x - Savannah State University
... for which f (r) = 0, then r is called a (real) zero of f, or root of f. If r is a (real) zero of f, then a.) (r,0) is an x-intercept of the graph of f. b.) (x - r) is a factor of f. ...
... for which f (r) = 0, then r is called a (real) zero of f, or root of f. If r is a (real) zero of f, then a.) (r,0) is an x-intercept of the graph of f. b.) (x - r) is a factor of f. ...
No Slide Title
... By the Imaginary Root Theorem, the equation has either no imaginary roots, two imaginary roots (one conjugate pair), or four imaginary roots (two conjugate pairs). So the equation has either zero real roots, two real roots, or four real roots. By the Rational Root Theorem, the possible rational root ...
... By the Imaginary Root Theorem, the equation has either no imaginary roots, two imaginary roots (one conjugate pair), or four imaginary roots (two conjugate pairs). So the equation has either zero real roots, two real roots, or four real roots. By the Rational Root Theorem, the possible rational root ...
Document
... Solve the system by substitution. Interpret the solution. A. (18, 6); Emily spent $18 and Devin spent $6. B. (6, 18); Emily spent $6 and Devin spent $18. C. (15, 5); Emily spent $15 and Devin spent $5. D. (5, 15); Emily spent $5 and Devin spent $15. ...
... Solve the system by substitution. Interpret the solution. A. (18, 6); Emily spent $18 and Devin spent $6. B. (6, 18); Emily spent $6 and Devin spent $18. C. (15, 5); Emily spent $15 and Devin spent $5. D. (5, 15); Emily spent $5 and Devin spent $15. ...
Document
... equations, 1. Isolate a variable on one side of either equation. 2. Substitute the expression for the variable found in step 1 into the other equation. 3. Solve the equation in one variable found in step 2. 4. Substitute the solution found in step 3 into one of the original equations, and solve for ...
... equations, 1. Isolate a variable on one side of either equation. 2. Substitute the expression for the variable found in step 1 into the other equation. 3. Solve the equation in one variable found in step 2. 4. Substitute the solution found in step 3 into one of the original equations, and solve for ...
Complex exponentials: Euler`s formula
... Complex exponentials: Euler’s formula What happens when we try to solve an equation such as y 00 − 2y 0 + 5y = 0. The characteristic equation is r2 − 2r + 5 = 0, whose roots are complex: ...
... Complex exponentials: Euler’s formula What happens when we try to solve an equation such as y 00 − 2y 0 + 5y = 0. The characteristic equation is r2 − 2r + 5 = 0, whose roots are complex: ...
Expressions-Writing
... algebraic expression for a given situation, using up to three variables. OBJECTIVE: Students will evaluate expressions by applying algebraic order of operations and the commutative, associative, and distributive properties and justify each step in the process by following and performing the correct ...
... algebraic expression for a given situation, using up to three variables. OBJECTIVE: Students will evaluate expressions by applying algebraic order of operations and the commutative, associative, and distributive properties and justify each step in the process by following and performing the correct ...
Geometry Level 3 Curriculum
... Unit D - Polygons and Quadrilaterals Overview In this unit, students learn first about polygons and then focus on quadrilaterals. Properties of quadrilaterals are introduced through various discovery activities in order to build a quadrilateral tree and to be able to classify the special quadrilater ...
... Unit D - Polygons and Quadrilaterals Overview In this unit, students learn first about polygons and then focus on quadrilaterals. Properties of quadrilaterals are introduced through various discovery activities in order to build a quadrilateral tree and to be able to classify the special quadrilater ...
