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Math 251: Beginning Algebra
Section 4.2 Notes
Solving Systems of Linear Equations by Substitution
Solving a system by graphing is very difficult, especially without graph paper! Thus, we prefer
algebraic methods for solving systems of linear equations. There are two such algebraic methods:
1. Substitution
2. Elimination
We look at the method of substitution in this section.
Example 1: Solve the system by the substitution method.
2 x + 7 y = −12
x = −2 y
Step 1
Solve one equation for either variable.
Step 2
Substitute for that variable in the other equation.
Step 3
Solve the equation from Step 2.
Step 4
Substitute the result from Step 3 into the equation from Step 1 to find the value
of the other variable.
Step 5
Check the solution in both of the original equations.
Math 251: Beginning Algebra
Section 4.2 Notes
Solving a Linear System of Substitution
Step 1
Step 2
Step 3
Step 4
Step 5
Solve one equation for either variable.
Substitute for that variable in the other equation.
Solve the equation from Step 2.
Substitute the result from Step 3 into the equation from Step 1 to find the
value of the other variable.
Check the solution in both of the original equations.
Example 2: Solve the system by the substitution method.
x + 1 = −4 y
2 x − 5 y = 11
Example 3: Solve the system by the substitution method.
y = 8x + 4
16 x − 2 y = 8
Math 251: Beginning Algebra
Section 4.2 Notes
Example 4: Solve the system by the substitution method.
x + 3 y = −7
4 x + 12 y = −28
Example 5: Solve the system by the substitution method.
1
1
1
x+ y=−
2
3
3
1
x + 2 y = −2
2
(Clear fractions first!!)
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