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Lecture 25: Quantitative Traits V Date: 11/19/02 Environmental variation Resemblance of relatives Parent-offspring regression Types of Environmental Effects General environmental effects are trait-affecting factors that are shared by groups of individuals. local habitat effects maternal effects Special environmental effects are the residual deviations from the expected phenotype given genetic and general environmental effects. microenvironmental variation developmental noise measurement error Genotype x Environment Effect If different genotypes respond to environmental change in different ways (e.g. trait increases for one genotype, but decreases for another when moved from environment A to B), then there are genotype by environment effects. Here, we develop our general linear model for all genetic and environmental effects to give us a final model for PHENOTYPE. Linear Model for Phenotypes E : general environmental effect e : specific environmental effect I : genotype by environment interaction effect. zijk : phenotype of kth individual of the ith genotype in the jth general environment. zijk Gi I ij E j eijk Properties of Full Linear Model Genotypic value Gi are linear functions of additive, dominance, and epistatic effects. Terms are mean 0 deviations from lower order expectations. m G zijk is mean phenotype in population. Gi is the expected phenotype of genotype i averaged over all environmental conditions. mG + Ej is mean phenotype of all genotypes if they are assayed in jth general environment. Gi + Iij + Ej is expected phenotype of genotype i in the jth general environment. Example – Thrips Daisy Line 1 2 3 G I Thrip Line II III E 77 61 40 59.33 34 159 71 88.00 47 51 107 68.33 -19.22 18.44 0.78 mG = 71.89 - Average density of thrips reported from replicated experiments. - Specific environmental effect is small and ignored in the analysis. Example – Thrips Daisy Line 1 2 3 G I Thrip Linephenotype of Expected Mean trait value obtained genotype 1, calculated II III bybyassuming averagingequal over weight for each cell and environments (equal 34averaging weights)47 77 61Average 159 51 environmental across 40effect is average 71 107 genotypes in this 59.33 88.00 68.33 environment (plant line), E -19.22 18.44 0.78 mG = 71.89 mean phenotype. - Average densitysubtracting of thrips reported from replicated experiments. - Error is small and ignored in the analysis. Example – Thrip Interactions Because we are assuming measurement error and microenvironmental effects are small (eijk = 0), we can estimate interaction effects. I ij zij Gi E j II,1 = 36.89 III,1 = -34.78 IIII,1 = -2.11 II,2 = -16.78 III,2 = 52.56 IIII,2 = -35.78 II,3 = -20.11 III,3 = -17.78 IIII,3 = 37.89 Variance I and e are uncorrelated with the other variables: s s s 2s G, E s s 2 P 2 G 2 I 2 E 2 e sG,E is genotype-environment covariance. It measures the physical association of genotypes and environments. If individuals are randomly distributed by environment, then it is 0. sI is a measure of the variation in phenotypic response to specific environments. Genotype-Environment Covariance There is no way to estimate sG,E. It is confounded with genetic variance and results in biased estimates of genetic variance. Experimental design can reduce, but you cannot always control for: limited seed/pollen dispersal genetically-based social structure maternal/paternal effects Example – Two-Way ANOVA Trait Var(G) Var(E) Var(I) Var(e) Longest leaf length Longest leaf width 26.7 29.5 6.1 37.7 27.5 7.8 3.6 61.3 Grow various plant clones (each clone is different genotype) in three different sites (sand dunes, grassland, marsh) . Example – Two-Way ANOVA Trait Var(G) Var(E) Var(I) Longest 26.7 29.5 6.1 Variance among leaf length Clone by site Variance within Var(e) 37.7 three sites Among-clone variance is an within clones sites Longest estimates 27.5 7.8 3.6 61.3 variance estimates estimate ofestimates the specific leaf width generalgenotype total genetic byenvironmental environmental variance. environment effects. Two-way ANOVA with factors clone (genotype) and effects. variance. environment. Estimating Variance Components We have partitioned phenotypic variance of trait into various components. We still need methods to estimate the components. Genetic and environmental sources of variance contribute differently to different types of relatives. Use this fact to estimate components. To show that there are differences between relative types, we derive expressions for phenotypic covariance between relatives. Covariance of Relatives Consider two relatives x and y. Covariance of one z x = G x + Ex + e x genotypic value with environment of other. zy = Gy + Ey + ey ex and ey do not contribute to resemblance. s x, y s Gx Ex ex , Gy E y ey s G x, y s G , E x, y s G , E y, x s E x, y Assume No GenotypeEnvironment Covariance Experiment can be designed to remove such crossed genotype by environment covariance. One can assume these covariance terms are nonzero. If they are not, they are absorbed in the genetic variance. s x, y s G x, y s E x, y Relatedness Relatedness is defined with respect to an identified frame of reference. In the global frame of reference, we are all related. Usually assume that founders of the observed pedigree are unrelated. Then, relatedness is determined by IBD status of alleles. Coefficient of Identity Individuals are inbred if they contain pairs of alleles which are IBD. We know there are 9 identity states (next slide). With each identity state is associated a probability Di, a condensed coefficient of identity. All 9 coefficients define the complete identity state probability distribution of single loci in two individuals. Possible IBD Status S1 S2 S3 S4 S5 S6 S7 S8 S9 Identity State Distributions Relative Type 1 2 3 4 5 6 7 8 9 Parent/ Offspring 0 0 0 0 0 0 0 1 0 Full Sibs 0 0 0 0 0 0 ¼ ½ ¼ Coefficient of Coancestry AKA: coefficient of consanguinity / kinship / de parente It is the probability that two alleles selected randomly from two individuals, one from each individual, are IBD. 1 1 D1 D 3 D 5 D 7 D 8 2 4 P(2 alleles are IBD | IBD state 8) Inbreeding Coefficient The inbreeding coefficient of an individual is the probability that the two alleles they have at a locus are IBD. This is merely the coefficient of ancestry of the individual’s parents. f z xy Coefficient of Coancestry for Self S7 1 xx PIBD IBD state 7 2 Coefficient of Coancestry of Self with Inbreeding xx Psame selected and IBD S 7 Pdifferent selected and IBD S 7 1 1 1 f x 2 2 1 1 f x 2 Coefficient of Ancestry for Parent/Offspring Assume non-inbred parent and offspring: po 1 4 Assume parent inbred with inbreeding coefficient fp: po Pdraw passed gene from both and IBD S8 Pdraw passed gene from child and non - passed from parent and IBD S8 1 1 1 f p 4 4 Coefficient of Ancestry for Parent/Offspring Suppose offspring is inbred with inbreeding coefficient fo: po Pdraw passed gene in parent and offspring and IBD S8 Pdraw other parent gene from offspring and IBD S8 1 1 1 f o 4 2 Most general equation: po 1 1 f p 2 f o 4 Coefficient of Ancestry for Full Sibs 1 xy 2 f m f f 4 mf 8 Inbreeding coefficient of mother Inbreeding coefficient of father Coefficient of coancestry of mother and father Coefficient of Fraternity The probability that the single-locus genotype of two individuals are identical by descent is the coefficient of fraternity. Coefficient of Fraternity px my mx m y px mx mx p y py mx px p y x y D xy mx my px p y mx p y px my Example - Dxy Consider full sibs: Then they share a mother and father (mx = my = m and px = py = p). D xy mm pp 2 mp What if the parents are unrelated? What if the parents are not inbred? Example - Dxy Consider half sibs sharing a father: px = py = p D xy mx my pp mx p pmy What if the parents are unrelated? What if the parents are not inbred? Genetic Covariance Assume autosomal loci Assume random mating Assume unlinked loci Assume linkage equilibrium Assume no maternal effects Assume genotype-environment covariance and interaction are ~0. Assume no sexual dimorphism Assume no selection Genotypic Values of Two Individuals Gijkl x m G ix xj kx lx ijx klx ik il jk jl x x ikl x x x jkl kij lij x x x x ijkl Gijkl y m G iy jy ky ly ijy kly ik il jk jl y y ikl y y y jkl kij lij y y y Gx Ax Dx AAx ADx DDx y ijkl Genetic Covariance The effects are uncorrelated within and between individuals if the assumptions are met. s G x, y s A x, y s D x, y s AA x, y s AD x, y s DD x, y Now, write each term as a function of variance components and coefficients of relationship. Additive Genetic Covariance Mean effects are 0 by definition. s A x, y Eix xj kx lx iy jy ky ly E E E ix iy E ix iy IBD PIBD E ix iy not IBD Pnot IBD 2 i xy x i x j y i jy 4E i2 xy s A x, y 2xys A2 Dominance Genetic Variance E ijx ijy E ij2 IBD genotype PIBD genotype E ijx ijy not IBD genotype Pnot IBD genotype s D x, y D xys 2 D Additive x Additive Genetic Covariance E ik ik E IBD alleles selected at 1, IBD alleles selected at 2 PIBD at 1, IBD at 2 x y 2 not IBD at 1, not IBD at 2 Pnot IBD at 1, not IBD at 2 2 2xy E 2 2 s AA x, y 2 xy s AA 2 In General... Any covariance due to higher-order epistatic effects is the product of: probability of identity for each additive effect probability of identity for each dominance effect corresponding variance component. 2 s AD x, y 2 xy D xys AD additive x dominance: 2 2 s x , y D s dominance x dominance: DD xy DD Overall Covariance s G x, y 2 xy n Dmxys A2 D n m 2 2 xys A2 D xys D2 2 xy s AA 2 2 2 2 xy D xys AD D2xys DD 2 xy s 2AAA 3 Coefficients Relationship Parent-offspring Grandparent-grandchild A ½ ¼ D Great grandparent-great grandchild Half sibs Full sibs (DZ) 1/8 1/64 ¼ ½ 1/16 ¼ ¼ 1/8 1/16 Uncle – nephew First cousins Monozygotic twins (MZ) ¼ 1/8 1 1/16 1/64 1 1 1 AA AD ¼ 1/16 1 DD Heritability Though many components of variance cannot be estimated, progress can be made in estimating additive genetic variance** dominance genetic variance environmental variance due to common families 2 s Narrow-sense heritability is the ratio h 2 A2 sz Estimating Heritability One can use sets of relatives to estimate h2. If additive genetic variance is the dominant source of phenotypic covariation, then h 2 because Covz x , z y 2 xy Var z Covz x , z y 2xys A2 Parent-Offspring Regression Heritabilities are often estimated by regressing offspring phenotypes on parental phenotypes. Parent-offspring relationships are often easiest to identify. Simple computation: least-squares Dominance and linkage do not influence covariance between parents and offspring. Unbiased by selection on the parents. The Role of Mama Often only the mother can be identified. Or the trait can only be observed on mothers (e.g. birth weight). Maternal effects can confound the analysis. We assume no maternal effects in the following analysis. Also, assume no significant genotype by environment interaction nor covariance. Balanced Design Assume single offspring and single parent observed in each family. zoi op z pi ei offspring phenotype for ith family parent phenotype for ith family Regression Coefficient Assumes no environmental causes of resemblance op Covzo , z p Var z p 1 2 1 2 1 2 s zo , z p 2 s A 4 s AA 8 s AAA E op 2 2 s zp sz Estimate of Heritability Assuming no additive x additive interactions: h 2bop 2 Midparent Values When both parents are known, a more precise estimate is available. Let zmi be the phenotype of the mother in the ith family. For father, zpi. zmi z pi ei zoi op 2 Estimating Heritability zm z p Cov zo , 2 bop zm z p Var in both sexes 2 in both generations 1 Cov zo , z m Covzo , z p Assume resemblance in 2 1 Var z Var z relatives is independent 4 of sex. 2Covzo , z p Var z 2bop Assume phenotypic variance is same