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Session 2 Using Iteration to Solve Quadratic Equations 2.1 Roots of a Quadratic Polynomial Consider a quadratic polynomial p(x) = ax 2 + bx + c, a ¹ 0 . We say a number r is a zero or root of p( x) ax 2 bx c if p(r ) ar 2 br c 0 Note that testing if a number is a root is easy because we can plug it into the equation and see that it equals zero. The reverse process is not easy, that is finding a root, or more precisely approximating a root, e.g approximation of the square-root of two. By solving a quadratic equation iteratively we mean having a process that can compute a root as precisely as we wish. In order to approximate the roots of a quadratic polynomial via iterations it is necessary to find fixed points. 2.2 Newton’s Method for Solving Quadratic Equations In the 1700’s Sir Isaac Newton devised a way to find solutions to equations of the form f ( x) 0 . Newton’s Method uses iteration to find solutions to equations such as quadratic equations and more general polynomial equations. Newton’s Method for solving equations of the form f (x) = 0 computes orbits of the function N(x) = x - f (x) f '(x) If f(x) =ax2 + bx + c, the derivative of f (x ) is defined as f ' ( x) 2ax b . Thus, the Newton Function for f(x) is N(x) N(x) = x - ax 2 + bx + c 2ax 2 + bx - ax 2 - bx - c ax 2 - c = = 2ax + b 2ax + b 2ax + b Here is how Newton’s Method works. f’(x) is the slope of the tangent line at ( x, f(x) ). If the initial quess or seed equals x0 then f’(x0) gives the slope of the tangent line at (x0 , f(x0) ). The Newton function for f(x), N(x), is equal to f (x) N(x) = x f '(x) Iterating N(x) yields the solutions to f(x) = 0. Here’s why 1. Pick a seed x0 and calculate f(x0 ). 2. The tangent line has equation y - f(x0 ) = f’(x0 )( x - x0 ) 3. The x-intercept of the tangent line, x1 , is equal to x1 = x0 - f (x0 ) f '(x0 ) 4. Repeat to find x2 5. Use N(xn) = xn+1 until you get the desired accuracy Figure 2.5.1 Newton’s Method Diagram In order to solve x 2 6 x 8 0 , we can form the Newton Function using a 1, b 6, c 8 . In this case , N(x) = x - x 2 + 6x + 8 x 2 - 8 = 2x + 6 2x + 6 The first column in Table 2.1 shows the orbit of 3. Notice that the orbit very quickly converges to -2. Also, included in table 1 are the orbits for 2, -5 and -10. Notice that some orbits tend to one of the solutions and some to the other solution. 3 2 -5 -10 0.083333333 -0.4 -4.25 -6.571428571 -1.296171171 -1.507692308 -4.025 -4.925714286 -1.854628877 -1.918794607 -4.000304878 -4.22250106 -1.990774709 -1.99695048 -4.000000046 -4.02024813 -1.999957836 -1.999995364 -4 -4.000200925 -1.999999999 -2 -4 -4.00000002 -2 -2 -4 -4 -2 -2 -4 -4 2 Table 2.1 Iterative solutions to x 6 x 8 0 Remark. If we take the polynomial f (x) = x 2 - 2 , then Newton’s method gives a formula for approximation of 2 and it gives: N ( x) x2 2 1 x2 2 1 2 ( ) ( x ). 2x 2 x x 2 x Surprisingly, this coincides with the Babylonian formula! Exercises 2.2.1 1. In the above example, what is the basin of attraction for the solution x = -2, x = -4 ? 2. Using Newton’s Method and a spreadsheet to find the solutions and the corresponding basins of attraction for the following quadratic equations. You can use the spreadsheet Newton Quadratic Analysis to find the solutions and and the corresponding Basins of Attraction. a. 3x2 +10x + 6 = 0 b. 2x2 – 6x +1 = 0 c. x 2 5 x 6 0 d. x 2 2 x 6 0 Class Activity: Create a color Basin of Attraction Color Plot for the solutions of x2 – 2x - 8 = 0 2.3 Solving Quadratic Equations and Complex Numbers Our goal here is to solve quadratic equations via iterative methods and then enjoy them through visualization with Polynomiography software. However, first we need to develop some understanding of complex numbers and why we need to solve equations iteratively. First we will consider the solutions of a quadratic equation through the quadratic formula. In middle and high schools we learn how to solve a linear equation of the form ax b 0, where a is nonzero. The solution is x b a In an algebra course we learn several different methods for solving quadratic equations ax 2 bx c 0 Where a is nonzero. The numbers a, b, c are real numbers, called coefficients. Linear and quadratic equations are examples of polynomial equations. We can solve linear equations trivially and some quadratic equations can be solved by factoring. For example, you could solve x 2 6 x 8 0 by noticing that the sum of the roots is 6 and their product is 8 so that x 2 6 x 8 ( x 2)( x 4) and then solving ( x 2)( x 4) 0 which has solutions x 2 and x 4 . You can also solve quadratics by using the quadratic formula which states that the solutions to the quadratic equation ax 2 bx c 0 are x b b 2 4ac 2a or x b b 2 4ac 2a Solving x 2 6 x 8 0 by the quadratic formula you get x 6 36 32 6 4 6 2 2 2 2 2 and 6 36 32 6 4 6 2 4 2 2 2 The discriminant of a quadratic polynomial is x b 2 4ac This can say a lot about the solution of a quadratic equation. If 0 there are two roots. If 0 there is only one solution and is said to be a repeated root or a double root. x b 2a If 0 there are no solutions. To be exact, there are no real solutions. It turns out that there are two complex solutions. Later on, SESSION 3, we will consider this case again after we have formally defined complex numbers. The quadratic formula gives exact answers in terms of a, b, c , if b 2 4ac is a perfect square. If for instance the coefficients are integer but the discriminant is not a perfect square, you have to use a calculator or a set of tables to find approximate values for the square root of b 2 4ac . Actually what the calculator uses is an iterative method which goes back to the Babylonians. 2.4 Complex Numbers We can think of complex numbers as a mechanism to turn a location (a, b) in the Euclidean plane into a number. This is done by identifying the point with the complex number a ib where i 1 so that i 1 . With this rule we can add two complex numbers, subtract them, multiply and divide them. Examples follow. 2 Example 2.4.1 Consider two complex numbers 1 3i and 2 i . When multiplying or dividing we have to keep in mind that i 2 1 . Four elementary operations can be defined. Examples: (1 3i ) (2 i ) (1 2) (3 1)i 3 2i (1 3i ) (2 i ) (1 2) (3 1)i 1 4i (1 3i) (2 i) 2 i 6i 3i 2 2 5i 3 5 5i Next consider division of the two numbers. 1 + 3i æ 1 + 3i ö æ 2 + i ö =ç ÷ç ÷ 2 - i è 2 - i ø è 2 + iø (1 + 3i ) ( 2 + i ) = (2 - i) (2 + i) -1 + 7i 5 -1 7 = + i 5 5 = Exercises 2.4.1 1. Let u = 2-3i, v=-3+4i and w= 5-2i. Calculate the following a. u +v b. uv c. 2u+5w u w u v e. + v w 3. The conjugate of a + bi is equal to a-bi. Calculate the following a. (1+2i)(1-2i) and (1+2i)+(1-2i) b. (3-4i)(3+4i) and (3-4i)+(3+4i) c. i) What happens when you multiply a complex number and it’s conjugate? ii) What happens when you add a complex number and it’s conjugate? d. 4. Find two numbers a and b such that a. a + b = -6 and a*b = 25 b. a + b =-2 and a*b = 26 5. Food for thought: Given any two real numbers n and m can you always find real numbers a and b such that a + b = m and ab = n? 2.5 Plotting Complex Numbers Complex numbers, a + bi, can be plotted in an Argand diagram. The Argand diagram can also be referred to as the complex plane. In the complex plane the traditional x-axis represents the real axis and the traditional y-axis represents the imaginary axis. See the figure below When you plot the complex number 4+2i in the complex plane as shown in Figure 2.5.1 you go over 4 on the Real axis and up 2 on the Imaginary axis. Figure 2.5.1 Plot of 4 + 2i Historical Note: While Argand (1806) is generally credited with the discovery, the Argand diagram (also known as the Argand plane) was actually described by C. Wessel prior to Argand. Historically, the geometric representation of a complex number as a point in the plane was important because it made the whole idea of a complex number more acceptable. In particular, this visualization helped "imaginary" and "complex" numbers become accepted in mainstream mathematics as a natural extension to negative numbers along the real line. http://mathworld.wolfram.com/ArgandDiagram.html Exercises 2.5.1 Graph the following complex numbers on the set of axes below. 1. 3 - 2i 2. -3 +5i 3. -1-i 4. 2 5. -3i