* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Chapter 5 I. Multiple Alleles
Mitochondrial DNA wikipedia , lookup
Population genetics wikipedia , lookup
Gene nomenclature wikipedia , lookup
Public health genomics wikipedia , lookup
Therapeutic gene modulation wikipedia , lookup
Epigenetics of diabetes Type 2 wikipedia , lookup
Oncogenomics wikipedia , lookup
Pharmacogenomics wikipedia , lookup
Epigenetics of neurodegenerative diseases wikipedia , lookup
Gene desert wikipedia , lookup
Point mutation wikipedia , lookup
Ridge (biology) wikipedia , lookup
Minimal genome wikipedia , lookup
Site-specific recombinase technology wikipedia , lookup
History of genetic engineering wikipedia , lookup
Biology and consumer behaviour wikipedia , lookup
Transgenerational epigenetic inheritance wikipedia , lookup
Epigenetics of human development wikipedia , lookup
Gene expression programming wikipedia , lookup
Artificial gene synthesis wikipedia , lookup
Genome evolution wikipedia , lookup
Nutriepigenomics wikipedia , lookup
Genome (book) wikipedia , lookup
Gene expression profiling wikipedia , lookup
Designer baby wikipedia , lookup
Genomic imprinting wikipedia , lookup
Dominance (genetics) wikipedia , lookup
Chapter 5 Extensions and Modifications of Basic Principles I. Multiple Alleles • • • The ABO blood group has multiple alleles codominance and complete dominance. In codominance, both alleles are expressed simultaneously. In the ABO blood system, there are 3 alleles: IA IB i IA is dominant over i IB is dominant over i IA and IB are co-dominant Universal donor (type O) and universal recipient (type AB) Summary points 1. Dominance is a function of interaction between alleles. 2. Epistatsis is a function of interaction between genes. What pattern of inheritance is demonstrated in the following cross? 1 II. Sex limited and sex influenced inheritance What pattern of inheritance is demonstrated in the following cross? What pattern of inheritance is demonstrated in the cross above? What pattern of inheritance is demonstrated in the following cross? 2 What pattern of inheritance is demonstrated in the cross above? III. Dominance / Incomplete dominance IV. Gene interaction A. New genotypes can show up in the F1 and F2 generation. Eg. Comb type in chickens Walnut R-P What are the phenotypes of these parents, and what F1 and F2 offspring would you expect from the following crosses? RRPP x rrpp walnut x single F1: all walnut Note that your first hypothesis here would probably be a single gene where walnut is dominant. F2: __ walnut: __ rose: __ pea: __ single Rose R-pp Pea rrP- Single rrpp What are the phenotypes of these parents, and what F1 and F2 offspring would you expect from the following crosses? RRpp x rrPP rose x pea F1: all walnut Note that a novel phenotype appears in this generation. F2: __ walnut: __ rose: __ pea: __ single 3 B. Epistasis occurs when one gene masks the effect of a second gene. Gene interaction and/or epistasis may produce offspring ratios that are variations of a 9:3:3:1. Dominant epistasis __ white: __ yellow: __ green W--- white: wwY- yellow: wwyy green 9 3 3 1 A-B- A-bb aaB- aabb 9:3:3:1 12:3:1 10:3:3 9:6:1 9:3:4 15:1 13:3 12:4 10:6 9:7 Duplicate recessive epistasis __ pigmented: __ white A-B- pigmented: A-bb or aaB- or aabb white 4 Two pathways that would yield a 9:7 (color : white) ratio. … with two pathways you can also get a 9:3:3:1 ratio, but… A- gene A Colorless f gene B Colorless f Colorless Colorless (C?) gene A Colorless f Colorless f gene B Colorless f Color f f RED f PURPLE BLUE aaB3 blue aabb 1 white Colorless aa RED Colorless f BColorless f A-BA- bb 9 3 purple red aa Colorless f B- Color PURPLE BLUE RED f bb Colorless If the functional a gene is recessive? A-BA- bb aaB- aabb 9 3 3 1 blue white purple red f f PURPLE BLUE If both functional genes are recessive? A-BA- bb aaB- aabb 9 3 3 1 white blue red purple How do we get so many different ratios? AColorless f BPINK f RED Recessive epistasis A-BA- bb aaB- aabb 9 3 3 1 red pink white white 9 3 4 We have already seen that if the intermediate product is white (colorless) you get a ___:___ ratio. 5 … and with a slight variation? aa Colorless A-B9 white B- f A- bb 3 white 12 … but if these are duplicate pathways… PINK aaB3 red 3 f ARED aabb 1 pink 1 What ratio do you get if the intermediate product is white? Colorless f Colorless f Summer squash •9 disk: 6 sphere: 1 elongate Fowl color •13 white: 3 colored Corn kernel color •9 purple: 7 white Complementation test Determines whether two independently isolated mutations are at the same loci or different loci. f B- A-B9 red A- bb 3 red RED aaB3 red aabb 1 white ____red :____ white Summary points Examples of Epistatic Ratios Sheperd’s purse •15 triangular : 1 oval RED 1. Genes are discrete units that control the phenotype of organisms. 2. Inheritance follows the rules of segregation and independent assortment 3. Dominance is a function of interaction between alleles. 4. Genes control the production of enzymes and thus the function of biochemical pathways. 5. Epistatsis is a function of interaction between genes. Flower color Wile type is red, mutant is white. Consider two independently isolated white mutants, where wild type is dominant: w c w c 6 Cross them. Two possible outcomes Two possible outcomes Allelic: no complementation Allelic: no complementation Different genes: complementation w w c W c c Cw Summary points In a cross between two mutant lines (with the same phenotype) , complementation results in a wild type phenotype and indicates that two mutations are in different genes. This is called a complementation test. V. Lethal alleles Lethal alleles result in missing classes in a genetic cross Eg. 2:1 phenotypic ratio in a monohybrid cross VI. Non-Mendelian inheritance A. Maternal effects: influence of mother's genotype on phenotype of offspring B. Cytoplasmic inheritance: extra-nuclear genes that are found in chloroplasts and mitochondria 7 Snail shell coiling dextral (right hand) sinistral (left hand) Start with two true-breeding lines Dextral female x sinistral male: all dextral F1 Sinstral female x dextral male: all sinistral F1 Give a hypothesis about how this trait is controlled. A. Maternal effects Dextral female X sinistral male: dextral F1 selfing produces all dextral all Sinstral female X dextral male: all sinistral F1 selfing produces all dextral Genotype of mother determines cleavage pattern in egg, and that determines direction of coiling She is sinistral because her mother was ss. They are dextral because their mother was s+s. What will their offspring be? Summary points For traits determined by genetic maternal effects, the genotype of the mother (rather than of the gamete she contributes) determines the phenotype of the offspring through mRNA in the egg. 8 B. Cytoplasmic inheritance organelles or particles Mitochondria and chloroplasts have own genome Rules of extranuclear inheritance 1. 2. 3. 1. Mitochondrial genome 4. Uniparental inheritance leads to differences between reciprocal crosses. Genes cannot be mapped to nuclear chromosomes. Ratios associated with Mendelian traits cannot be found. Extranuclear inheritance is persists despite nuclear substitution. Homoplasmic: all mitochondria identical or heteroplasmic: mitochondrial DNAs have more than one sequence Inheritance is uniparental; usually maternal. Summary points For traits determined by cytoplasmic inheritance, genes are encoded in the cytoplasm (usually in the mitochondria and chloroplast). These organelles usually show uniparental inheritance. V. Imprinting: Phenotype of offspring depends upon maternal or paternal source of altered allele i.e. which parent contributed the allele Mutants act like a dominant, but only through one parent. 9 Prader-Willi/Angelman syndrome Results from deletion of 15q11-15q13. But sometimes you got one phenotype and sometimes another…. AS PWS Angelman syndrome: jerky, repetitive, lurching body movements; seizures; incoherent speech; loud bursts of laughter; large mouths; red cheeks Prader-Willi syndrome: mild to moderate mental retardation; lack muscle tone; insatiably hungry so become obese; tiny hands and gonads. Prader-Willi/Angelman syndrome Results from deletion of 15q11-15q13. Two different imprinted genes in the same region. Maternally inheritted deletion causes Angelman’s Paternal deletion causes Prader-Willi Summary points For traits determined by genomic imprinting, only the allele inherited from the parent of one sex is expressed. VI. Anticipation: The severity increases or the age of onset gets early when you look across generations. Eg: Grandfather age of onset: 50 Mother age of onset: 35 Child age of onset: 5 Ascertainment bias? NO 10 Summary points For traits that show anticipation, mutant alleles are unstable and may change over even one generation. They are caused by trinucleotide repeats; more repeats results in earlier and/or more severe expression of the mutant phenotype. VII. Environmental effects on gene expression Mutations due to trinucleotide repeat expansion: (CAG)n Huntington’s Several types of ataxia Fragile X (non-coding) Grandfather age of onset: 50 (CAG)25 Mother age of onset: 35 (CAG)50 Child age of onset: 5 (CAG)120 Summary points Expression of many genes is modified by the environment. This is known as a gene x environment interaction. This is so common as to be virtually universal. 11