1 PHYSICS 231 Lecture 12: Keeping momentum
... A train is moving with a speed of 25 km/h to the east. An environment-unfriendly passenger throws a can out of the window. The velocity with which he throws the can relative to the moving train is 25 km/h toward the back of the train the (west) and 10 km/h away from the train toward the south. To an ...
... A train is moving with a speed of 25 km/h to the east. An environment-unfriendly passenger throws a can out of the window. The velocity with which he throws the can relative to the moving train is 25 km/h toward the back of the train the (west) and 10 km/h away from the train toward the south. To an ...
Physics I - Rose
... 13.23. Model: A circular plastic disk rotating on an axle through its center is a rigid body. Assume axis is perpendicular to the disk. Solve: To determine the torque () needed to take the plastic disk from i 0 rad/s to f 1800 rpm (1800)(2)/ 60 rad/s 60 rad/s in tf – ti 4.0 s, we nee ...
... 13.23. Model: A circular plastic disk rotating on an axle through its center is a rigid body. Assume axis is perpendicular to the disk. Solve: To determine the torque () needed to take the plastic disk from i 0 rad/s to f 1800 rpm (1800)(2)/ 60 rad/s 60 rad/s in tf – ti 4.0 s, we nee ...
Laws of Force
... Small masses have a small gravitational force The larger masses have a larger gravitational force If the distance between the two objects is in creased then the gravitational force is reduced ...
... Small masses have a small gravitational force The larger masses have a larger gravitational force If the distance between the two objects is in creased then the gravitational force is reduced ...
Newton`s Second Law.
... going on “under the hood” in Newton’s second law which we need to discuss. First of all, let us deal with a common mental mistake made by beginners. It is perhaps tempting to read Newton’s second law as a literal identification of force with mass times acceleration. This is not the way to think of i ...
... going on “under the hood” in Newton’s second law which we need to discuss. First of all, let us deal with a common mental mistake made by beginners. It is perhaps tempting to read Newton’s second law as a literal identification of force with mass times acceleration. This is not the way to think of i ...
Test 1 Sample
... 4. Joe exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant speed. The constant horizontal force applied to the box by Joe a. has the same magnitude as the weight of the box. b. is greater than the weight of the box. c. has the same m ...
... 4. Joe exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant speed. The constant horizontal force applied to the box by Joe a. has the same magnitude as the weight of the box. b. is greater than the weight of the box. c. has the same m ...
A Revolution In Science - Empirical
... • II. “Law of Equal Areas” The line connecting a planet to the Sun sweeps out equal areas in equal times, regardless of where the planet is in its orbit. • An imaginary line connecting the Sun to any planet sweeps out equal areas of the ellipse in equal intervals of time. – The speed of a planet cha ...
... • II. “Law of Equal Areas” The line connecting a planet to the Sun sweeps out equal areas in equal times, regardless of where the planet is in its orbit. • An imaginary line connecting the Sun to any planet sweeps out equal areas of the ellipse in equal intervals of time. – The speed of a planet cha ...
A solid disk with mass = 0
... c) If the skater decreases her rotational inertia to 25 kg.m2, what will be the skater’s new rotational speed? ...
... c) If the skater decreases her rotational inertia to 25 kg.m2, what will be the skater’s new rotational speed? ...
Slide 1
... Every object continues in its state of rest, or of uniform velocity in a straight line, as long as no net force acts on it. ...
... Every object continues in its state of rest, or of uniform velocity in a straight line, as long as no net force acts on it. ...
Chapter 8 Rotational Dynamics continued
... 1. Select the object to which the equations for equilibrium are to be applied. 2. Draw a free-body diagram that shows all of the external forces acting on the object. 3. Choose a convenient set of x, y axes and resolve all forces into components that lie along these axes. 4. Apply the equations t ...
... 1. Select the object to which the equations for equilibrium are to be applied. 2. Draw a free-body diagram that shows all of the external forces acting on the object. 3. Choose a convenient set of x, y axes and resolve all forces into components that lie along these axes. 4. Apply the equations t ...
Simple Harmonic Motion and Elastic Energy
... (I am going to walk you through this one and then you will need to try the next one before getting the answer off line…) 1. The given expression describes the vibration by telling the position at every instant of time as it continually changes. Think about a treetop swaying in the wind while you are ...
... (I am going to walk you through this one and then you will need to try the next one before getting the answer off line…) 1. The given expression describes the vibration by telling the position at every instant of time as it continually changes. Think about a treetop swaying in the wind while you are ...
Newton`s Laws webquest
... Sixth Stop: Find your weight on Other Planets…MASS VS. WEIGHT! http://www.exploratorium.edu/ronh/weight/ 1. Enter in your weight and click “calculate”. On which planet do you weigh the most? _________________ On which planet do you weight the least? _____________________ 2. How much do you weigh on ...
... Sixth Stop: Find your weight on Other Planets…MASS VS. WEIGHT! http://www.exploratorium.edu/ronh/weight/ 1. Enter in your weight and click “calculate”. On which planet do you weigh the most? _________________ On which planet do you weight the least? _____________________ 2. How much do you weigh on ...
Newton Second Law OK
... and directions as accurate as you can. Label each force. If there are multiple objects, draw a separate diagram for each one. 3. Resolve vectors into components. 4. Apply Newton’s second law to each component. 5. Solve. ...
... and directions as accurate as you can. Label each force. If there are multiple objects, draw a separate diagram for each one. 3. Resolve vectors into components. 4. Apply Newton’s second law to each component. 5. Solve. ...
equilibrium
... A person holds a 50.0-N sphere in his hand. The forearm is horizontal. The biceps muscle is attached 3.00 cm from the joint, and the sphere is 35.0 cm from the joint. Find the upward force exerted by the biceps on the forearm and the downward force exerted by the upper arm on the forearm and acting ...
... A person holds a 50.0-N sphere in his hand. The forearm is horizontal. The biceps muscle is attached 3.00 cm from the joint, and the sphere is 35.0 cm from the joint. Find the upward force exerted by the biceps on the forearm and the downward force exerted by the upper arm on the forearm and acting ...
