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MathMatters 3 Chapter 6 Lesson 6-3 Example 1 Write an equation of the line with slope of -3 and containing the point P(-3, 4). Solution y - y1 y-4 y-4 y-4 y = m(x - x1) = -3(x - (-3)) = -3(x + 3) = -3x - 9 = -3x - 5 point-slope form Substitute -3 for m, -3 for x1, and 4 for y1. Solve for y. slope-intercept form. Example 2 Write an equation of the line that contains the points A(2, -3) and B(4, 3). Solution Given: x1 = 2, y1 = -3, x2 = 4, y2 = 3 y2 - y1 3 - (-3) 6 Find the slope of the line: m = x - x = 4 - 2 = 2 = 3 2 1 Find the equation using the point-slope form. y - y1 y - (-3) y+3 y = m(x - x1) = 3(x - 2) = 3x - 6 = 3x - 9 Solve for y. slope-intercept form An equation of the line is y = 3x - 9. MathMatters 3 Chapter 6 Example 3 PRODUCT DESIGN A technician is using a coordinate grid to design a schematic for a circuit board. A connection aligns with the line shown at the right. Write an equation of the line. Solution y-intercepts: slope: The line intersects the y-axis at the point (0, 2). The y-intercept is 2. Use two points on the line whose coordinates are easily determined. Use (x1, y1) = (0, 2) and (x2, y2) = (3, -4). -4 - 2 -6 m = 3 - 0 = 3 = -2 An equation of the line: y = mx + b y = -2x + 2 slope-intercept form Example 4 2 Write an equation of a line parallel to y = x - 2 containing the point R(-2, 1). 3 Solution 2 y = 3x - 2 2 m=3 slope of line 2 Because parallel lines have equal slopes, m = 3. y - y1 = m(x - x1) 2 y - 1 = 3(x - (-2)) 2 4 y - 1 = 3x + 3 2 7 y = 3x + 3 point-slope form x1 = -2, y1 = 1 2 7 An equation of the line is y = 3x + 3.