
HW2SOL
... What is the worst case running time of sequential search? What about binary search? What conditions need to hold before we can run binary search? The worst case running time of sequential search is n. The worst case running time of binary search is log n Before we run a binary search the elements be ...
... What is the worst case running time of sequential search? What about binary search? What conditions need to hold before we can run binary search? The worst case running time of sequential search is n. The worst case running time of binary search is log n Before we run a binary search the elements be ...
Chapter 11 Special Products and Factors
... Usually, when we factor a positive integer, we write only the positive integral factors. Two factors of any number are 1 and the number itself. To find other integral factors, if they exist, we use division, as stated above. We let the number being factored be the dividend, and we divide this number ...
... Usually, when we factor a positive integer, we write only the positive integral factors. Two factors of any number are 1 and the number itself. To find other integral factors, if they exist, we use division, as stated above. We let the number being factored be the dividend, and we divide this number ...
An explicit example of a noncrossed product division algebra
... division algebra (3 + 3, −7+2 −7 )K over the biquadratic number field K = Q( 3, −7). In general, it is very difficult to explicitly compute outer automorphisms of division algebras or central simple algebras. But in very special cases the problem can be reduced to the solution of norm equations in f ...
... division algebra (3 + 3, −7+2 −7 )K over the biquadratic number field K = Q( 3, −7). In general, it is very difficult to explicitly compute outer automorphisms of division algebras or central simple algebras. But in very special cases the problem can be reduced to the solution of norm equations in f ...
Logs and significant figures
... When taking a log of a number, the mantissa should have the same number of digits as the number of significant digits in the original number. Examples: log (5.12 × 10-5) = log (5.12) + log (10-5) = 0.709 + (-5) = -4.291 log (5.12 × 10-6) = log (5.12) + log (10-6) = 0.709 + (-6) = -5.291 log (5 × 10- ...
... When taking a log of a number, the mantissa should have the same number of digits as the number of significant digits in the original number. Examples: log (5.12 × 10-5) = log (5.12) + log (10-5) = 0.709 + (-5) = -4.291 log (5.12 × 10-6) = log (5.12) + log (10-6) = 0.709 + (-6) = -5.291 log (5 × 10- ...