrimidine + pyrimidine: too narrow Purine + pyrimidine: width Consistent with X-ray data Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings DNA Replication Section 16.2 • Semi-conservative model – each of the two daughter molecules will have one old strand, derived from the parent molecules, and one newly made strand Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.9 A model for DNA replication: the basic concept (layer 1) A T C G T A A T G C (a) The parent molecule has two complementary strands of DNA. Each base is paired by hydrogen bonding with its specific partner, A with T and G with C. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.9 A model for DNA replication: the basic concept (layer 2) A T A T C G C G T A T A A T A T G C G C (a) The parent molecule has two complementary strands of DNA. Each base is paired by hydrogen bonding with its specific partner, A with T and G with C. (b) The first step in replication is separation of the two DNA strands. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.9 A model for DNA replication: the basic concept (layer 3) T A T A T A C G C G C T A T A T A A T A T A T G C G C G C G A T C G T A A C G (a) The parent molecule has two complementary strands of DNA. Each base is paired by hydrogen bonding with its specific partner, A with T and G with C. (b) The first step in replication is separation of the two DNA strands. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings T (c) Each parental strand now serves as a template that determines the order of nucleotides along a new, complementary strand. Figure 16.9 A model for DNA replication: the basic concept (layer 4) T A T A T A C G C G C T A T A T A A T A T A T G C G C G C G A T A T A T C G C G C G T A T A T A T A T A T C G C G C A G (a) The parent molecule has two complementary strands of DNA. Each base is paired by hydrogen bonding with its specific partner, A with T and G with C. (b) The first step in replication is separation of the two DNA strands. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (c) Each parental strand now serves as a template that determines the order of nucleotides along a new, complementary strand. (d) The nucleotides are connected to form the sugar-phosphate backbones of the new strands. Each “daughter” DNA molecule consists of one parental strand and one new strand. Figure 16.10 Three alternative models of DNA replication Parent cell (a) Conservative model. The two parental strands reassociate after acting as templates for new strands, thus restoring the parental double helix. (b) Semiconservative model. The two strands of the parental molecule separate, and each functions as a template for synthesis of a new, complementary strand. (c) Dispersive model. Each strand of both daughter molecules contains a mixture of old and newly synthesized DNA. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings First replication Second replication Figure 16.13 Incorporation of a nucleotide into a DNA strand New strand Template strand Sugar A Base Phosphate 3’ end 5’ end 3’ end 5’ end T A T C G C G G C G C A T A P OH P Pyrophosphate 3’ end C C OH Nucleoside triphosphate 2 P 5’ end Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 5’ end Figure 16.12 Origins of replication in eukaryotes Origin of replication 1 Replication begins at specific sites where the two parental strands separate and form replication bubbles. Bubble Parental (template) strand Daughter (new) strand 0.25 µm Replication fork 2 The bubbles expand laterally, as DNA replication proceeds in both directions. 3 Eventually, the replication bubbles fuse, and synthesis of the daughter strands is complete. Two daughter DNA molecules (a) In eukaryotes, DNA replication begins at many sites along the giant DNA molecule of each chromosome. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings (b) In this micrograph, three replication bubbles are visible along the DNA of a cultured Chinese hamster cell (TEM). Figure 16.14 Synthesis of leading and lagging strands during DNA replication 1 DNA pol Ill elongates DNA strands only in the 5 3 direction. 3 5 Parental DNA 2 One new strand, the leading strand, can elongate continuously 5 3 as the replication fork progresses. 5 3 Okazaki fragments 2 1 3 5 3 The other new strand, the lagging strand must grow in an overall 3 5 direction by addition of short segments, Okazaki fragments, that grow 5 3 (numbered here in the order they were made). DNA pol III Template strand 3 Leading strand Lagging strand 2 Template strand 1 DNA ligase Overall direction of replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 4 DNA ligase joins Okazaki fragments by forming a bond between their free ends. This results in a continuous strand. Figure 16.15 Synthesis of the lagging strand 1 Primase joins RNA nucleotides into a primer. 3 5 5 3 Template strand 2 RNA primer 3 5 3 DNA pol III adds DNA nucleotides to the primer, forming an Okazaki fragment. 5 3 1 After reaching the next RNA primer (not shown), DNA pol III falls off. Okazaki fragment 3 3 5 1 5 4 After the second fragment is primed. DNA pol III adds DNA nucleotides until it reaches the first primer and falls off. 5 3 5 3 2 5 1 DNA pol 1 replaces the RNA with DNA, adding to the 3 end of fragment 2. 5 3 6 3 2 DNA ligase forms a bond between the newest DNA and the adjacent DNA of fragment 1. 5 3 5 1 7 The lagging strand in this region is now complete. 3 2 1 Overall direction of replication Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 5 Table 16.1 Bacterial DNA replication proteins and their functions Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.16 A summary of bacterial DNA replication Overall direction of replication Lagging Leading strand Origin of replication strand 1 Helicase unwinds the parental double helix. 2 Molecules of single- 3 The leading strand is strand binding protein synthesized continuously in the stabilize the unwound 5 3 direction by DNA pol III. template strands. DNA pol III Lagging strand OVERVIEW Leading strand Leading strand 5 3 Parental DNA 4 Primase begins synthesis of RNA primer for fifth Okazaki fragment. 5 DNA pol III is completing synthesis of the fourth fragment, when it reaches the RNA primer on the third fragment, it will dissociate, move to the replication fork, and add DNA nucleotides to the 3 end of the fifth fragment primer. Replication fork Primase DNA pol III Primer 4 Lagging strand 3 6 DNA pol I removes the primer from the 5 end of the second fragment, replacing it with DNA nucleotides that it adds one by one to the 3’ end of the third fragment. The replacement of the last RNA nucleotide with DNA leaves the sugarphosphate backbone with a free 3 end. Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings DNA ligase DNA pol I 2 1 3 5 7 DNA ligase bonds the 3 end of the second fragment to the 5 end of the first fragment. Proofreading and repairing DNA • Errors do occur – 1 in 10 billion nucleotides on entire DNA – 1 in 100,000 for incoming nucleotides • Proofreading is done by DNA pol III as it attaches new nucleotides • Mismatch repair cells use special enzymes to fix mismatched nucleotides – A-C for example Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.17 Nucleotide excision repair of DNA damage 1 A thymine dimer distorts the DNA molecule. 2 A nuclease enzyme cuts the damaged DNA strand at two points and the damaged section is removed. Nuclease 3 Repair synthesis by a DNA polymerase fills in the missing nucleotides. DNA polymerase DNA ligase Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 4 DNA ligase seals the Free end of the new DNA To the old DNA, making the strand complete. Telomeres • Repeated units of bases – TTAGGG in humans • Do NOT contain genes • They protect the genes from being eroded (getting shorter and shorter) through DNA replication rounds Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.18 Shortening of the ends of linear DNA molecules 5 End of parental DNA strands Leading strand Lagging strand 3 Last fragment Previous fragment RNA primer Lagging strand 5 3 Primer removed but cannot be replaced with DNA because no 3 end available for DNA polymerase Removal of primers and replacement with DNA where a 3 end is available 5 3 Second round of replication 5 New leading strand 3 New lagging strand 5 3 Further rounds of replication Shorter and shorter daughter molecules Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Figure 16.19 Telomeres 1 µm Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings