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Data provided: Formula Sheet MAS140 SCHOOL OF MATHEMATICS AND STATISTICS MAS140 Spring Semester 2012–2013 Mathematics (Chemical) 3 hours Attempt ALL questions. Each question in Section A carries 3 marks, each question in Section B carries 8 marks. Section A (8 − ax)1/3 − 2 A1 Use the binomial theorem to find the value of a for which lim = 1. x→0 x A2 If f (x) = 3x , x ≥ 0, what is the range of f (x)? Find f −1 (y). x+2 A3 Find the first three nonzero terms in the Maclaurin expansion of f (x) = e−2x cos 3x. x cos 3x . x→π/2 2x − π A4 Evaluate lim A5 Find all the complex numbers z for which Re(z) + Im(z) = 0 and |z − 1 + i| = √ 2. A6 If a = (3, 1, −1) and b = (1, −2, 1), show that a is perpendicular to b and find a × b. MAS140 1 Turn Over MAS140 A7 Use integration by parts to find the indefinite integral Z xn ln(x)dx where n 6= −1. A8 Compute the definite integral Z 1 sin2 −1 πx dx. 2 A9 Find the determinant of A−1 B, where A and B are given by " A= 1 −1 2 −4 # " , B= 4 1 1 1 # . A10 Consider the homogeneous linear system of equations 3x + y = 0, ax − 4y = 0, which has the trivial solution x = y = 0. Find the value of a for which the system has additional solutions. A11 Find the general solution of the following differential equation: d2 y dy + 5 + 6y = 0. 2 dx dx A12 Show that the general solution of the differential equation dy y = , dx 1 − x2 s is given by y = A MAS140 1+x , where A is a constant. 1−x 2 Continued MAS140 Section B B1 Find the quadratic Q(x) for which the polynomial P (x) = x3 − x2 − x − 15 can be written in the form P (x) = (x − 3) Q(x). Find the roots of Q(x) and plot them on an Argand diagram. Find the constants A and B such that Q(x) = (x − A)2 + B. Sketch the curve y = Q(x). B2 Determine the modulus and principal argument of the complex numbers z1 = −3 + 4i and z2 = −4 − 3i. By expressing z1 and z2 in exponential form, or otherwise, show that 1 z13 = z¯1 , 4 z2 25 where z¯1 is the complex conjugate of z1 . B3 Find the values of x at which the function f (x) = x3 + 2x2 − 4x + 1 has stationary points. Determine the nature of each of the stationary points and sketch the curve y = f (x). B4 A function f (x, y) of two variables is given by f (x, y) = 2x5 − 1 cos 5y. x5 Calculate the first-order partial derivatives fx and fy . Calculate the second-order partial derivatives fxx and fyy and demonstrate that x2 fxx + xfx + fyy = 0. B5 Let dx + 2x + a where a is a constant. Find the indefinite integral I in the following cases, (i) a = 1, I= Z x2 (ii) a = 0, (iii) a = 2. MAS140 3 Turn Over MAS140 B6 Let 1 0 2 A = 0 3 1 . 1 −4 1 (a) Find |A|, the determinant of A. (b) Find A−1 , the inverse of A. (c) Use A−1 to find x, y and z which are solutions to the linear equations x + 2z = 5, 3y + z = 11, x − 4y + z = −9. B7 Let " A= 1 2 2 1 # . (a) Find the eigenvalues and normalized eigenvectors of A. (b) Show that the eigenvectors are orthogonal. (c) Four points P QRS on a unit square are described by the column vectors " 0 0 # " , 1 0 # " , 0 1 # " , 1 1 # , respectively. The transformed points P 0 Q0 R0 S 0 are obtained by multiplying the column vectors by matrix A. Draw a sketch of the xy plane showing the original points P QRS, the transformed points P 0 Q0 R0 S 0 , and the direction of the eigenvectors of A. B8 Consider the following differential equation: y 00 + 2y 0 + 2y = f (x) (a) Find the general solution in the case f (x) = 0. (b) Find a particular solution for f (x) = cos x. (c) Find the solution for f (x) = cos x with initial conditions y(0) = y 0 (0) = 0. End of Question Paper MAS140 4 MAS140-151-152 Formula Sheet These results may be quoted without proof unless proofs are asked for in the questions. Trigonometry Hyperbolic Functions sin2 x + cos2 x = 1 sinh x = 21 (ex − e−x ) 1 + tan2 x = sec2 x cosh x = 21 (ex + e−x ) sinh x cosh x cosh x coth x = sinh x 1 sechx = cosh x 1 + cot2 x = cosec2 x tanh x = 2 sin2 x = 1 − cos 2x 2 cos2 x = 1 + cos 2x 2 sin x cos x = sin 2x cos(x ± y) = cos x cos y ∓ sin x sin y cosh2 x − sinh2 x = 1 sin(x ± y) = sin x cos y ± cos x sin y 2 cosh2 x = 1 + cosh 2x tan(x ± y) = tan x ± tan y 1 ∓ tan x tan y 2 sinh2 x = cosh 2x − 1 2 sinh x cosh x = sinh 2x a cos x + b sin x = R cos (x − α) √ where R = a2 + b2 , cos α = a R and sin α = sech2 x = 1 − tanh2 x √ sinh−1 x = ln(x + x2 + 1) , all x √ cosh−1 x = ln(x + x2 − 1) , x ≥ 1 ( ) 1 1+x −1 tanh x = ln , |x| < 1 2 1−x b R 2 cos x cos y = cos(x + y) + cos(x − y) 2 sin x sin y = cos(x − y) − cos(x + y) 2 sin x cos y = sin(x + y) + sin(x − y) 1 − tan2 (x/2) cos x = 1 + tan2 (x/2) sin x = 2 tan(x/2) 1 + tan2 (x/2) tan x = 2 tan(x/2) 1 − tan2 (x/2) 1 Series Sum of an arithmetic series: first term + last term × (number of terms) 2 1 − xn Sum of a geometric series: 1 + x + x2 + . . . + xn−1 = 1 − x( ) n(n − 1) n r 2 Binomial theorem: (1 + x)n = 1 + nx + x + ... + x + ... 2! r ( ) n(n − 1)(n − 2) . . . (n − r + 1) n = where r r! If n is a positive integer then the series terminates and the result is true for all x, otherwise, the series is infinite and only converges for |x| < 1. x3 x5 x7 sin x = x − + − + ... 3! 5! 7! 2 4 6 x x x cos x = 1 − + − + ... 2! 4! 6! 3 5 7 x x x valid for all x sinh x = x + + + + ... 3! 5! 7! 2 4 6 x x x cosh x = 1 + + + + ... 2! 4! 6! 2 3 x x x exp x = e = 1 + x + + + ... 2! 3! x2 x3 x4 ln(1 + x) = x − + − + . . . (−1 < x ≤ 1) 2 3 4 2 Differentiation Function Derivative Function Derivative sin x cos x cos x − sin x tan x sec2 x cot x −cosec2 x sin−1 x √ 1 , |x| < 1 1 − x2 1 1 + x2 cos−1 x −√ cosh x cosh x sinh x coth x − tan−1 x sinh x tanh x sinh−1 x tanh−1 x coth−1 x cot−1 x 1 cosh2 x 1 √ 2 x +1 1 , |x| < 1 1 − x2 1 , |x| > 1 1 − x2 cosh−1 x 3 1 , |x| < 1 1 − x2 1 − 1 + x2 1 sinh2 x 1 √ , |x| > 1 2 x −1 Integration In the following table the constants of integration have been omitted. ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ xn+1 x dx = n+1 n x e dx = e ∫ (n ̸= −1) ∫ x ∫ sin x dx = − cos x ∫ sec2 x dx = tan x ∫ sinh x dx = cosh x ∫ sech2 x dx = tanh x x dx √ = sin−1 a a 2 − x2 ∫ (|x| < a) dx = ln |x| x ax a dx = ln a x (a > 0, a ̸= 1) cos x dx = sin x cosec2 x dx = − cot x cosh x dx = sinh x cosech2 x dx = − coth x dx 1 −1 x = tan a 2 + x2 a a ∫ dx dx x −1 x √ √ = sinh = cosh−1 a a x 2 − a2 x2 + a 2 a + x dx 1 (= tanh−1 x if |x| < a) = ln 2 2 a −x 2a a − x a (x) cosecx dx = ln tan or ln (cosecx − cot x) 2 (x π ) sec x dx = ln tan or ln (sec x + tan x) + 2 4 (x) cosechx dx = ln tanh 2 4 (|x| > a) Integration by parts ∫ ∫ ′ f (x) g (x) dx = f (x) g(x) − f ′ (x) g(x) dx Newton-Leibnitz formula ∫ b b ′ If F (x) = f (x), then f (x) dx = F (b) − F (a) = F (x) a a Variable substitution in definite integral If x = φ(t) is a monotonic function in the interval [α, β] and a = φ(α), b = φ(β), then ∫ b ∫ β f (x) dx = f (φ(t)) φ′ (t) dt a α Variable substitution for a rational function of sin x and cos x Let t = tan (x) 2 then sin x = 2t , 1+t2 cos x = 1−t2 1+t2 and dx dt = 2 . 1+t2 Area of planar figure The area of a planar figure bounded by the graph of a continuous positive function f (x), the x-axis, and the ordinates x = a and x = b is ∫ b S= f (x) dx a Volume of solid of revolution The volume of a solid of revolution, obtained by rotation of a planar figure bounded by the graph of a continuous positive function f (x), the x-axis, and the ordinates x = a and x = b through a complete revolution around the x-axis, is ∫ b V =π f 2 (x) dx a 5 Powered by TCPDF (www.tcpdf.org)