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Solving Systems Using Substitution Substitution • Sometimes you don’t have a graphing calculator to use. • Substitution allows you to solve a onevariable equation. • One of the equations should be in either y = or x = form – if not isolate one variable and solve. • Replace that variable in the other equation and solve. Example 1 𝑥 = 2𝑦 − 13 2𝑥 + 𝑦 = −1 • Solve 2x + y = -1 and x = 2y – 13 • Replace the x in the first equation with what x is equal to in the second equation • 2(2y – 13) + y = -1 • Simplify: 4y – 26 + y = -1 5y – 26 = -1 • Solve: y = 5 • Now, replace y in either equation with 5 to find x x = 2(5) – 13 • x = -3 so the solution is (-3, 5) • Check in the second equation 2(-3) + 5 = -1 • -6 + 5 = -1 is true so the solution is (-3, 5) Example 2 • • • • • • 4 𝑦 = 𝑥+7 3 4𝑥 − 3𝑦 = 15 Solve: y = 4/3x – 7 and 4x – 3y = 15 Replace the y in the second equation with “3/4x – 7” 4x – 3(4/3x – 7) = 15 Simplify: 4x – 4x + 21 = 15 0x +21 = 15 Solve: 21 does not equal 15 No Solution Example 3 • • • • • • • • • • • 1 𝑦 = 𝑥+4 2 𝑥 + 2𝑦 = 8 Solve: y = 1/2x + 4 and x + 2y = 8 Replace the y in the second equation with “1/2x + 4” x + 2(1/2x + 4) = 8 Distribute x + x + 8 = 8 Simplify 2x + 8 = 8 2x = 0 x=0 Replace the x in the first equation with 0 y = 1/2(0) + 4 y=4 (0, 4) Check your work. Example 4 • • • • • • • 𝑦 = 2𝑥 + 3 𝑥 − 2𝑦 = 3 Solve: y = 2x + 3 and x – 2y = 3 Replace y with 2x + 3 in the second equation. x – 2(2x + 3) = 3 Distribute the –2 x – 4x – 6 = 3 Simplify -3x – 6 = 3 Solve -3x = 9 x = -3 Replace x with –3 in the first equation y = 2(-3) + 3 y = -3 • So, the solution is (-3, -3) (Check it in the 2nd equation too.) Try these… • x + y = 38 x = 2y – 25 • y = x + 2.8 y + 4.6 = 2x • y=x+4 3x – 2y = -7 • x + y = 90 y = 4x - 10 • (17, 21) • (7.4, 10.2) • (1, 5) • (20, 70)